#๐Ÿ”’ new: trying to calculate 100 digits of sqrt(2) in under 50 bytes.

4 messages ยท Page 1 of 1 (latest)

celest void
#

current record:

t=n=10**999;exec("n=n//2+t*t//n;"*99);print(f"1.{n-t}")
round hollyBOT
#

@celest void

Python help channel opened

Remember to:

  • Ask your Python question, not if you can ask or if there's an expert who can help.
  • Show a code sample as text (rather than a screenshot) and the error message, if you've got one.
  • Explain what you expect to happen and what actually happens.

:warning: Do not pip install anything that isn't related to your question, especially if asked to over DMs.

round hollyBOT
#

@celest void

Python help channel closed

This help channel has been closed and it's no longer possible to send messages here. If your question wasn't answered, feel free to create a new post in #1035199133436354600. To maximize your chances of getting a response, check out this guide on asking good questions.