🔒 Gang can someone explain me the reason behind

[spare ravine]

if i == len(arr) - 1:
return

[fleet belfry]

@spare ravine

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[spare ravine]

I mean what's the purpose of -1 , here

[lusty karma]

the important thing to remember is, that indices of lists start from 0

that means if you have a list of length 5, say like this:
['apple', 'orange','lemon', 'lime', 'blueberry']
then the respective indices are 0, 1, 2, 3, 4

so when i == len(my_list)-1 == 4, that's the last element

[spare ravine]

so in the output it'll show 4 elements

[astral crescent]

No the output is a boolean

[spare ravine]

nah I'm just telling in basic case

[random stone]

it is to detect if it is at the last element, because you would go out of bound if you do i + 1 at that point

[spare ravine]

@astral crescent

[astral crescent]

You need to actually say the code

!code

[fleet belfry]

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[spare ravine]

!code

[astral crescent]

Read the message bro

[astral crescent]

That isn't showing any elements, that's a number

[spare ravine]

mhm

[random stone]

len(l) - 1 give you the index of the last elemen

[spare ravine]

yeh

[astral crescent]

Notice that we do arr[i + 1]

In order for this to work, we have to stop i one before the last index

otherwise i + 1 is too large

[spare ravine]

sorry guys but I can't understand shit atp the i+1 stuff

okay lemme try to tell you guys what I've understand now that len(arr)-1 , will gonna print boolean according to the respective indices as @lusty karma said

[spare ravine]

here

now that case I understood ,

GANG

IG i understood

now

in 2nd case if arr[i] > arr[i+1]: , it'll gonna add false , as its in arr2 case . 5>8 (false)

tyy guys for the help I appericiate that

!lock

[fleet belfry]

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