#🔒 I plan on sending my code to someone else. How can I make it work regardless of path?

14 messages · Page 1 of 1 (latest)

delicate yacht
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Currently in my code I am parsing a file in the same directory as my .py file. When I send it to someone else I assume that path will no longer work.

for line in open(r'C:\Users\User\project\Q1.dat'):

How can I modify this to look in the local directory instead of needing the full path?

short basaltBOT
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@delicate yacht

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royal heron
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there's a __file__ that gives you the location of the .py

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you can manipulate that to go to whichever directory I suppose

delicate yacht
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Q1path = Path(file).parent / "Q1.dat" seems to work

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many thanks

royal heron
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You can close the channel if you have no further questions

delicate yacht
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is it a /something? I'm somewhat new, sry 😛

royal heron
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it's !close

delicate yacht
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ty!

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!close

short basaltBOT
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