🔒 lists and while loops

[stone grotto]

Hello I have been having trouble with lists and while loops and can’t find a way to fix my code ai and YouTube were no help I have to hand this in for tomorrow so if any one has some tips on how I could fix this that would be awesome. I also am not allowed to use while true in the code

[fair dust]

@stone grotto

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[trim phoenix]

Can you share the code in text and maybe use a pastebin service?

[fair dust]

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[trim phoenix]

Reading a code screenshot is not good for the eyes

[trim phoenix]

also, what is the problem with it? Are you getting any error messages?

[trim phoenix]

So instead of a while loop, you can use recursive function call and inside a try/except

[stone grotto]

def get_nummin_num: int, prompt: str) -> int:
user_input = input (prompt)
while (user_ input.isdigit()) or (user_input < min_num) :
print('your entery was not valied try again')
else:
print(user_input)

I don’t know if I did that right but that’s my code

[trim phoenix]

Are you still allowed to use while?

[fair dust]

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[trim phoenix]

Use the code format

[stone grotto]

Yes just not while true for some reason

[trim phoenix]

wdym?

are you allowed to use while or not?

[stone grotto]

I am trying to get it to ask for a number input and if it is a str or below zero to repeat asking until the input is above 0

[trim phoenix]

yup

I get that

thanks for the explanation

its appreciated

[stone grotto]

No my prof said I have to use while but no while not

[trim phoenix]

ok...

[trim phoenix]

Then use while True

[stone grotto]

Ok I’ll try that is there anything else I need to fix. For when the input is a str

[trim phoenix]

Use a try/except

If its not an int, it throws a ValueError exception

[solar gulch]

Use a flag variable

flag = False
while not flag:
    inp = input()
    if inp.isditgit() and inp < min_number:
        flag = True

[trim phoenix]

His prof said no while not #1294209917863067679 message

[solar gulch]

The switch the flag to True

And mark it False if the input met req

[trim phoenix]

thats such a roundabout way of doing this. Could just leave it as while True and when the if conditions are met, use break

[solar gulch]

Point is, put the input() into the while loop and set it to run the first time

You put the input() line outside of the loop so it will not print the prompt for the user again because it is dead lock

It keep checking if input is ditgit and bigger than min number but user never have a chance to type it because there's no prompt to because the prompt is outside the loop

[stone grotto]

Where would I put the except value error for str then?

[trim phoenix]

try:
  int(input())
except ValueError:
  continue

[stone grotto]

Ok that all works but now it’s giving me an error that says. < not supported between an str and a int

[trim phoenix]

That would be a different exception

-except ValueError:
+except (ValueError, TypeError):

[stone grotto]

Where do I put that in the try part?

[trim phoenix]

Do you know how try/except works?

[stone grotto]

No I don’t think I’ve learnt that yet

[trim phoenix]

then you can skip try/except ig

Do what ThanhZ suggested

[stone grotto]

Ok thanks

[fair dust]

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