send help
#๐ helps
bronze rose
gusty jungle
<@617708949705064488>
@bronze rose read this embed please
heady warren
hey
heady warren
<@617708949705064488> read this embed please
its for me
bronze rose
i know thyem from the python discussion
heady warren
alright
golden moat
could you send your code?
bronze rose
#ValiderRejouer
def ValiderRejouer() -> bool:
reponse: bool
question:str
question = str(input("Voulez vous rejouer? (O ou N)\n"))
if question == ("o"):
reponse = True
elif question == ("n"):
reponse = False
else:
print(question)
question:str
question = str("")
print(question)
return reponse
lets go back to something imporant @bronze rose
and ill show you a few things
and ill show yoou more on how to make it into what you want
if that is ok
heady warren
type hints is a thing in python, and it has one purpose
name: str this is a type hint
bronze rose
okay
heady warren
and that point iis to tell the human what your intent is
i intent for the name name to be a string of type str
python does not use or care about this
it ignores it
type hints are for the human that reads your code
you can just remove it and it will not affect how python sees your code
because python just ignores it
you should use type hints, but know that python will not care about it at all
with me so far?
@bronze rose
bronze rose
sorry im back
bronze rose
<@617708949705064488>
yup i understand
heady warren
good!
lets not try to fix your code, but lets write it again how i would do it, then add the parts that you need for your school to be happy
bronze rose
i also want the function to work ๐ญ
heady warren
you want the user to input o or n, and if the user does that, you are alright?
bronze rose
idk how to write it so it would work
heady warren
idk how to write it so it would work
we will get there in smal;l steps
bronze rose
you want the user to input `o` or `n`, and if the user does that, you are alrigh...
yes
bronze rose
no clue how to treat those
heady warren
no clue how to treat those
im asking if that is valid or not
heady warren
im asking you the human,
not your computer program that does not work
i would argue that O and N are valid here
heady warren
what about oui and non ?
heady warren
so we have multiple things to look for, and that is something we can inspect later.. just have it in the back of the mind for now
let me write a simple while loop and we wiill use that as our starting point, and change iit over time
heady warren
valid_input = 'o', 'n', 'O', 'N'
while True:
user_input = input('write something')
if user_input in valid_input:
break
lets unpack this example
bronze rose
i thnk we need to use .uppercase or something
heady warren
explain it to me as you see it
heady warren
i thnk we need to use .uppercase or something
we will get there, dont rush it
i know you said not to use break, and that is something to fix later, we are just looking at this as simple as possible.
bronze rose
explain it to me as you see it
i didnt see in so i cant use it either
valid input is o n O n
while the string is true (which is that smt is in it)
userinput is (something that the user write)
if o n O N is in valid input (which it always is)
it ends
heady warren
alright, fantastic
lets unpack a few moore thing
valid input is o n O n yes good.. this is correct
while the string is true (which is that smt is in it) im not checking a string
while True just means run forever
with me on this?
heady warren
i dont want to make an infinite loop tho
i said we will fix it later, we have to start simple
bronze rose
okay sorry haha
heady warren
iif you start complex, your code will break
and you already know about that now..
๐
userinput is (something that the user write) yes correct and important
if o n O N is in valid input (which it always is) thats not what this if statement checks
can you see again?
heady warren
correct
it might be or it might not be
if it is, we are ok, and we should end the loop
if it is not, we continue the loop
agree?
bronze rose
yes
heady warren
notice i have not put in annotations yet. because python does not use them, i will wait until the end to do so
valid_input = 'o', 'n', 'O', 'N'
while True:
user_input = input('write something')
if user_input in valid_input:
break
are you allowed to use in ? like i used here?
bronze rose
nope
heady warren
yeah, thats what i asked aboout, schools have rules
heady warren
no worries
heady warren
if user_input == valid_input
you can only check equality for things that are equal
what data type is user_input ?
bronze rose
str
heady warren
yes, and what about valid_input?
bronze rose
str too?
heady warren
no, its not, its a tuple
a tuple with four strings inside it
so to check for equality, you have to check each string
heady warren
how is it a tuple if theres only text
the comma makes it a tuple
bronze rose
oh
mellow domeBOT
!e
```py
my_thing = 1, 2, 3
print(type(my_thing))
```
:white_check_mark: Your 3.14 eval job has completed with return code 0.
<class 'tuple'>
no, you normally just use in but to do it by hand you just check them one after each other
user_input == 'o'
user_input == 'n'
user_input == 'O'
user_input == 'N'
do you know how to add conditions together?
bronze rose
ohh
heady warren
when your writing a check?
bronze rose
do you know how to add conditions together?
yes
heady warren
how?
bronze rose
if user input == o or user input ==......
heady warren
yes.. lets do that
valid_input = 'o', 'n', 'O', 'N'
while True:
user_input = input('write something')
if user_input == 'o' and user_input == 'O' and user_input == 'n' and user_input == 'N' :
break
but can user input be both o and O at the same time?
bronze rose
cant you just do uppercase
heady warren
cant you just do uppercase
lets make it simple first, then add more things
and tells you something needs to be both true
bronze rose
you cant put oOnN tho
heady warren
would it be better to write or ?
heady warren
you cant put oOnN tho
if you use in you can. thats what in does, and you said you could not use it
heady warren
or
good.
while True:
user_input = input('write something')
if user_input == 'o' or user_input == 'O' oor user_input == 'n' or user_input == 'N' :
break
sorry its just its 1:30am im just tryna skip a few steps so i cna maybe do another one because i have class is 7h lol
heady warren
now we are getting somewhere
bronze rose
thats why i said uppercase
heady warren
i is smart to use uppercase or lowercase, bacuse you half the amount of checks you have to write
how would you make the user_input upper or lower case?
mellow domeBOT
!e
```py
print('O'.lower())
```
:white_check_mark: Your 3.14 eval job has completed with return code 0.
o
while True:
user_input = input('write something')
user_input = user_input.lower()
if user_input == 'o' or user_input == 'n':
break
oh wiat
heady warren
it will be easier
you can do one or the other
bronze rose
nvm that seems simpler
heady warren
yes, i agree
bronze rose
i was scared because of the tons of parenthesis lol
heady warren
i was scared because of the tons of parenthesis lol
() is needed to run something in python
bronze rose
the thing you wrote is really logical
heady warren
alright.. there is one final thing
it is how to swap out break with a condition (a rule for when the loop should end)
what is needed for this to work, have you been told?
bronze rose
a condition?
heady warren
yes, the rules of this condition
the thing you are checking in your condition, needs to change inside the loop
bronze rose
also for the function i need the function to return true or false and make it ask the questoin while the condition isnt o or n
heady warren
so now we will go from simple to a bit more comlicated
and this is something your teacher do on purpose
this is not something you would ever write for real
you want code to be simple
so lets add a running_loop condition instead of while True
bronze rose
and this is something your teacher do on purpose
why tho
i feel bad for taking so much for a single function when i have this to do
heady warren
why tho
because there are many languages out there, and not all have in to check for this
running_loop = True
while running_loop:
user_input = input('write something')
user_input = user_input.lower()
if user_input == 'o' or user_input == 'n':
running_loop = False
take a look at this change
heady warren
notice it is far less simple, but it is similiar to the one i wrote
bronze rose
ohhhhhhhhhhhhhhhhhhhhhh
heady warren
you need to check this in the loop as your conditiion
and you have to change that value inside the loop
so much work
three times the work, when you could just use a break
but do you agree that this example is the same?
bronze rose
yeah
bronze rose
https://paste.pythondiscord.com/DFLA
do you think i have enough time in 5 days to write this?
wait nvm you cnat underrstand french lmfao
mb
heady warren
do you think i have enough time in 5 days to write this?
yes, if you focus on thiinking simple and not so complicated
bronze rose
the cool thing is i understand what you're writing lol
heady warren
if you want to write this into a function, you have to have the function return something
what should a function of this do?
should it return True if o and False if n and continue the loop if anything else?
bronze rose
uhh
if its o you replay the hangman game
and if its n you just say thanks for playing or smt
heady warren
a function works well if it only does one thing
heady warren
the if statement that sets the running variable to False, at that place in yoour code, your response is valid. agree?
bronze rose
uh
heady warren
running_loop = True
while running_loop:
user_input = input('write something')
user_input = user_input.lower()
if user_input == 'o':
running_loop = False
elif user_input == 'n':
running_loop = False
else:
print('invalid input')
i have made it less simple now
bronze rose
i still understand it tho
bronze rose
while the running loop is true check what user input said and if its o or n stop the loop if its smt else print invalid input
heady warren
this can be put into a function, because it has clear checks for what happends insiidde the loop
def yes_or_no():
running_loop = True
while running_loop:
user_input = input('write something')
user_input = user_input.lower()
if user_input == 'o':
return True
elif user_input == 'n':
return False
else:
print('invalid input')
a function will end when you use return
bronze rose
boucle: bool
def ValiderRejouer() -> bool:
while boucle == True:
input_utilisateur: str = str("Voulez vous rejouer?\n")
input_utilisateur = input_utilisateur.lower()
if input_utilisateur == ("o") or input_utilisateur == ("n"):
boucle == True
else:
print(input_utilisateur)
here what i did
heady warren
and a loop will also end
heady warren
```py
boucle: bool
def ValiderRejouer() -> bool:
while boucle == True:
...
boucle has no value before the while loop
you have to assign it a value
bronze rose
can i just assign it to true or false
bronze rose
ohhh
bronze rose
im not sure what to writre with the return tho
bronze rose
yeah my bad
heady warren
write with the return?
bronze rose
i wouldve never noticed it lmao
bronze rose
write with the return?
dont i need to return smt
i need to return if its true or not
bronze rose
i dont see it
heady warren
def yes_or_no():
running_loop = True
while running_loop:
user_input = input('write something')
user_input = user_input.lower()
if user_input == 'o':
return True
elif user_input == 'n':
return False
else:
print('invalid input')
im doing thisi iin steps with you so you understand
heady warren
what happends in my yes_or_no functioon?
im still using the same code as before, almost at least
heady warren
if the user enters o or O it will return True
heady warren
if the user enters n or N it will return False
bronze rose
yeah
heady warren
if the user enters anytrhing else, the loop will go again
bronze rose
def ValiderRejouer() -> bool:
boucle: bool = True #Assigner une valeur pour que la fonction fonctionne
while boucle == True:
input_utilisateur: str = str(input("Voulez vous rejouer?\n"))
input_utilisateur = input_utilisateur.lower()
if input_utilisateur == ("o") or input_utilisateur == ("n"):
boucle == True
else:
print(input_utilisateur)
return boucle
is that part clear?
bronze rose
i think so yeah
heady warren
i think so yeah
in the function example, i am no longer doing something, because i change it to a return instead. what is that change i made?
if you focus on this, you will get there in a few moments
heady warren
```py
def ValiderRejouer() -> bool:
boucle: bool = True #Assigner une valeur...
your focusing on diifferent things now..
bronze rose
uh
heady warren
so please dont do that
sharp pelican
What does this function supposed to do? Asking user whether to continue playing?
bronze rose
so please dont do that
its almost 2am sorry lol
heady warren
its almost 2am sorry lol
im aware, but its only two more details to explain now ๐
bronze rose
```py
def yes_or_no():
running_loop = True
while running_loop:
u...
im not sure what changes...
heady warren
im not sure what changes...
lets loook
sharp pelican
then you should return the result of user input, true: y, false: n, keep asking: other inputs.
heady warren
def yes_or_no():
running_loop = True
while running_loop:
user_input = input('write something')
user_input = user_input.lower()
if user_input == 'o':
+ return True
- running_loop = False
elif user_input == 'n':
+ return False
- running_loop = False
else:
print('invalid input')
then handle your game logic in the main loop according to the return value of this function
heady warren
then handle your game logic in the main loop according to the return value of th...
thank you, but im explaining a while loop from the beginning due to some previous missunderstandings
bronze rose
then handle your game logic in the main loop according to the return value of th...
i dont even have the main loop
im starting the homework
heady warren
can you see the change?
bronze rose
```diff
def yes_or_no():
running_loop = True
while running_loop:
...
you stopped the loop from looping?
heady warren
you stopped the loop from looping?
return stops the function
bronze rose
oh
heady warren
so i dont need to tell the loop to end
bronze rose
if it stops why do you need true or false
heady warren
the loop can just run forever unless the user inputs the correct value
heady warren
if it stops why do you need true or false
you dont when you use it in a function
bronze rose
uh
heady warren
def yes_or_no():
while True:
user_input = input('write something')
user_input = user_input.lower()
if user_input == 'o':
return True
elif user_input == 'n':
return False
else:
print('invalid input')
now the while loop is a bit simpler
bronze rose
if it returns true does it loop back to the while
heady warren
if it returns true does it loop back to the while
no, return ends the function
heady warren
because you have to return one value, and this function checks if the user enters yes or no
true means it entered o for yes
false means he entered n for no
but i could have returned other things
the logic of the loop is still the same
bronze rose
how are you going to stop it from making an infinite loop then
heady warren
how are you going to stop it from making an infinite loop then
return
what is unclear?
bronze rose
i dont wanna make this difficuly im actually trying ๐ญ
heady warren
the loop is inside a function, the function ends... hence the loop does not run anymore
heady warren
i dont wanna make this difficuly im actually trying ๐ญ
your not difficult, im just not using the correct words
appreacite you for telling me when you dont understand
bronze rose
it returns nothing so because it will always be true UNLESS theres a return
heady warren
because that is important information, ii want to make you undersand it
bronze rose
OAIWNFPAOGISDNEPOWIWQH#EN:SHOIN
heady warren
it returns nothing so because it will always be true UNLESS theres a return
if the function returns, you have valid input yes
bronze rose
and at the end in the code i can just make if ValiderRejouter == True reloop the whole code and if false print thank you for playing
OHHHH
heady warren
because the only way to get out of the loop is with a valid return
heady warren
and at the end in the code i can just make if ValiderRejouter == True reloop the...
yes
but you dont need == True
you just do if ValiderRejouter()
bronze rose
what
bronze rose
ohh
im done with 1/30 of the work lmfao
um what
^
SyntaxError: invalid syntax
& C:/Users/jacin/AppData/Local/Programs/Python/Python313/python.exe "c:/Users/jacin/OneDrive - Cegep de Lanaudiere/Programmation/2025-01/tp2_git/tp2.py"
File "<stdin>", line 1
heady warren
def yes_or_no() -> bool:
while True:
user_input: str = input('write something')
user_input = user_input.lower()
if user_input == 'o':
return True
elif user_input == 'n':
return False
else:
print('invalid input')
notice i added type hints
bronze rose
i think i had those
heady warren
im done with 1/30 of the work lmfao
you have understood how a loop works
bronze rose
def ValiderRejouer() -> bool:
boucle: bool = True #Assigner une valeur pour que la fonction fonctionne
while boucle == True:
input_utilisateur: str = str(input("Voulez vous rejouer?\n"))
input_utilisateur = input_utilisateur.lower()
if input_utilisateur == ("o") or input_utilisateur == ("n"):
boucle == True
else:
print(input_utilisateur)
return boucle
i already understood how a loop worked but not within a funtion lmao
nvm im stupid
heady warren
does boucle change here?
bronze rose
i forgot something
heady warren
while boucle == True is the same as while boucle
bronze rose
oh
def ValiderRejouer() -> bool:
boucle: bool = True #Assigner une valeur pour que la fonction fonctionne
while boucle == True:
input_utilisateur: str = str(input("Voulez vous rejouer?\n"))
input_utilisateur = input_utilisateur.lower()
if input_utilisateur == ("o"):
boucle == True
elif input_utilisateur == ("n"):
boucle = False
else:
print(input_utilisateur)
return boucle
i forgot to unindent one time the return tho
i think
heady warren
dont mix changing boncle and return
notice i did not do that at all
if the user enters W your else will run and return True
bronze rose
i cant do multiple return in one single function
heady warren
you have broken the logic of the code by mixing multiple things
bronze rose
oh no
heady warren
what happends if the user enters W ?
heady warren
no
if the user enters W
three things happends in your code
if input_utilisateur == ("o"):
is this true or false?
heady warren
it is False, so it goes to the next
elif input_utilisateur == ("n"):
is this true or false?
heady warren
it is false, so it contineis to the next
there are no more, and else runs when all above are False
heady warren
by not using iit
bronze rose
i cant put multiple returns in a singel function
heady warren
or do you mean, as a limit of the task?
heady warren
my teacher doesnt want me to do that
oh i see..
bronze rose
sorry
heady warren
def yes_or_no():
while True:
user_input = input('write something')
user_input = user_input.lower()
if user_input == 'o':
return True
elif user_input == 'n':
return False
else:
print('invalid input')
that means one thing, your while looop will go back to be more complicated
because your loop need to end and then you do the one return
bronze rose
thats why i tried smt with boucle
heady warren
def yes_or_no():
running = True
while running:
user_input = input('write something')
user_input = user_input.lower()
if user_input == 'o':
running = False
elif user_input == 'n':
running = False
else:
print('invalid input')
print(running) # what is the value here?
yes, and remember that if you keep things simple, its easy to understand.. now we are making it more complicated to adhere to a school rule
bronze rose
im gonna have a meltdown lmfao
heady warren
im gonna have a meltdown lmfao
the code is back to beeing the same as before i made it more simple
well, i added the extra print
what is the value on the last line?
heady warren
if the user enters o here, what is the last print
bronze rose
false?
heady warren
yes
so the loop ends, you have a valid user input
if i to return True there, it means the loop ended, but might not be what you want
but once the loop has ended, you can return the one value you want.. what is that value your loooking for?
you can return user_input iit will be o or n
bronze rose
true or false?
heady warren
true or false?
true if o and false if n?
bronze rose
yes
heady warren
then lets add a new variable to keep track of if the answer is True or False
robust bison
hello
robust bison
can i make with u some python projects
bronze rose
i will physically not be able to wake up tmr if we dont end this quick ahah
i love your help but i still wanna get some sleep x)
heady warren
def yes_or_no():
running = True
while running:
user_input = input('write something')
user_input = user_input.lower()
if user_input == 'o':
running = False
response = True
elif user_input == 'n':
running = False
response = False
else:
print('invalid input')
return response
see?
heady warren
it will return the response value only if the loop ends
bronze rose
one to keep the loop and one for the return
heady warren
you used 2 comparisions
two variables yes
bronze rose
you're so smart ๐ญ
heady warren
one to keep the loop and one for the return
yes
heady warren
you're so smart ๐ญ
notice that the code is now not simple anymore
bronze rose
it kinda is
robust bison
```py
def yes_or_no():
running = True
while running:
user_input ...
u can use while True and in the end of the input .lower()
heady warren
and code that is not simple, breaks really easily
heady warren
u can use while True and in the end of the input .lower()
im not looking to make it more complicated or complex
bronze rose
u can use while True and in the end of the input .lower()
my brain is having a headache
i think
ik theres 9000 ways to make this easier but this will do
heady warren
but now it does what you want
bronze rose
now im 1/35 of the way done
robust bison
my brain is having a headache
but it still nice damn
bronze rose
and i have 5 days left
heady warren
ik theres 9000 ways to make this easier but this will do
break would soolve this in three lines ๐
heady warren
idk what im gonna do lmao
now that you have the ability to take user input, you should be able to do the same with other functions
robust bison
who can code using tkinter
heady warren
who can code using tkinter
#โ๏ฝhow-to-get-help please loook for your own help channel! ๐ this is occupied
i think this is enough for today @bronze rose
heady warren
notice that it is not easy to make something simple
bronze rose
now that you have the ability to take user input, you should be able to do the s...
i knew how to do it just not with a function
heady warren
idk what i learnt today
well.. you have not learned it yet, you have to do it yourself and repate to learn
bronze rose
can i show u smt i did rq
heady warren
sure
bronze rose
its too long hold on
also dont mind the mistake
i edited it accidentraly
just assume everything works
heady warren
i can see it
bronze rose
#ValiderRejouer
def ValiderRejouer() -> bool:
boucle: bool = True #Assigner une valeur pour que la boucle fonctionne
reponse: bool = True # Pour que le jeu recommence ou non
while boucle == True:
input_utilisateur: str = str(input("Voulez vous rejouer?\n"))
input_utilisateur = input_utilisateur.lower()
if input_utilisateur == ("o"):
reponse == True
boucle == False
elif input_utilisateur == ("n"):
reponse == False
boucle == False
else:
print(input_utilisateur)
return reponse
is this better
heady warren
dont use return in the else
def yes_or_no():
running = True
while running:
user_input = input('write something')
user_input = user_input.lower()
if user_input == 'o':
running = False
response = True
elif user_input == 'n':
running = False
response = False
else:
print('invalid input')
return response
notice that i have the return outside of the loop
bronze rose
ohh yeah
heady warren
the loop ends when you have valid user input
bronze rose
#ValiderRejouer
def ValiderRejouer() -> bool:
boucle: bool = True #Assigner une valeur pour que la boucle fonctionne
reponse: bool = True # Pour que le jeu recommence ou non
while boucle == True:
input_utilisateur: str = str(input("Voulez vous rejouer?\n"))
input_utilisateur = input_utilisateur.lower()
if input_utilisateur == ("o"):
reponse == True
boucle == False
elif input_utilisateur == ("n"):
reponse == False
boucle == False
else:
print(input_utilisateur)
return reponse
is that ok
heady warren
you should test it and see
bronze rose
File "<stdin>", line 1
& C:/Users/jacin/AppData/Local/Programs/Python/Python313/python.exe "c:/Users/jacin/OneDrive - Cegep de Lanaudiere/Programmation/2025-01/tp2_git/tp2.py"
^
SyntaxError: invalid syntax
dim knoll
Off topic but respect to both of yall for being dedicated for an hour and a half straight
bronze rose
Off topic but respect to both of yall for being dedicated for an hour and a half...
i wanna cry btw
because i have done 1/35 and i have 5 days left
dim knoll
Goodluck man
bronze rose
ill go sleep
im tired
im exhausted
my brain is dead
i wanna cry
thanks eivl ttyl ๐ญ
(prolly tmr)
dim knoll
Sleep well mate
mellow domeBOT
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