🔒 Use and in an for loop?

[vocal galleon]

Hey this is a simplification of my code, but I basically want to do this:
I want the loop to give out 1 six times. Is there are way to do this? I'm a beginner and am building a simple object based text adventure and I'm using the for loop to find an item in the players and the locations inventory.
Any help is appreciated!

[steep osprey]

@vocal galleon

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[vocal galleon]

for i in [1,2,3] and [4,5,6]:
print ("1")

[tepid narwhal]

Why the and? Why not just make a 6-element list?

And why not use range?

[ripe sand]

[1,2,3] and [4,5,6] is equivalent to [4,5,6]. You can concat lists using + though: [1, 2, 3] + [4, 5, 6]

[vocal galleon]

Because in my game those are two different objects, I'm not able, or do not know how to combine both without breaking my code ':)

[vocal galleon]

I will try that, thank you!

[jovial idol]

!e

for i in range(6):
    print("1")

[steep osprey]

:white_check_mark: Your 3.12 eval job has completed with return code 0.

001 | 1
002 | 1
003 | 1
004 | 1
005 | 1
006 | 1

[jovial idol]

!e

# fuck this extremely shitty code
for i in [1, 2, 3] + [4, 5, 6]:
    print("1")

[steep osprey]

:white_check_mark: Your 3.12 eval job has completed with return code 0.

001 | 1
002 | 1
003 | 1
004 | 1
005 | 1
006 | 1

[vocal galleon]

So basically, my code is like this:
class X:
def innit(inventory):
self.inventory = [item1, item2]

class Y_:
def innit(inventory):
self.inventory = [item3, item4]

if item3 is either in y.inventory or x.inventory do ABC

that is why I'm trying tpo use:

for item.name in y.inventory or x.inventory:
print ("x")

I hope this is somewhat clear, my code is on my work laptop, so I cannot access that right now.

[jovial idol]

did you mean to print something from the inventory

cause you're not actually printing anything from the inventory

[vocal galleon]

Yes, so well this is working if I only use the for loop for one object, but once I try to go through both it stops working

[mellow fable]

You can use zip() function to go through both lists at once

!d zip

[steep osprey]

zip

zip(*iterables, strict=False)```
Iterate over several iterables in parallel, producing tuples with an item from each one.

Example:

```py
>>> for item in zip([1, 2, 3], ['sugar', 'spice', 'everything nice']):
...     print(item)
...
(1, 'sugar')
(2, 'spice')
(3, 'everything nice')
```...

[jovial idol]

you're not actually printing anything from the inventory

but use zip yeah

[vocal galleon]

Oh that sounds good!

Thank you!

[mellow fable]

Anytime

[vocal galleon]

Oh small question, I just saw that this is specifically for tuples, can you use it for lists aswell? I need to be able to add things to the lists.

[mellow fable]

You can transform tuples into lists I think

!e
print(list((1,2,3)))

[steep osprey]

:white_check_mark: Your 3.12 eval job has completed with return code 0.

[1, 2, 3]

[mellow fable]

(1,2,3) being a tuple

[vocal galleon]

Ah I got an idea on how to do this then, thank you again!

[mellow fable]

No problemo

Are you involving the position of the elements in the list when you print your final results?

[mellow fable]

Like you want to put the position of the element and the element of the second list?

[tepid narwhal]

Why are those two different classes?
Those should be the same class, like Player, then each player would be an instance of this class. (Think car factory: they make cars, the "Car" class is kind of general idea of a car, then each car is produced and is used differently)

Also, init, not innit

[mellow fable]

În that case you should use enumerate()

[tepid narwhal]

Also, I don't think zip is a good idea - it means going through both lists simultaneously, while OP specifically said she wanted to search for an item in all inventories...

[vocal galleon]

No those are irrelevant, I basically want to make a function where I say "If ItemX is in either the player inventory or in the loctation inventory then do Y (pick it up for example)"

[mighty quartz]

Tuples are immutable after they're made. You can modify a like (eg append). Otherwise, they're both sequences and you can iterate over them etc as expected.

[vocal galleon]

I wrote this out of my head, sorry for the wrong spelling! ':]
One Class is the player and the other class is the location

[mellow fable]

I think that you could make a variable in the class that would hold everyone's inventory all together and just check if the itemX is in that variable

[mighty quartz]

Ok. You need to write the condition differently. This:

if itemX in player_inv or location_inv:

means:

if (itemX in player_inv) or (location_inv):

You need:

if itemX in player_inv or itemX in location_inv:

[vocal galleon]

Tried that, but that caused an error aswell

[mighty quartz]

You'd need to show us the error.

[tepid narwhal]

You can just do a function with two loops. You want to check if item is in either, you don't need to do anything else with that item in that function, right? So just yes/no (True/False) whether the item is in either, right?

[vocal galleon]

Unable to do that right now, my laptop is at work. But I think the issue was that I tried to implement an error catch, where I said if itemX isn't in player.inventory or location.inventory then print("ERROR") and it printed Error way to often.

[mellow fable]

Heh probably due to that or statement

!or

[steep osprey]

The or-gotcha

When checking if something is equal to one thing or another, you might think that this is possible:

# Incorrect...
if favorite_fruit == 'grapefruit' or 'lemon':
    print("That's a weird favorite fruit to have.")

While this makes sense in English, it may not behave the way you would expect. In Python, you should have complete instructions on both sides of the logical operator.

So, if you want to check if something is equal to one thing or another, there are two common ways:

# Like this...
if favorite_fruit == 'grapefruit' or favorite_fruit == 'lemon':
    print("That's a weird favorite fruit to have.")

# ...or like this.
if favorite_fruit in ('grapefruit', 'lemon'):
    print("That's a weird favorite fruit to have.")

[mellow fable]

As Cameron said

[mighty quartz]

Probably your condition is wrong. For example, in my code above, this:

if (location_inv):

means "if location_inv is not empty". So always true most likely.

[vocal galleon]

Thank you for your help, I'm going to try some of these tips and if for whatever reason this doesn't work I'm comming back with the actual code ':D
Thank you!

[mellow fable]

Good luck on your journey

[mighty quartz]

In general, in python a collection is "truthy" if it is not empty and "falsey" if it is empty. Applies to lists, tuples, strings etc.

[vocal galleon]

Thank you, I started this at work and honestly it's a lot of fun!

[steep osprey]

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