🔒 Can anyone help me with homework? | Python | Page 1

wraith void Apr 5, 2025, 1:05 AM

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Find the most frequent appearing value in a dictionary, if there are ties, just return any one among them
eg.
input: {"john": 3.5, "jane": 4.0, "bob": 2.8, "mary": 4.0}
output: 4.0
Given a list of numbers, return a list with the order of numbers reversed (challenging)
hint: try to use the range function in a forloop, by counting the numbers in the list in reverse
then try to build a new list out of it
input: [1,2,3,4,5]
out: [5,4,3,2,1]

subtle schoonerBOT Apr 5, 2025, 1:05 AM

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wraith void 2. Find the most frequent appearing value in a dictionary, if there are ties, ju...

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@wraith void

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wraith void Apr 5, 2025, 1:08 AM

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how do i write a list?

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i know .dict doesnt allow duplicates

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tht i know

static ravine Apr 5, 2025, 1:10 AM

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list = [1, 2, 3]

wraith void Apr 5, 2025, 1:11 AM

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how can i write a list using input?

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input("Write a list of numbers")

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how do i get python to detect tht list of numbers?

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anyone here?

static ravine Apr 5, 2025, 1:13 AM

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Uhh

fiery depot Apr 5, 2025, 1:13 AM

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What do they mean by "given a list of numbers"? That can mean different things.

wraith void Apr 5, 2025, 1:14 AM

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urm

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like

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input("1, 2, 3, 4, 5")

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and then make python write

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5 4 3 2 1

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yea

static ravine Apr 5, 2025, 1:14 AM

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I don't think they're looking for an input

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I think it's just in the code

wraith void Apr 5, 2025, 1:15 AM

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mind getting the 2nd one done first?

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i know what .dict is, HOW DO I WRITE A LIST WITH .DICT

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LIKE

fiery depot Apr 5, 2025, 1:15 AM

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If you mean a comma separated string representing a list, look j into the split method on strings.

wraith void Apr 5, 2025, 1:15 AM

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list.dict?

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list.dict = [1, 2, 3, 4, 5, 5] i have tried this

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gives me an error

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TypeError: cannot set 'dict' attribute of immutable type 'list'

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wtf is tht supposed to mean

static ravine Apr 5, 2025, 1:16 AM

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I don't think you're supposed to use list.dict

fiery depot Apr 5, 2025, 1:16 AM

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That line of code attempts to create a dict attribute on the list class, because you did an assignment.

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What are you trying to do there?

wraith void Apr 5, 2025, 1:17 AM

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.dict doesnt allow duplicats correct?

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im tryna like get .dict to give me the duplicate

fiery depot Apr 5, 2025, 1:17 AM

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wraith void .dict doesnt allow duplicats correct?

It doesn't allow duplicate keys, no

wraith void Apr 5, 2025, 1:17 AM

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wdym?

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like 1, 1, 2, 2, 3,

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would be 1, 2, 3?

fiery depot Apr 5, 2025, 1:18 AM

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A dictionary can't have two of the same key:

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!e

d = { 1: 'a', 1: 'b', 2: 'c', 3: 'd' }
print(d)

subtle schoonerBOT Apr 5, 2025, 1:18 AM

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fiery depot !e ```python d = { 1: 'a', 1: 'b', 2: 'c', 3: 'd' } print(d) ```

:white_check_mark: Your 3.12 eval job has completed with return code 0.

{1: 'b', 2: 'c', 3: 'd'}

fiery depot Apr 5, 2025, 1:18 AM

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Notice there's only a single 1 key.

wraith void Apr 5, 2025, 1:19 AM

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thought it was number?

fiery depot Apr 5, 2025, 1:19 AM

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You thought what was a number?

wraith void Apr 5, 2025, 1:19 AM

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I thought .dict removed duplicate numbers

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like 1, 1, 2, 2, 3, 3, it would be 1, 2, 3, after

fiery depot Apr 5, 2025, 1:20 AM

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It did. Look at the printout #1357883763299848312 message

wraith void Apr 5, 2025, 1:20 AM

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fiery depot !e ```python d = { 1: 'a', 1: 'b', 2: 'c', 3: 'd' } print(d) ```

huh?

fiery depot Apr 5, 2025, 1:20 AM

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My code shows that d was created with two 1 keys, but only one remained after the dictionary was created.

wraith void Apr 5, 2025, 1:21 AM

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oh

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ohh

wraith void Apr 5, 2025, 1:21 AM

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wraith void 2. Find the most frequent appearing value in a dictionary, if there are ties, ju...

how would i do 2. then

wraith void Apr 5, 2025, 1:21 AM

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fiery depot !e ```python d = { 1: 'a', 1: 'b', 2: 'c', 3: 'd' } print(d) ```

wait where was the dictionary-

fiery depot Apr 5, 2025, 1:22 AM

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wraith void wait where was the dictionary-

The{ } and the part inside that

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!e

d = { 1: 'a' }
print(d, type(d))

subtle schoonerBOT Apr 5, 2025, 1:23 AM

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fiery depot !e ```python d = { 1: 'a' } print(d, type(d)) ```

:white_check_mark: Your 3.12 eval job has completed with return code 0.

{1: 'a'} <class 'dict'>

fiery depot Apr 5, 2025, 1:23 AM

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How have you been creating dictionaries?

wraith void Apr 5, 2025, 1:23 AM

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uh

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here is the thing

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i never did-

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d = { "john": '3.5', "jane": '4.0', "bob": '2.8', "mary": '4.0' }
print(d)

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thissss

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doesnt work

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i tried replacing everything

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AUGHHH

fiery depot Apr 5, 2025, 1:24 AM

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That code looks like it will execute fine

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!e

d = { "john": '3.5', "jane": '4.0', "bob": '2.8', "mary": '4.0' }
print(d)

subtle schoonerBOT Apr 5, 2025, 1:24 AM

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fiery depot !e ```python d = { "john": '3.5', "jane": '4.0', "bob": '2.8', "mary": '4.0' } p...

:white_check_mark: Your 3.12 eval job has completed with return code 0.

{'john': '3.5', 'jane': '4.0', 'bob': '2.8', 'mary': '4.0'}

fiery depot Apr 5, 2025, 1:24 AM

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It created a dictionary and stored it in d.

wraith void Apr 5, 2025, 1:24 AM

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how do i get it

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to output the 4.0

fiery depot Apr 5, 2025, 1:25 AM

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You'd need to determine which value is occurring the most frequently.

wraith void Apr 5, 2025, 1:25 AM

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tht would be 4.0

fiery depot Apr 5, 2025, 1:25 AM

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Which means you want to check every value in the dictionary.

wraith void Apr 5, 2025, 1:25 AM

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and how do i do tht?

fiery depot Apr 5, 2025, 1:25 AM

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wraith void tht would be 4.0

In this one case, ya

wraith void Apr 5, 2025, 1:25 AM

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(im a total beginer)

fiery depot Apr 5, 2025, 1:26 AM

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wraith void and how do i do tht?

You can use the values method on dictionaries to iterate over them:

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!e

d = { 1: 'a', 2: 'b', 3: 'c' }
for value in d.values():
    print(value)

subtle schoonerBOT Apr 5, 2025, 1:26 AM

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fiery depot !e ```python d = { 1: 'a', 2: 'b', 3: 'c' } for value in d.values(): print(v...

:white_check_mark: Your 3.12 eval job has completed with return code 0.

001 | a
002 | b
003 | c

fiery depot Apr 5, 2025, 1:27 AM

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Reverted to Javascript for a second there lmao

wraith void Apr 5, 2025, 1:27 AM

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fiery depot You can use the `values` method on dictionaries to iterate over them:

whats a values

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have not touched tht yet

fiery depot Apr 5, 2025, 1:27 AM

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The part after the : in the dictionary

wraith void Apr 5, 2025, 1:27 AM

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brb

fiery depot Apr 5, 2025, 1:28 AM

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You're likely going to need to take a step back and study dictionaries. You won't be able to use them for things like this without having a good undertanding of them.

static ravine Apr 5, 2025, 1:28 AM

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Dictionary are lists where you can access a item in the list with a key instead of a number.

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for example

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{"john": 3.5, "jane": 4.0, "bob": 2.8, "mary": 4.0}

fiery depot Apr 5, 2025, 1:29 AM

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Well, to be clear, they're not lists. They're comparable to lists in the sense that they can contain other things, and allow looking up specific elements by some key/index.

static ravine Apr 5, 2025, 1:29 AM

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^

static ravine Apr 5, 2025, 1:30 AM

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static ravine {"john": 3.5, "jane": 4.0, "bob": 2.8, "mary": 4.0}

in the first item john is the key and 3.5 is the value associated with the key

wraith void Apr 5, 2025, 1:30 AM

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erm idfk what a value is

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here is the thing

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if i havent learned it

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i cant use it

static ravine Apr 5, 2025, 1:31 AM

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yeah im trying to help you learn it

fiery depot Apr 5, 2025, 1:31 AM

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You can't use a dictionary without using "values" of the dictionary.

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If they are requiring you to use a dictionary, they're expecting you to understand values.

wraith void Apr 5, 2025, 1:32 AM

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oop

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tell tht to the github website my teach is using

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https://github.com/huangsam/ultimate-python/blob/main/ultimatepython/data_structures/defaultdict.py

GitHub

ultimate-python/ultimatepython/data_structures/defaultdict.py at ma...

Ultimate Python study guide :snake: :snake: :snake: - huangsam/ultimate-python

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if u click on the .dict py one

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there is no values

static ravine Apr 5, 2025, 1:33 AM

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!e

d = {"john": 3.5, "jane": 4.0, "bob": 2.8, "mary": 4.0}

print(d["john"])

subtle schoonerBOT Apr 5, 2025, 1:33 AM

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static ravine !e ```py d = {"john": 3.5, "jane": 4.0, "bob": 2.8, "mary": 4.0} print(d["john"...

:white_check_mark: Your 3.12 eval job has completed with return code 0.

3.5

fiery depot Apr 5, 2025, 1:33 AM

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wraith void https://github.com/huangsam/ultimate-python/blob/main/ultimatepython/data_struct...

https://github.com/huangsam/ultimate-python/blob/main/ultimatepython/data_structures/dict.py#L14

subtle schoonerBOT Apr 5, 2025, 1:33 AM

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ultimatepython/data_structures/dict.py line 14

# Let's create a dictionary with student keys and GPA values```

wraith void Apr 5, 2025, 1:34 AM

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fiery depot https://github.com/huangsam/ultimate-python/blob/main/ultimatepython/data_struct...

well the only problem with

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d = { "john": '3.5', "jane": '4.0', "bob": '2.8', "mary": '4.0' }
print(d)
for value in d.values():
print(value)

subtle schoonerBOT Apr 5, 2025, 1:34 AM

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Hey @wraith void!

Please edit your message to use a code block

```py
print('Hello, world!')
```

This will result in the following:

print('Hello, world!')```

wraith void Apr 5, 2025, 1:35 AM

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IT DOESNT DELETE THE STUPID 4.0

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AUGH IM GONNA CRASH OTU

static ravine Apr 5, 2025, 1:37 AM

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static ravine !e ```py d = {"john": 3.5, "jane": 4.0, "bob": 2.8, "mary": 4.0} print(d["john"...

You can access values in a dictionary using the key to the value, john is the key, d is the dictionary, d["john"] is the value of john.

d = {"john": 3.5, "jane": 4.0, "bob": 2.8, "mary": 4.0}

print(d["john"])

wraith void Apr 5, 2025, 1:37 AM

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wdym

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key?

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gives the wrong number

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wait now it doesnt

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i changed it to mary

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alr now

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can anyone help w/ the 3.

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Given a list of numbers, return a list with the order of numbers reversed (challenging)
hint: try to use the range function in a forloop, by counting the numbers in the list in reverse
then try to build a new list out of it
input: [1,2,3,4,5]
out: [5,4,3,2,1]

static ravine Apr 5, 2025, 1:41 AM

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!e

inputlist = [1,2,3,4,5]
newlist = [
for i in list[::-1]
  newlist.append(i)

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!e

inputlist = [1,2,3,4,5]
newlist = []
for i in list[::-1]
  newlist.append(i)

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bruh

wraith void Apr 5, 2025, 1:42 AM

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tf

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help

static ravine Apr 5, 2025, 1:42 AM

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!e

inputlist = [1,2,3,4,5]
newlist = []
for i in list[::-1]:
  newlist.append(i)

wraith void Apr 5, 2025, 1:42 AM

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help

static ravine Apr 5, 2025, 1:42 AM

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trying

wraith void Apr 5, 2025, 1:43 AM

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someone also gotta explain it

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btw

static ravine Apr 5, 2025, 1:43 AM

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!e

inputlist = [1,2,3,4,5]
newlist = []
for i in list[::-1]:
  newlist.append(i)
print(newlist)

wraith void Apr 5, 2025, 1:43 AM

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i aint looking for answers, im looking for explanations

static ravine Apr 5, 2025, 1:43 AM

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yeah ill explain

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one moment

spiral fulcrum Apr 5, 2025, 1:50 AM

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They asked to use range though

static ravine Apr 5, 2025, 1:50 AM

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Ok so one way to do it would be this:

inputlist = [1,2,3,4,5]
newlist = []

for i in reversed(inputlist):
  newlist.append(i)
print(newlist)

It iterates over the list reversed(inputlist) with a for loop. reversed() is a function that outputs a reversed version of a list, inside of the for loop it appends the current number to an empty list.

static ravine Apr 5, 2025, 1:51 AM

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spiral fulcrum They asked to use range though

oh true

wraith void Apr 5, 2025, 1:51 AM

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yea

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i was readin the code

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and was like

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where did the range code

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*go

spiral fulcrum Apr 5, 2025, 1:51 AM

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wraith void yea

Do you understand what range does?

wraith void Apr 5, 2025, 1:51 AM

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not at all

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im quite the forgetful one

spiral fulcrum Apr 5, 2025, 1:51 AM

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range is basically a shortcut for making a sequence of numbers

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range(5) is roughly the same as [0, 1, 2, 3, 4]

wraith void Apr 5, 2025, 1:52 AM

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ohh

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alr now

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Given a list of numbers, return a list with the order of numbers reversed (challenging)
hint: try to use the range function in a forloop, by counting the numbers in the list in reverse
then try to build a new list out of it
input: [1,2,3,4,5]
out: [5,4,3,2,1]

help/

spiral fulcrum Apr 5, 2025, 1:52 AM

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do you understand what indexing is?

wraith void Apr 5, 2025, 1:52 AM

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nope

spiral fulcrum Apr 5, 2025, 1:52 AM

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Ok, I'm going to use an example but with letters instead

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because I think the numbers actually make this more confusing

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letters = ['a', 'b', 'c', 'd', 'e']

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this is a list of letters

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"indexing" lets us access something at a specific position in the list

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so if I just wanted "c"

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I would do letters[2]

wraith void Apr 5, 2025, 1:53 AM

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mhm

spiral fulcrum Apr 5, 2025, 1:54 AM

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we start counting from 0 in indexing

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so "a" is 0

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"b" is 1

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etc

wraith void Apr 5, 2025, 1:54 AM

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ohh

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alr alr i see

spiral fulcrum Apr 5, 2025, 1:54 AM

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now there's some useful relationships to keep in mind

wraith void Apr 5, 2025, 1:54 AM

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wait

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whats reversed in python

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i js typed it in

spiral fulcrum Apr 5, 2025, 1:54 AM

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the last position in the list will always be "the length of the list minus one"

wraith void Apr 5, 2025, 1:54 AM

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and it turned blue

spiral fulcrum Apr 5, 2025, 1:54 AM

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it's a function

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(technically it's a class but I won't get into that now)

wraith void Apr 5, 2025, 1:54 AM

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tf does it do

spiral fulcrum Apr 5, 2025, 1:55 AM

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it reverses things

wraith void Apr 5, 2025, 1:55 AM

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its giving me exit code 0

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WAHAT

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IHQEIOQWE

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WAIT

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WAIT

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WHAT NOW

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I NEED THIS THING

spiral fulcrum Apr 5, 2025, 1:55 AM

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there's definitely easier ways to reverse things than using range

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but they asked you to use range

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learning programming isn't about just finding the easiest way to do things

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it's about learning how to think logically

wraith void Apr 5, 2025, 1:56 AM

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spiral fulcrum learning programming isn't about just finding the easiest way to do things

oof

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me being excited for liek 1 second

spiral fulcrum Apr 5, 2025, 1:56 AM

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spiral fulcrum the last position in the list will always be "the length of the list minus one"

does this make sense?

wraith void Apr 5, 2025, 1:57 AM

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yep

spiral fulcrum Apr 5, 2025, 1:58 AM

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ok

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so something nice about range, is if we give it a range based on the length of a list, we get the correct index count

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!e

letters = ['a', 'b', 'c', 'd', 'e']

for i in range(len(letters)):
    print(letters[i])

subtle schoonerBOT Apr 5, 2025, 1:58 AM

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spiral fulcrum !e ```py letters = ['a', 'b', 'c', 'd', 'e'] for i in range(len(letters)): ...

:white_check_mark: Your 3.12 eval job has completed with return code 0.

001 | a
002 | b
003 | c
004 | d
005 | e

spiral fulcrum Apr 5, 2025, 1:58 AM

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Does this make sense to you?

wraith void Apr 5, 2025, 1:59 AM

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yo wait

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i got it workin

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it js uh

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has a lot of commas in it

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result = reversed("1, 2, 3")
print(list(result))

spiral fulcrum Apr 5, 2025, 1:59 AM

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don't use reversed here

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if you'd like me to stop explaining, I can

wraith void Apr 5, 2025, 2:00 AM

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wait i gtg sleep now

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augh

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ill read it later

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!close

subtle schoonerBOT Apr 5, 2025, 2:00 AM

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Python help channel closed with !close

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#🔒 Can anyone help me with homework?