I want to print a range of numbers from 1 to 100.
But every number that is a factor of 3, I want to print "Fizz", every number that is a factor of 5, I want to print "Buzz", and every number that is a factor of 15, I want to print "FizzBuzz".
#🔒 Doing a coding exercise using for loops, and range function. Why doesn't this print what I expect?
candid tinsel
frozen fjordBOT
I want to print a range of numbers from 1 to 100.
But every number that is a fac...
@candid tinsel
Python help channel opened
candid tinsel
I have a feeling Im headed the right direction, I just cant tell what it is I am missing.
shy kraken
You are comparing the right thing
Now you are doing :
Is number equal to its third ? Then print "Fizz"
etc.
You want to do:
Is the third of the number an integer ? Then print "Fizz"
candid tinsel
I figured writing it like that to mean "If the number is an integer after dividing number by 3, then print "Fizz".
shy kraken
You will also need to think about your ifs and elifs: do you want to enter the elif if your previous if passed ?
shy kraken
I figured writing it like that to mean "If the number is an integer after dividi...
That's not how
candid tinsel
I guess not. So they would need to be seperate if statements for each condition im writing
shy kraken
Shhh
Let him think
He read the message already but 🤷♂️😅
Tips: you can use the modulus, you don't have to
candid tinsel
Yeah i haven't made it that far in the course im taking lol
okay i know how to fix my if statements, but im blanking on how to write this equation differently
the third of every number an integer.
well i cant add steps because I want all the other numbers included in the list
shy kraken
think about : what property does an integer have ?
candid tinsel
its a whole number, and not a float.
shy kraken
True, what a property a float has that an int do not ?
There are several good answers
candid tinsel
decimal points?
shy kraken
That is one good answer
If you already know about strings, you can manage to do it
Wait no
Python doesn't work like that
Integers have a decimal point
Only it is hidden
Like 3 is equal to 3.0
And python divison return a float
So you need another property
shy kraken
Not necessarily
Alright
If N is an integer (or a float ending by .0)
What's int(N) ?
candid tinsel
its whatever N is equal to
floral tartan
3 is only represented as 3.0 if it's a float, not when it is an int
and it's correct that division always returns a float in python
candid tinsel
are you talking about making it a string?
shy kraken
You don't have to
Like you can, but is logically not a good solution imo
Stick with number
And what I asked you
candid tinsel
I can't think of any other properties. If its going to be a float after I divide it, then it doesn't matter, unless I convert the result to a int, which is what i thought i was doing.
candid tinsel
Im trying to tell the program that if (number from range is divisible by 3, and is an integer) print as "Fizz instead"
floral tartan
I can't think of any other properties. If its going to be a float after I divide...
converting a float to an integer with int() will just remove/truncate any decimals, not even round it, it's effectively a floor() operation
shy kraken
Im trying to tell the program that if (number from range is divisible by 3, and ...
That's not what you are doing
candid tinsel
oh so it might even just divide every number and remove the decimal then, which i dont want either
shy kraken
Read carefully your code
You are currently printing Fizz is a number is equal to int(number/3)
So if a number is equal to the integer part of its third
floral tartan
that should only be true for 0
shy kraken
You want the integer part of the third of the number to be equal to the third of the number
candid tinsel
Yeah I keep rewriting it, only for it to end up the exact same. So I guess its a conceptual issue on my part. Let me go back and read through everything here again.
shy kraken
You want the integer part of the third of the number to be equal to the third of the number
Let's get it step by step:
Let N an integer
What is "the integer part of the third of N" ?
Then, what is the "third of N"
Then, how can you compare if the two are equal ?
And finally:
What do you do in that case?
ancient quiver
maybe spell out everything with variable names first to sort it out
third_of_number = ...
int_of_third_of_number = ...
..etc
Normally this would help. But as I said, I think im just having trouble wrapping my brain around it.
shy kraken
Then, how can you compare if the two are equal ?
You are there
ancient quiver
so close, line 4
shy kraken
I gotta go andrew I let you finish helping him, also about the assignation and print statement
ancient quiver
as @shy kraken said:
You want the integer part of the third of the number to be equal to the third of the number
Is that what you have on line 4?
And I'll give you this one for free: your indentation is wrong on line 8
print is outside of the for loop, which you don't want
How 'ya doing @candid tinsel ?
candid tinsel
well thank you for that freebie, it did change the result
instead of printing 100 like normal. It just lists the range normally from 1 to 100
ancient quiver
good. you can probably limit that to 20 for now, so the output isn't so long
but there's still a mistake on line 4
and you're probably overthinking it.
I can't think of any other hint than:
You want the third of the number to be equal to the integer part of the third of the number
Try reading it out loud
shy kraken
Try describing line by line what your current algorithm is doing
And spot the differences with what it should do
candid tinsel
so like this?
int_of_third_number = int(third_of_number / 3)
int of the third number equal to the third number of the integer
ancient quiver
no, at that point you'd be dividing by 9... because you're taking 1/3rd of 1/3rd of the number
how about changing your print call to
print(number, int_of_third_number, third_of_number)
maybe seeing the data would help achieve your goal
candid tinsel
I've been doing this course work for a couple hours and Im just getting tunnel vision I think. Im gonna step away for a couple of hours, and revisit everything here and see what I can come up with then. Thank you guys. Sorry for the headache. This course moves pretty quickly and I don't want to get in the habit of getting stuck, looking at the solution and learning nothing.
ancient quiver
Tunnel vision is common, and stepping away is usually a good idea. Let us know here if you get it. 👋
floral tartan
I've been doing this course work for a couple hours and Im just getting tunnel v...
just know that these help threads are automatically closed by a bot after an hour without any activity, so if you or anyone else isn't keeping it alive it will get closed, and you'll have to open a new help thread
floral tartan
Normally this would help. But as I said, I think im just having trouble wrapping...
another tip, the // operator also divides, but it always gives you an integer by flooring the result
you will end up with the same result as putting int() around your division or the result of your division
ancient quiver
I had another option to suggest:
float objects have a method f.is_integer() which simplifies the logic:
>>> f = 1 / 3
>>> f.is_integer()
False
>>> f = 3 / 3
>>> f.is_integer()
True
rocky nacelle
i feel like this is a good time to tell them about the modulo operator
coarse garnet
and floor division just for funsies
timid needle
i feel like this is a good time to tell them about the modulo operator
he said he ain't that far yet into the course he's learning
timid needle
I want to print a range of numbers from 1 to 100.
But every number that is a fac...
You can just do this
for number in range(1, 101):
if number % 3 == 0:
print(f'{number} frizz')
the modulo operator give the remaining of a division and == check if said remaining is equal to 0.
frozen fjordBOT
Python help channel closed for inactivity