🔒 Alternating for loop

[thin laurel]

Hi,

How do i make an alternating for loop?
for example when i try, it doesnt alternate, it just adds +1 in the beginning then does nothing.

for i in range(0, 10):
    i += 1
    print(i)

[lean nest]

@thin laurel

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[thin laurel]

for example i want it to print 2 4 6 8 10

[steel raven]

Well the problem above is that i gets reset to the next number in the sequence on each loop iteration. So your +1 happens, your print happens, then the value of i becomes whatever is next from range.

[thin laurel]

ah, so i need to create a new variable then

[steel raven]

Like, overtly:

for j in range(10):
    i = j
    i += 1
    print(i)

You can make the range step by 2 instead of 1 (the default).

You can make the loop body conditional:

if i%2== 0:
    print(i)

You can use another variable.

[thin laurel]

i will try my homework with the additional variable for now maybe it will work

[steel raven]

You can do the counting yourself:

i=0
while i < 10:
    i += 1
    print(i)
    i += 1 # this is like the next item from the for-loop

[thin laurel]

hmm

i didnt think of that

[steel raven]

What strategy you usedepends a bit on the larger problem.

[thin laurel]

i think the best way would be to do the counting myself tbh

i didnt even think of that for some reason

thanks!

[steel raven]

Don't forget that range() has an optional third step parameter. But yes, counting yourself gives complete control.

[thin laurel]

this is the final code, it works now with the manual counting:

def fizz_buzz(n: int) -> str:
    """
    Gets `n` int and checks if it is divisble by 3, 5 or both and prints Fizz, Buzz or Fizz Buzz respectively

    :param n: Int to be used to generate string
    :return: Returns string `Fizz`, `Buzz`, or `Fizz Buzz` and if `n`is not divisible by 3 nor 5, it will output the `n` and a error
    """
    if n % 3 == 0 and n % 5 == 0:
        return "Fizz Buzz"
    elif n % 3 == 0:
        return "Fizz"
    elif n % 5 == 0:
        return "Buzz"
    else:
        return str(n)

turns = 0
i = 1
while not turns == 101:
    print(i, "Comp A")
    print("computer says ",fizz_buzz(i))

    i += 1
    print(i, "P A")
    guess = input("Number, Fizz, Buzz or Fizz Buzz?: ")

    if guess == fizz_buzz(i):
        print("True")
        i += 1
        pass
    else:
        print("WRONG")
        break

!solved

[lean nest]

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