🔒 is there a way to make this code more efficient?

[feral vale]

here is the code:

file_name = input("file name:  ").lower().strip()
if file_name.endswith((".jpg","jpeg")):
    print("image/jpeg ")
elif file_name.endswith((".png",)):
    print("image/png ")
elif file_name.endswith((".gif")):
    print("image/gif ")
elif file_name.endswith((".pdf")):
    print("application/pdf ")
elif file_name.endswith(("txt")):
    print("text/plain ")
elif file_name.endswith((".zip")):
    print("application/zip ")
else:
    print("application/octet-stream")

[grizzled plaza]

@feral vale

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[blazing dune]

There is a clear pattern where the folder is simply the name of the extension after the period.

The only exceptions is jpg, which you can solve by replacing .jpg with .jpeg before checking which folder it should be placed in.

Oh hmm, not exactly just the suffix

But you can make a mapping for each suffix to a specific folder name

[desert rune]

I'd use pathlib.Path to do the extension (aka "suffix") detection, then a dictionary to map to your relevant value

[blazing dune]

suffix_to_folder = {
  "jpg": "image/jpeg",
  "png": "image/png",
  etc.
}

And pathlib is indeed nicer to get the suffix in a more readable way

[feral vale]

I see

I didnt think of that

[desert rune]

from pathlib import Path
fname = input("file name: ")
p = Path(fname.strip())
mapping = {
   ".pdf": "application/pdf",
   ".jpg": "application/jpg",
   ".jpeg": "application/jpg",
   ...
}

result = mapping.get(p.suffix.lower(), "application/octect-stream")

print(result)

something like that maybe

[feral vale]

thank you both very much.

[grizzled plaza]

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