🔒 duplicated list

[smoky hedge]

list = [1,2,3,4,5,6,6,6]

un_duplicated_list = []

while list:
for i in list:
if list.count(i) > 1 and not un_duplicated_list:
un_duplicated_list.append(i)
list.remove(i)
print(list)

I am lost. I want to remove duplicated values from list and I want to keep what was duplicated in another list. like second list should be [6,6]

Please dont write completely different code just show me how can I fix on this.

ty

[clever cypress]

@smoky hedge

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[bright oracle]

any restrictions ?

[smoky hedge]

what do u mean

[bright oracle]

like in a school project where some u cant use sum()

anything like that going on here ?

[smoky hedge]

no but I am trying to understand why I made this code wrong

so I can fix it

[bright oracle]

and not un_duplicated_list:

this will only be true when un_duplicated_list is empty

which it will never be after first iteration since u appended to it

[smoky hedge]

list = [1,2,3,4,5,6,6,6]

un_duplicated_list = []

while list:
 for i in list:
    if list.count(i) > 1:
        un_duplicated_list.append(i)
        list.remove(i)
        print(list)

[clever cypress]

Hey @smoky hedge!

Please edit your message to use a code block

Add a py after the three backticks.

```py
print('Hello, world!')
```

This will result in the following:

print('Hello, world!')```

[smoky hedge]

didnt fix anyway

[bright oracle]

!e
list = [1,2,3,4,5,6,6,6]

un_duplicated_list = []

while list:
for i in list:
if list.count(i) > 1:
un_duplicated_list.append(i)
list.remove(i)
print(list)

[clever cypress]

:x: Your 3.12 eval job timed out or ran out of memory.

001 | [1, 2, 3, 4, 5, 6, 6]
002 | [1, 2, 3, 4, 5, 6]

[bright oracle]

infinite loop

[smoky hedge]

I know so ?

[bright oracle]

!e

list = [1,2,3,4,5,6,6,6]

un_duplicated_list = []

while list:
 print(un_duplicated_list)
 for i in list:
    if list.count(i) > 1:
        un_duplicated_list.append(i)
        list.remove(i)
        print(list)

[clever cypress]

:x: Your 3.12 eval job has completed with return code 143 (SIGTERM).

001 | []
002 | [1, 2, 3, 4, 5, 6, 6]
003 | [1, 2, 3, 4, 5, 6]
004 | [6, 6]
005 | [6, 6]
006 | [6, 6]
007 | [6, 6]
008 | [6, 6]
009 | [6, 6]
010 | [6, 6]
... (truncated - too many lines)

Full output: too long to upload

[ornate shore]

iterating thru a container (for i in list) and changing said container in the loop (list.remove(i)) is 90% of the time a bad idea

[bright oracle]

did i forget to say that

i did huh

oops

[smoky hedge]

yes I can reverse the list and make it like that according to chatgpt but I dont understand the logic

[ornate shore]

what does this message have anything to do with what I said

[smoky hedge]

Remove function will not make slips

[glossy ferry]

even though removing from a list while iterating through it in reverse might work, it gets confusing really quick

try doing it in separate loops first, and then when you get that right, take a shot at it again

[smoky hedge]

!close

[clever cypress]

Python help channel closed with !close

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