🔒 confused

[soft stag]

hour = int(input("Starting time (hours): "))
mins = int(input("Starting time (minutes): "))
dura = int(input("Event duration (minutes): "))

#hour = 24
#mins = 60

mins = mins + dura # find a total of all minutes
hour = hour + mins // 60 # find a number of hours hidden in minutes and update the hour
mins = mins % 60 # correct minutes to fall in the (0..59) range
hour = hour % 24 # correct hours to fall in the (0..23) range
print(hour, ":", mins, sep='')

[harsh river]

@soft stag

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[soft stag]

i was trying to solve this but ended up giving up because i couldn't figure it out

but going over the answer, how is mins & hour defined twice

wouldn't that just ignore the first definitions of mins & hour?

i thought python cared about defining a variable twice but when you do, the 1st variable becomes useless

[foggy crystal]

not exactly

notice how the second assignment to mins references mins? that uses the value from the first assignment

so:

foo = 4 + 4   # afte this, foo == 8
foo = foo / 2  # foo is 8, so this is 8 / 2

foo will be 4 after the above

remebmer that in an assignment statement, the expression the right of = is evaluated first, and then the value that expression evaluates to is assigned to the name on the left

[sullen jolt]

you probably want to use # for comments instead of // as that is another operator in python, especially here when doing calculations

[foggy crystal]

thanks! I'm days-deep in a frontend project and the js has taken over

[sullen jolt]

haha, yes, looked like you where coming from one of many many other language where // is for single line comments 🙂

[soft stag]

why can't you just do mins = mins + dura % 60 in one line

[foggy crystal]

yo uabsolutely can

[soft stag]

i at least had that part

[foggy crystal]

breaking it up is purely an aesthetic preference here

[soft stag]

i coudlnt figure out how to get the hour

[sullen jolt]

it isn't useless unless you never use that value before overwriting the variable with a new value

[foggy crystal]

there's mixed opinions here: on one hand, re-assigning variables is generally discouraged because it can make it hard to reason about the current value/meaning of a variable later in the code (was foo this thing, or that other thing?) and it can muddy type signatures. On the other, it can clear up what migh totherwise be complicated logic (I think your example falls into this category)

[sullen jolt]

there is a function named divmod() that would probably be beneficial here that does both operations at the same time and yields two results

!d divmod

[harsh river]

divmod

divmod(a, b)```
Take two (non-complex) numbers as arguments and return a pair of numbers consisting of their quotient and remainder when using integer division. With mixed operand types, the rules for binary arithmetic operators apply. For integers, the result is the same as `(a // b, a % b)`. For floating-point numbers the result is `(q, a % b)`, where *q* is usually `math.floor(a / b)` but may be 1 less than that. In any case `q * b + a % b` is very close to *a*, if `a % b` is non-zero it has the same sign as *b*, and `0 <= abs(a % b) < abs(b)`.

[sullen jolt]

just to clarify, what result are you getting and what are expecting instead?
asking because as far as i can tell i think your code should be working even if it can be done in several other ways

[sullen jolt]

!e - just as a demo, this does the same but without the input as it doesn't work here with the python bot

hours = 24
minutes = 60
duration = 2

hours, minutes = divmod(hours * 60 + minutes + duration, 60)
hours %= 24
print(f"{hours}:{minutes}")

[harsh river]

:white_check_mark: Your 3.13 eval job has completed with return code 0.

1:2

[harsh river]

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