🔒 can someone explain to me what this is asking pls

[crimson nexus]

@quasi lynx

Python help channel opened

Remember to:

• Ask your Python question, not if you can ask or if there's an expert who can help.
• Show a code sample as text (rather than a screenshot) and the error message, if you've got one.
• Explain what you expect to happen and what actually happens.

:warning: Do not pip install anything that isn't related to your question, especially if asked to over DMs.

Closes after a period of inactivity, or when you send !close.

[vernal spindle]

What about it are you unsure of?

[quasi lynx]

I don't get the whole question, so basically it's a grid with different cells, and it's asking to calculate the neighbours living in one cell?

but if that's the case, why in the testing part, it gives us a full grid instead of just one cell

[vernal spindle]

each cell can be on or off

[quasi lynx]

what does it mean to be on/off tho

[vernal spindle]

given a cell, how many of its neighbours are on

if the value is 0, it is off. If the value is 1, it is on

basically, how many cell neighbours are 1s

[quasi lynx]

ok I kinda get it

but then what does this mean then

[vernal spindle]

since this is a grid, we're just scanning all the positions around the current position. We need to make sure the position we're looking at actually is on the grid

if 0, 0 is the top left corner, then our neighbour -1, 0 would not be valid

[quasi lynx]

wait so if that cell is on, then we're just adding the value of the cell to the living amount right

[quasi lynx]

but then in that case, x and y will the the whole grid right, not just the cell

[vernal spindle]

yes, we could just sum the neighbours to get the number of neighbours that are on

[vernal spindle]

your function has 3 parameters. The grid, and two coordinates

x is the grid, i and j are your coordinates

it's super confusing that they decided to use these parameter names though

[quasi lynx]

oooh ok I think I get it?

[vernal spindle]

the names are explained in the comment at least

[quasi lynx]

yh I'm just counfused mainly because of this sentence

[vernal spindle]

they give an example for checking the top left neighbour. You just need to complete the logic for the other 7 neighbours

they show you the logic for each neighbour

[quasi lynx]

ahhh ok

[vernal spindle]

let's say that my current position is 3, 3

2, 2 would be the top left

2, 3 would be top mid

2, 4 would be top right

etc

[quasi lynx]

oooh so basically

the number of neighbours living in one cell

is based on the neighbours living in the 8 cells around it?

[vernal spindle]

each cell only holds 1 value (on or off)

and every cell has 8 neighbours

(unless a boundary)

[quasi lynx]

oh so they're asking us to check the sum of the neighbours of one cell

[vernal spindle]

yes, which is "how many neighbours are on of any given cell"

[quasi lynx]

ooooooooh ok I get it

thank you very much

!close

[crimson nexus]

Python help channel closed

This help channel has been closed and it's no longer possible to send messages here. If your question wasn't answered, feel free to create a new post in #1035199133436354600. To maximize your chances of getting a response, check out this guide on asking good questions.