#🔒 Need help
stark harness
scarlet remnant
Further context I can reassure i added the input.txt thats needed into the same directory
ionic timber
if you want help with code, paste it -- all of it -- as text, not a screenshot
scarlet remnant
???
ionic timber
ah sorry
ionic timber
the screenshots are so much more attention-grabbing than the link 🙂
scarlet remnant
hey man shi happens just i beg for support
am i not
having the file
read properly?
scarlet remnant
rn gotchu
ionic timber
Oh I think I see it
scarlet remnant
ionic timber
you're calling "split" to break the line into fields.
and you're assuming the second field is a float.
But in fact, it's the person's last name.
scarlet remnant
So if im correct youre stating the i have it as split into break the lines but it's geniuely one of the last names?
Just clarifying right quick
ionic timber
ya
try this ```py
def calculate_score(scores, dd):
scores.remove(min(scores))
scores.remove(max(scores))
return round(sum(scores) / len(scores) * dd, 1)
def main() -> None:
with open("input.txt") as file:
print("Name DD Score")
for line in file:
given_name, surname, dd, *scores = line.strip().split()
print(f"{given_name=} {surname=} {dd=} {scores=}")
try:
dd = float(dd)
scores = list(map(float, scores))
except ValueError:
print("Error: Invalid data format in the input file.")
final_score = calculate_score(scores, dd)
print(given_name, surname, dd, final_score)
if name == "main":
main()
wfm
scarlet remnant
When I do that
It only outputs
bob smith
name
and not the rest
how would I include the others then?
i also did for the split area
ionic timber
I see this ```
main()
Name DD Score
given_name='Bob' surname='Smith' dd='1' scores=['7.5', '0.5', '8.5', '6.5', '2.5', '8.0', '9.5']
Bob Smith 1.0 6.6
given_name='Bob' surname='Smith' dd='5' scores=['0.5', '5.5', '5.5', '0.5', '9.5', '10.0', '6.5']
Bob Smith 5.0 27.5
given_name='Paul' surname='Phillips' dd='3' scores=['2.5', '2.0', '8.0', '9.0', '4.5', '7.0', '5.5']
Paul Phillips 3.0 16.5
given_name='Paul' surname='Phillips' dd='1' scores=['6.0', '1.5', '2.5', '4.0', '1.0', '10.0', '8.5']
Paul Phillips 1.0 4.5
given_name='Molly' surname='Brown' dd='1' scores=['9.0', '5.0', '1.5', '9.0', '4.0', '0.0', '8.0']
Molly Brown 1.0 5.5
given_name='Molly' surname='Brown' dd='2' scores=['4.5', '4.5', '0.5', '3.0', '1.5', '0.5', '1.0']
Molly Brown 2.0 4.2
dunno why you're seeing something different
scarlet remnant
Im a slow poke
had the other part added
that works
but I need the output
identical as this
for the autograder
to match it
ionic timber
oh well I dunno about that
scarlet remnant
I put "\t"
for it to work
but it only adds bob smith name
try to run this
and see what I mean @ionic timber
ionic timber
try this ```py
def calculate_score(scores, dd):
scores.remove(min(scores))
scores.remove(max(scores))
return round(sum(scores) / len(scores) * dd, 1)
def main() -> None:
with open("input.txt") as file:
print("Name DD Score")
for line in file:
name, dd, *scores = line.strip().split("\t")
try:
dd = float(dd)
scores = list(map(float, scores))
except ValueError as e:
print(f"{e} in {line=}.")
continue
final_score = calculate_score(scores, dd)
print(name, dd, final_score, sep="\t")
if name == "main":
main()
I get ```
uv run python nikto.py
Name DD Score
Bob Smith 1.0 6.6
Bob Smith 5.0 27.5
Paul Phillips 3.0 16.5
Paul Phillips 1.0 4.5
Molly Brown 1.0 5.5
Molly Brown 2.0 4.2
seems pretty close, anyway
ionic timber
Any remaining discrepancies are "an exercise for the reader"
scarlet remnant
The covnvnert has a problem
but that actually
is sm closer
than what I have 😭
scarlet remnant
Any remaining discrepancies are "an exercise for the reader"
LMAO
