🔒 I am trying to make a wave like pattern can you help me in a step

[nocturne elbow]

@leaden jetty

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[leaden jetty]

import time
def design():
    while True:
     for x in range(10):
         print("*"*x)
         time.sleep(0.2)
        
        
design()

I want that after stars increase to 10 they should decrease and then increase so a wave like pattern form

@versed spire

[versed spire]

yes

i will try to help

[fluid plover]

uhh what's the problem?

[leaden jetty]

This I want to do this

[versed spire]

oh ok

i will try to make it

[fluid plover]

soo it'll just start with 10 and dicrease one by one ?

[leaden jetty]

Uh?

[balmy ferry]

!e - looks like this works

for n in range(10):
   print("●"*n)

what are you having trouble with? maybe having it decrease in length?

[nocturne elbow]

:white_check_mark: Your 3.13 eval job has completed with return code 0.

001 | 
002 | ●
003 | ●●
004 | ●●●
005 | ●●●●
006 | ●●●●●
007 | ●●●●●●
008 | ●●●●●●●
009 | ●●●●●●●●
010 | ●●●●●●●●●

[leaden jetty]

Yeah decrease after increasing to 10

[balmy ferry]

or did u want to animate it, to run on a single/multie lines?

[leaden jetty]

This

I don't know how to decrease

[fluid plover]

n=n-1 i think this might work

[balmy ferry]

well you could go about it in multiple ways.

some quick examples -
• using another loop, with negative steps.
• using reversed()
• creating a cycle; using a while loop, or the builtin itertools.cycle().

!d range

[nocturne elbow]

range

class range(stop)``````py

class range(start, stop[, step])```
The arguments to the range constructor must be integers (either built-in [`int`](https://docs.python.org/3/library/functions.html#int) or any object that implements the [`__index__()`](https://docs.python.org/3/reference/datamodel.html#object.__index__) special method). If the *step* argument is omitted, it defaults to `1`. If the *start* argument is omitted, it defaults to `0`. If *step* is zero, [`ValueError`](https://docs.python.org/3/library/exceptions.html#ValueError) is raised.

For a positive *step*, the contents of a range `r` are determined by the formula `r[i] = start + step*i` where `i >= 0` and `r[i] < stop`.

For a negative *step*, the contents of the range are still determined by the formula `r[i] = start + step*i`, but the constraints are `i >= 0` and `r[i] > stop`.

Similar names: django.range

[leaden jetty]

I used reversed it's say reversed object<code>

[balmy ferry]

!e - working with this,

using negative steps, inside range() —

for n in range(10, -1, -1):
   print("●"*n)

using reversed()

print("\nUsing reversed —\n")

for n in reversed( range(10) ):
   print("●"*n)

[nocturne elbow]

:white_check_mark: Your 3.13 eval job has completed with return code 0.

001 | ●●●●●●●●●●
002 | ●●●●●●●●●
003 | ●●●●●●●●
004 | ●●●●●●●
005 | ●●●●●●
006 | ●●●●●
007 | ●●●●
008 | ●●●
009 | ●●
010 | ●
... (truncated - too many lines)

Full output: https://paste.pythondiscord.com/5SQG63MD7MSRYFCF7755NRA5D4

[leaden jetty]

Oo we can use reversed with range

New topic for me thanks

Now I can do it

[balmy ferry]

!e - do notice that simply stating range(10), yields a sequence that starts from zero(0)

print( list(range(10)) )

[nocturne elbow]

:white_check_mark: Your 3.13 eval job has completed with return code 0.

[0, 1, 2, 3, 4, 5, 6, 7, 8, 9]

[balmy ferry]

meaning that the first part/print would be printing nothing(/empty string)

!e

print("●"*0)
print("●"*1)

[nocturne elbow]

:white_check_mark: Your 3.13 eval job has completed with return code 0.

001 | 
002 | ●

[balmy ferry]

consider starting the sequence from 1; range(1, 10) .

[balmy ferry]

^ for more info, regarding range() functionality, refer to this.

@leaden jetty (didn't ping ;-;)

[nocturne elbow]

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