🔒 too many items to unpack

[hybrid field]

this is the error

Traceback (most recent call last):
  File "/piston/jobs/84134f09-a047-4c90-818b-68bf6363f496/file0.code", line 11, in <module>
    for j, w in func.items():
AttributeError: 'function' object has no attribute 'items'

this is the code

mylist = ['a','b','c']
def func():
    newlist = []
    otherlist = []
    for i in mylist:
        newlist.append(i)
    for x in range(1, len(newlist)):
        otherlist.append(x)
    return newlist, otherlist

for j, w in func():
    print(j, w)

[still grail]

@hybrid field

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[hybrid field]

what can i do for this to return the lists?

[prime marsh]

you are returning lists already?

where is the .lists() method call in that snippet?

[north shell]

Why are you calling function without parameters?

[hybrid field]

yes but it raises an error

[hybrid field]

shouldnt it work either way?

[little burrow]

what you want to achieve

[hybrid field]

return both lists

without raising an error

[prime marsh]

but that code already does it?

[little burrow]

it did

[hybrid field]

!e
mylist = ['a','b','c']
def func():
newlist = []
otherlist = []
for i in mylist:
newlist.append(i)
for x in range(1, len(newlist)):
otherlist.append(x)
return newlist, otherlist

for j, w in func():
print(j, w)

[north shell]

You should for sure pass mylist to the function. Is this full code?

[still grail]

:x: Your 3.12 eval job has completed with return code 1.

001 | Traceback (most recent call last):
002 |   File "/home/main.py", line 11, in <module>
003 |     for j, w in func():
004 |         ^^^^
005 | ValueError: too many values to unpack (expected 2)

[hybrid field]

alright

[little burrow]

!e

mylist = ['a','b','c']
def func():
    newlist = []
    otherlist = []
    for i in mylist:
        newlist.append(i)
    for x in range(1, len(newlist)):
        otherlist.append(x)
    return newlist, otherlist
j, w = func()
print(j)
print(w)

[prime marsh]

yeah, that

if you just want to get those two lists from func()

[little burrow]

you need unpack it

[hybrid field]

how

[little burrow]

check my above code

[hybrid field]

i want to do it in a for loop

like

for i x in func():
print(i,x)

[little burrow]

then use zip()

[north shell]

you can also use enumeration

[hybrid field]

thats what im trying to do

recreate it

[hybrid field]

where do i use it

[prime marsh]

ok, just what do you expect j and w to be on the first iteration of the loop?

so we're clear on what you're trying to accomplish here

[hybrid field]

a and 1 or vice versa

[north shell]

for count, ele in enumerate(my_list):
    print(count, ele)

[hybrid field]

i know

im trying to recreate enumerate myself

[north shell]

my_list = ['a','b','c']
cnt = 0

def func(some_list):
    for i in some_list:
        yield i

for i in func(my_list):
    print(i, cnt+1)
    cnt=cnt+1

?

you can add counter to the function and just add +1

[hybrid field]

whats yield?

[torpid bear]

yield is return but with the added option to resume execution

[north shell]

https://www.geeksforgeeks.org/use-yield-keyword-instead-return-keyword-python/

[hybrid field]

hm

im lost

wait

[north shell]

def func(some_list):
    cnt = 0
    for i in some_list:
        cnt = cnt+1
        yield i, cnt

for i, j in func(my_list):
    print(i, j)

I suppose this is what you want to achieve, right?

[hybrid field]

yea

[north shell]

so you should use yield

[hybrid field]

so if i do return it raises an error?

[north shell]

you do not return here, you yield

[hybrid field]

but with yield it doesnt?

[north shell]

there isn't really any possibility to achieve an error

[hybrid field]

!e

def func(some_list):
    cnt = 0
    for i in some_list:
        cnt = cnt+1
        yield i, cnt
my_list = ['a','b','c']
for i, j in func(my_list):
    print(i, j)

[still grail]

:white_check_mark: Your 3.12 eval job has completed with return code 0.

001 | a 1
002 | b 2
003 | c 3

[hybrid field]

okay

[north shell]

you kind of "return" (yield) two values and you can for loop using in func(my_list)

[hybrid field]

so how do i know when to use return and when to use yield?

[torpid bear]

you probably want to ignore yield for now

if you're creating pairs of n, x, where x is a value and n is an index

then what you have is *many* *pairs*

whenever you have the concept of *many* - the default structure for that is *list*

[hybrid field]

alright

there really is much to learn

[torpid bear]

[(0, a), (1, b), (2, c), ...]

[hybrid field]

thanks for the help!

[torpid bear]

you had this:

[0, 1, 2, 3]
[a, b, c, d]

which is slightly off, since what you have is pairs, not two separate "many's"

[hybrid field]

yea

!close

[still grail]

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