🔒 Is there a better way to do this?

[thorny sapphire]

            if num[index] == 'one':
                num[index] = 1
            elif num[index] == 'two':
                num[index] = 2
            elif num[index] == 'three':
                num[index] = 3
            elif num[index] == 'four':
                num[index] = 4
            elif num[index] == 'five':
                num[index] = 5
            elif num[index] == 'six':
                num[index] = 6
            elif num[index] == 'seven':
                num[index] = 7
            elif num[index] == 'eight':
                num[index] = 8
            elif num[index] == 'nine':
                num[index] = 9
            elif num[index] == 'zero':

[sharp ridge]

@thorny sapphire

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[glossy marlin]

Have you learned about dictionaries yet?

[thorny sapphire]

yes

[glossy marlin]

You can make a dict mapping then

[thorny sapphire]

import re
num_dict = {
        'one':1,
        'two':2,
        'three':3,
        'four':4,
        'five':5,
        'six':6,
        'seven':7,
        'eight':8,
        'nine':9,
        'zero':0
        }
with open('meow.txt','r') as file:
    for line in file:
        num = (re.findall('one|two|three|four|five|six|seven|eight|nine|zero',line))
        for index,item in enumerate(num):
            num[index] == num_dict.get(item)
        print(num)
        

nvm got it

!close

[sharp ridge]

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