🔒 Answer will likely be obvious, but I cant work it out

[sharp warren]

Why is time() failing here

[cursive pelican]

@sharp warren

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[sharp warren]

How do I fix time() not working due to an out of bounds error.

Apologies for the strange screenshot, python was showing my folder name in the shell and I needed to leave that out

[weak mango]

you're importing the function time, but then you're also naming a variable time inside your function

use a different name in your function

for this line, use a name other than time

(you're also not timing correctly but one thing at a time)

[sand inlet]

Python looks ahead in the function definition to determine which variables are local to the function, and which are from outside.

def fun():
    print(time)
``` This uses whatever `time` is from outside the function.

```py
def fun2():
    time = 2
    print(time)
``` This uses the local variable `time` from inside the function, instead.

```py
def fun3():
    print(time)  # error
    time = 2
``` This *also* tries to use the local variable `time` in the function. But that variable is not yet defined when the `print(time)` code attempts to run, so it throws an error.

Best option, as Fashoomp points out: just rename the variable in the function to avoid confusion.

[steady walrus]

Another tip , perf_counter is more accurate than time

[cursive pelican]

Python help channel closed for inactivity

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