#🔒 Can someone help me fill in the numbers?

45 messages · Page 1 of 1 (latest)

novel hollow
#

So i got this code here to determine if a number is odd or even, but it takes me to long to code, need help

remote gardenBOT
#

@novel hollow

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novel hollow
# 
number = 1842
if number == 0:
    print("Even")
if number == 1:
    print("Odd")
if number == 2:
    print("Even")
if number == 3:
    print("Odd")
if number == 4:
    print("Even")
if number == 5:
    print("Odd")
if number == 6:
    print("Even")
if number == 7:
    print("Odd")
if number == 8:
    print("Even")
if number == 9:
    print("Odd")
if number == 10:
    print("Even")
if number == 11:
    print("Odd")
if number == 12:
    print("Even")
if number == 13:
    print("Odd")
if number == 14:
    print("Even")
if number == 15:
    print("Odd")
if number == 16:
    print("Even")
if number == 17:
    print("Odd")
if number == 18:
    print("Even")
if number == 19:
    print("Odd")
if number == 20:
    print("Even")
if number == 21:
    print("Odd")
if number == 22:
    print("Even")
if number == 23:
    print("Odd")
if number == 24:
    print("Even")
if number == 25:
    print("Odd")
if number == 26:
    print("Even")
if number == 27:
    print("Odd")
if number == 28:
    print("Even")
if number == 29:
    print("Odd")
if number == 30:
    print("Even")
if number == 31:
    print("Odd")
if number == 32:
    print("Even")
if number == 33:
    print("Odd")
if number == 34:
    print("Even")
if number == 35:
    print("Odd")
if number == 36:
    print("Even")
if number == 37:
    print("Odd")
if number == 38:
    print("Even")
if number == 39:
    print("Odd")
if number == 40:
    print("Even")
if number == 41:
    print("Odd")
if number == 42:
    print("Even")
if number == 43:
    print("Odd")
if number == 44:
    print("Even")
if number == 45:
    print("Odd")
if number == 46:
    print("Even")
if number == 47:
    print("Odd")
sweet fox
#

Just to double check: Are you serious or is it a joke ?

novel hollow
#

why wouldnt I?

#

someone told me to use %

#

but i dunno how

sweet fox
#

yep

thorny dock
#

AI could probably help with this

sweet fox
#

% returns the remaining of the integer division

thorny dock
#

Or write a function to write the function

novel hollow
#

ahhh

sweet fox
novel hollow
#

so number % 2 = 0 is even

#

?

#

==*

sweet fox
#

yep

novel hollow
#

ok ty

sweet fox
novel hollow
#

even thought of coding more if clauses with an algorithm

sweet fox
#

repeting the (nearly) same line/block of code usually means you can do it more efficiently

#

At least with a loop and a function, or even with just like a different algorithm

round grotto
livid goblet
sweet fox
#

can you not insult people ?

lyric chasm
#

actually, this code is bad because its only up to 47 numbers and users cant send numbers higher like 500 or something
i would recommend you to do this instead
https://paste.pythondiscord.com/KZWQ

sweet fox
#

it's normal for a beginner to make mistakes, not knowing how to use features and making bad algorithms. That's why you learn

sweet fox
#

or is it a joke ?

lyric chasm
#

isnt that obvious

sweet fox
#

it's not

lyric chasm
#

i wouldnt waste my time writing 1k lines of code, so thats definitely a joke

stuck chasm
#

perhaps people should focus on being helpful or being silent

fair brook
#

Insulting peoples intelligence is not appropriate. if you don't want to give this person the benefit of the doubt, just don't engage with the thread.

livid goblet
livid goblet
silk path
#

there are other ways
like you can use // (integer division)

# checks if rounding down is the same as halfing thus checking if the half is an integer
x//2 == x/2
# same as:
floor(x/2) == x/2
#but floor has to be imported from math

or recursion

# recursion is the fact that a function can call itself, in this case that's done in 2 steps
# as a bonus here you get bot is_even and is_odd 
def is_even(x: int) -> bool:
  if x == 0:
    return True
  return is_odd(x-1)
def is_odd(x: int) -> bool:
  if x == 0:
    return False
  return is_even(x-1)

or loops can do it similarly as you did just for bigger numbers

# your method: counting up and checking if equal
n = 0
is_even = True
while n != x
  is_even = not is_even
  n += 1

or replicate the recursion with loops

# recursion method: counting down checking if 0
is_even = True
while x != 0:
  is_even = not is_even
  x -= 1

there are ways with binary operations

x >> 1 << 1 == x
# or
bool(x & 1) # need bool() because the result is 0 or 1

there are a lot of funny ways
some of them show different tools
but most of them are way slower and more complicated than needed

not x%2 # don't need bool() beacuse not a is the same as not bool(a)

is the most used i think

here is an other joke method

def is_even(x: int) -> bool:
  return not is_odd(x)
def is_odd(x: int) -> bool:
  return not is_even(x)

which is funny because it never finishes and symbolizes people trying to get others to do their tasks resulting in those tasks never getting done

lyric chasm
# 
num = input(">> ")
result = "Even" if int(num) % 2 == 0 else "Odd"
print(result)```
how bout this
silk path
lyric chasm
#

oh

#

yea

silk path
remote gardenBOT
#
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