🔒 uh can anyone please explain why it keeps going through the if statement even tho it's false?

[honest lark]

can anyone please help me

[abstract ferry]

@honest lark

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[copper fjord]

oh this is the or gotcha

!or

[abstract ferry]

The or-gotcha

When checking if something is equal to one thing or another, you might think that this is possible:

# Incorrect...
if favorite_fruit == 'grapefruit' or 'lemon':
    print("That's a weird favorite fruit to have.")

While this makes sense in English, it may not behave the way you would expect. In Python, you should have complete instructions on both sides of the logical operator.

So, if you want to check if something is equal to one thing or another, there are two common ways:

# Like this...
if favorite_fruit == 'grapefruit' or favorite_fruit == 'lemon':
    print("That's a weird favorite fruit to have.")

# ...or like this.
if favorite_fruit in ('grapefruit', 'lemon'):
    print("That's a weird favorite fruit to have.")

[copper fjord]

or and and have special things they do in the background that a lot of people dont know

in this case its not the matter but read above

[honest lark]

oh dang

tysm i apperciate it

[copper fjord]

int(22) will always be True

you could also consider using range

!d range

[abstract ferry]

range

class range(stop)``````py

class range(start, stop[, step])```
The arguments to the range constructor must be integers (either built-in [`int`](https://docs.python.org/3/library/functions.html#int) or any object that implements the [`__index__()`](https://docs.python.org/3/reference/datamodel.html#object.__index__) special method). If the *step* argument is omitted, it defaults to `1`. If the *start* argument is omitted, it defaults to `0`. If *step* is zero, [`ValueError`](https://docs.python.org/3/library/exceptions.html#ValueError) is raised.

For a positive *step*, the contents of a range `r` are determined by the formula `r[i] = start + step*i` where `i >= 0` and `r[i] < stop`.

For a negative *step*, the contents of the range are still determined by the formula `r[i] = start + step*i`, but the constraints are `i >= 0` and `r[i] > stop`.

Similar names: django.range

[copper fjord]

!e
print(list(range(10)))

[abstract ferry]

:white_check_mark: Your 3.12 eval job has completed with return code 0.

[0, 1, 2, 3, 4, 5, 6, 7, 8, 9]

[honest lark]

i did put it as 22 on purpose

[copper fjord]

ok

[honest lark]

oh wait nvm i understand what u mean

[copper fjord]

# ...or like this.
if favorite_fruit in ('grapefruit', 'lemon'):
    print("That's a weird favorite fruit to have.")
``` this is what you'll want

[honest lark]

yes

tysm again

[copper fjord]

np!!!!

do !close or not

[honest lark]

lemme just do somethings and ill do it

[copper fjord]

ok

[honest lark]

!close

[abstract ferry]

Python help channel closed with !close

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