🔒 someone help me

[fervent sun]

@fickle mango

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[timber yoke]

@fickle mango r u ok hahahahah

isnt this like ur 4th ticket within 20min

[fickle mango]

i gave up

i tried more than 14 hours :osb

[lime lion]

Print this and print listsd. See what's in them.

[lime lion]

Same bug as the previous one to my eye.

[timber yoke]

yep

@fickle mango okay so

a function

returns something

right

[fickle mango]

also i m seeing that since its a reference and not a new value so i cant assign a new value to it?

[timber yoke]

even when it returns nothing, it returns None, which is still "somethinf"

[lime lion]

Have you printed them yet?

[lime lion]

Also print(this) after the insert call.

[timber yoke]

now what happens to listsd after you say defkne it as text.split @fickle mango

[fickle mango]

i got u i want to make listd = this anyhow

so in next for loop it searches in list

instead of listd

basically changing the listd

[fickle mango]

i could not get what u saying

[timber yoke]

listsd = ...

[fickle mango]

its useless

[timber yoke]

the default python functions normally always use this formst

u can modify the data itself or create a new version of the data which is modified right away

sorted(list) and list.sort()

are great examples

so with sorted we are returning a sorted version of the list

as the name implies

with list.sort we are modifying the existing list

does this make sense? @fickle mango

[fickle mango]

gimme 2 mins

[fickle mango]

yeah so u saying basically in case value in place changes then function if didnt return anything still original value get affected

but i want to smh make both of them equal

so it searches for word in 'this'///

[timber yoke]

theres more to it id say but lets keep this close to a college course and so let you figure that out 5 years later

so .insert returns None

we know that

but it doesnt affect the original data

so

im gonna blow ur mind here

[fickle mango]

no way

wait

it affects i thought

[timber yoke]

instead of value = list.insert

lets do

list.insert

with assigning the output to a value

[fickle mango]

it affects value of this///

?

[fickle mango]

why now its not doing inplace and still returning None

[cerulean cradle]

sentence = "ADJECTIVE is NOUN and VERB is NOUN too."

for word in sentence.split():
    print(word)
    if word in ("ADJECTIVE", "NOUN", "VERB"):
        sentence = sentence.replace(word, input(f"Enter a {word}: "))

print(sentence)```

take this as an example

''.join(...) returns a value but you haven't assigned the output to anything, it doesn't actually change the listsd variable

[fickle mango]

can u give a list which returns and which dont /

[cerulean cradle]

I'm not sure which ones you know yet but it's a simple fix, just do my_variable = ''.join(...) instead if you want to keep that

[fickle mango]

i tried this trick of joining and splitting again to reassign it again

[cerulean cradle]

what's the point of joining the string back before adding the word? just do whaty I did in the example

sub it into the list directly

[fickle mango]

this is easy

[fickle mango]

to assign it a variable

which i cant directly

coz it changes value of list directly

[fickle mango]

isnt it possible to do it with join and split though like i did?

[fickle mango]

tyvm

like literally i was stuck for 12 hours

its working now

!close

[fervent sun]

Python help channel closed with !close

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