🔒 Sort method for list

[ocean pivot]

I am dumbfounded as to why this prints None:

print([1,2].sort())

No I have not made a separate function called print or anything, this is the entire script (I am playing around learning sorting algorithms):

import subprocess
subprocess.run('clear')

array = [1, 3, 3, 0, 5, 2, 6]

def selectionsort(arr : list):
    for start_idx in range(len(arr)):
        min_element = arr[start_idx]
        for element in arr[start_idx:]:
            if element < min_element:
                min_element = element
        min_idx = arr[start_idx:].index(min_element) + start_idx

        arr[min_idx], arr[start_idx] = arr[start_idx], arr[min_idx]

    return arr
    
print(selectionsort(array))
print([1, 2].sort())

If my selectionsort is wrong or ineffective I don't want any help with that, I just want to figure out why this prints None for now.

[agile sage]

@ocean pivot

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[mortal blade]

sort method does an in place sort and returns None

You probably want sorted

[tawny thistle]

was js gonna type that

[ocean pivot]

Okay thanks!

That make the entire thing work

[toxic slate]

!e

x = [3, 2, 1]

y = sorted(x)
print(y)

x.sort()
print(x)

print(x.sort())

[tawny thistle]

you could store the array in a variable and sort it, then use it.

[agile sage]

:white_check_mark: Your 3.13 eval job has completed with return code 0.

001 | [1, 2, 3]
002 | [1, 2, 3]
003 | None

[toxic slate]

There you go

[tawny thistle]

@toxic slate oh damn, i did not know we could eval code with bot..

[toxic slate]

.sort() sorts the list without returning a new one, while sorted() creates a new sorted list

[ocean pivot]

!close

[agile sage]

Python help channel closed with !close

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