🔒 Help please!

[wicked grail]

I need to move the "b" to the right then back to the left in a zig zag pattern my code is not letting me do that

[white mantle]

@wicked grail

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[coarse jetty]

you could maybe check if t is divisible by 2 and base the spaces off of that
like
z
z
z
z

(idk if i understood what you want correctly)

[grave cypress]

I can see the issue but I would like to know whether you tried debugging using python breakpoint or just print statement?

Here you can learn on how to use breakpoint to debug python program in terminal: https://youtu.be/aZJnGOwzHtU?si=6rnG5ESextFnxHTE

[wicked grail]

uhhh sorry

bad explanation

need to look like this

[wicked grail]

i dont think its much use? its not that its an error its just how the answer is formatted

[grave cypress]

You do not debug only where there is an error, you use it to understand how your current program is behaving in real time.

Is it a homework or assignment you are trying to complete? Because it looks like so

[coarse jetty]

oh mb

[wicked grail]

yessir

[warm knot]

import time


def zigzag(char, distance, duration):
    if not isinstance(char, str):
        raise TypeError("char must be str")
    if len(char) != 1:
        raise ValueError("char must be of len 1")
    if distance < 0:
        raise ValueError("distance must be not negative")

    elapsed = 0
    i = 0
    switch = False

    while elapsed < duration:
        start = time.perf_counter()
        print(char.rjust(i + 1, " "))

        i = i - 1 if switch else i + 1

        if i == distance or i == 0:
            switch = not switch

        end = time.perf_counter()
        elapsed += end - start


zigzag("B", 10, 1)

[wicked grail]

the hell bro

[warm knot]

takes to long for the bot 😂

[wicked grail]

look i wish i could copy that

but i kinda need to understand it 😢

[grave cypress]

@warm knot it looks like an violation of rule no 8

[wicked grail]

@grave cypress do you see problem in my code?

[warm knot]

take a look at the rjust() method of strings. it is possible to do it without it and implement it yourself but this method makes it easy because it is like a ready made solution

so you need only to loop throught the amout of spaces

and stop the time

and switch increasing and decreasing

[wicked grail]

bro when did python get so complicated

[grave cypress]

Yes there is a problem. First you have break your problem into separate parts. First would be to print "B" with increased spaces, such as:

B
 B
  B
   B

Second, once you achieved this, then work on printing "B" in reversed order which will be opposite of the first step, like this:

    B
   B
  B
B

Then last, combine first and second step and repeat it as many times you want

[wicked grail]

wasn

oops

wasn't the last couple of lines suppoused to do that though?

[grave cypress]

No, first your code inside your loop is not correct. This is why I asked to break your problem into multiple steps because that will help you.

[warm knot]

python is not complicated it is extremly easy, you can not be more simple and easy than python. but that does not make creating a algorithm easier. think about an algorithm has nothing to do with the language. you could do it in pseudocode and implement it in any language

[white mantle]

Python help channel closed for inactivity

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