🔒 Index error dependent on an else statement

[lethal blaze]

Could someone explain why commenting out/removing the else condition causes the given index error?
Doesn't this function send all iterations to the same code after if statement isnt met anyways??

[green nebula]

@lethal blaze

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[full granite]

Print index.

[silk stump]

can you paste the code here as text please?

[lethal blaze]

def solution(input):
slist = []
newstring = list(input)
for index in range(0, len(input), 2):

    if index == (len(input)-1): 
        slist.append(input[-1] + "_")

    else:
        slist.append(input[index] + input[index+1])

return slist

[green nebula]

Hey @lethal blaze!

It looks like you're trying to paste code into this channel.

Discord has support for Markdown, which allows you to post code with full syntax highlighting. Please use these whenever you paste code, as this helps improve the legibility and makes it easier for us to help you.

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print('Hello, world!')```
You can **edit your original message** to correct your code block.

[full granite]

Basicly, the if is to prevent the line after the else running in a particular circumstance (right at the end). By removing it you run this line which is known to try to access things bey0ond the end of the array.

[silk stump]

!e

def solution(input):
    slist = []
    newstring = list(input)
    for index in range(0, len(input), 2):

        if index == (len(input)-1): 
            slist.append(input[-1] + "_")

        # else:
        #     slist.append(input[index] + input[index+1])

    return slist

print(solution('asdfadsf'))

[green nebula]

:white_check_mark: Your 3.12 eval job has completed with return code 0.

[]

[full granite]

Print index in the loop before the if-statement. Then thinks about what is being accessed when it explodes.

[silk stump]

I see no errors with the else commented out

[full granite]

The OP commented out only the else, not the whole clause.

[silk stump]

oh you're right, whoops

[lethal blaze]

In both cases it should still access the last even index then try to concat the next index?

The error to me is just odd because the index+1 is specifically considered outside the array and I'm understanding that to always be true whether the else is commented out or not. Since all iterations should pass through it after the if line?

[full granite]

The if is to see: am I right at the end of the array. if so, just access the end item and add an underscore. Otherwise (else) you can access the index and the next index.

This looks like homework, an exercise to make you think about dealing with indices near the end of the array etc.

[green nebula]

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