lofty dove
Write a program in Python language that receives as input a pair of coordinates (x, y) and prints on the screen "OUT" if the pair is outside the drawn rhombus (see Figure), on the contrary you print "IN" if the couple is inside. Handle cases where the coordinate pair falls on the perimeter of the square, by printing “PERIMETER”.
Tip: search on the web for the equation of the line passing through two points and use them to solve the problem
potent stagBOT
Write a program in Python language that receives as input a pair of coordinates ...
@lofty dove
Python help channel opened
austere lantern
oh this is so difficult
indigo igloo
isnt that "rhombus" like
just a 45 degree rotated square
shouldnt |x| + |y| <= 2 be enough
austere lantern
Ah yes. These are four very complex quadratic functions.
carmine hedge
they are not quadratic tho
the go in a straight line so they are linear
mellow bison
!e
def in_or_out(x, y):
a = abs(x) + abs(y)
if a < 2:
return 'IN'
elif a == 2:
return 'PERIMETER'
return 'OUT'
print(in_or_out(3, 4))
print(in_or_out(1, 1))
print(in_or_out(1, .5))
:white_check_mark: Your 3.12 eval job has completed with return code 0.
001 | OUT
002 | PERIMETER
003 | IN
what is abs
indigo igloo
!d abs
absolute value
like |x| in math
potent stagBOT
lofty dove
our teacher wants us to use the y = -+x +-2 (depending on the quadrant)
austere lantern
|x| + |y| <= 2 is incorrect
indigo igloo
`|x| + |y| <= 2` is incorrect
it isnt
slow prawn
Write a program in Python language that receives as input a pair of coordinates ...
Okay, so people went straight to smart solutions instead of explaining why, despite our rules saying one shouldn't give out direct solutions to homework...
So here's an explanation:
You know how in maths a function tells you when a point belongs to that function? If you put x in the function and calculate the result it will be equal to y.
If your y is lower than calculated f(x), it means your point is below the function. If it's higher, your point is above the function.
Here you can divide the area depending on whether x is positive or negative and same for y - 4 areas, 4 formulas. The areas are already marked with numbers in your picture.
(+ When x or y is 0, then you get an easy if check)
(+ When x or y is below -2 or above 2? Won't fall inside or on the edge, it's automatic out.)
For other (x,y), you grab a function for the area it's in, calculate f(x) and see how it compares to y.
Given this^, you should be now able to code the solution. There will be a lot of ifs.
The ifs can be compressed into the smart check people gave you with abs.
lofty dove
alright thanks everyone
austere lantern
wow genius
lofty dove
so the Y always has to be lower in every quadrant so that the point is inside the figure
like for every equation
no my bad it doesn’t
for the 3rd and 4th one the Y has to be bigger right?
austere lantern
oh my god what do you mean
austere lantern
sorry thanks
slow prawn
for the 3rd and 4th one the Y has to be bigger right?
Yep.
lofty dove
so in the first and second quadrant a if a point is inside the figure the Y has to be smaller than the equation (y<-x+2 and y< x+2)
and in the third and forth the Y has to be bigger than the equation in order to be inside the figure right?
so y> -x-2 and y> x-2
yes it works
i just need to make sure that if x== 0 or Y== 0 it gives me a result
austere lantern
yes yes
-2<x<0 and -x+2<y<x+2
or 0<x<2 and x-2<y<-x+2
idk
I'm not good at math
haha
lofty dove
x = float(input("Inserisci il valore di x: "))
y = float(input("Inserisci il valore di y: "))
#se il punto e nel primo quadrante
if (y > 0 and x > 0):
if y == -x+2:
print("Il punto è sul perimetro")
elif y < - x+2:
print("Il punto è all'interno")
else:
print("il punto e fuori dalla figura")
#se il punto e nel secondo quadrante
if (y > 0 and x < 0):
if y == x+2:
print("Il punto è sul perimetro")
elif y < x+2:
print("Il punto è all'interno")
else:
print("il punto e fuori dalla figura")
#se il punto e nel terzo quadrante
if (y < 0 and x < 0):
if y == -x-2:
print("Il punto è sul perimetro")
elif y > -x-2:
print("Il punto è all'interno")
else:
print("il punto e fuori dalla figura")
#se il punto e nel quarto quadrante
if (y < 0 and x > 0):
if y == x-2:
print("Il punto è sul perimetro")
elif y > x-2:
print("Il punto è all'interno")
else:
print("il punto è fuori dalla figura")
#se una delle due coordinate appartiene agli assi
if y == 0:
if x == abs(2):
print("Il punto e sul perimetro")
else:
print("Il punto è all'interno")
elif x == 0:
if y == abs(2):
print("Il punto è sul perimetro")
else:
print("Il punto è all'interno")
can someone check if the spaces are alright
wait nvm
i need to fix the if statements
tidal dagger
`|x| + |y| <= 2` is incorrect
its correct tho
austere lantern
beautiful
lofty dove
yeah you guys are right i could’ve written a way shorter code but i don’t care
most people in my class didn’t manage to do it
indigo igloo
both approaches are valid and teach different things
indigo igloo
your approach is what the prof asked for
lofty dove
yeah
thank you guys i appreciate everything
is there a way for me to send a python file from phone?
i did this program on my phone which was a pain in the ass
slow prawn
is there a way for me to send a python file from phone?
As in to discord? We don't allow code files in here because discord doesn't show preview for them (bot will automatically delete it). But there is https://paste.pythondiscord.com to share longer code
potent stagBOT
Python help channel closed