🔒 how to copy the same file over to a destination path

[austere barn]

basically I'm trying to copy the same file multiple times into a new folder, each with either the same name or same-ish name to help indentify it was copied over multiple times

[strong galleon]

@austere barn

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[austere barn]

import random
import shutil

number_of_people = int(input("How many people are there?"))

list_of_stuff = []
stuff_to_add = list(range(1,69))

for i in range (number_of_people)
    random.shuffle(stuff_to_add)
    source_path = rf"C:\blah blah file path\{stuff_to_add[0]}.file"
    destination_path = rf"C:\blah blah file path 2"
    shutil.copy(source_path, destination_path)
    list_of_stuff.append(stuff_to_add[0])
    print(list_of_stuff)

lets say the number 42 is shuffled and put as position 0 in "stuff_to_add" multiple times
how can i copy multiple of said file into the destination path?
would i have to get the code to rename the file copied or what is the options here?

going to step away for just a moment though so if i dont respond right away sorry

[valid obsidian]

for n in range(2,20): # or something to pick the numbers to try
    copy(original_filename, f'{dest_dirpath}/{some_filename}{n}')

or some suitable variation on that.
You can precheck if the file exists with os.path.exists to avoid tromping things. You'd need a precheck if eg you used shutil.copyfile for the copy, or if you're opening the new file yourself you can use the 'x' open mode, which will fail of the file exists.

[austere barn]

sorry was finishing dinner

okay my brain is failing me tonight on this tbh, can i just ask this question tomororow lol

[valid obsidian]

Probably provide more detail on what you're doing. Just copying files into a folder and renaming with a number to avoid conflicts? Something else?

Anyway, for then, not now.

[austere barn]

gotcha, my full code is over 300 lines so i didnt want to paste all that when the issue is one paart but yeah

[strong galleon]

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