🔒 Password and user

[green bone]

Exactly what I want to know is why it's giving me an error
I'm trying to like set a password and if the user types anything wrong it would say Incorrect
I'm a beginner

[glass dirge]

@green bone

Python help channel opened

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[fallen shuttle]

damn idk what the bot command is

python uses indentation to determine how the code is supposed to run

[green bone]

What's indention

[fallen shuttle]

if a == 5:
  print('wow')
else:
  print('a is not 5 :(')

you can see the print statements have an extra tab (i.e. an extra indentation level) compared to the if/else parts

that tells python that they go inside the if/else branches

[green bone]

But I forgot how to

Like make It connected to

Under it

?

[rich abyss]

Yeah, that's how you make it connected, by putting the spaces on everything that you only want to run if the condition is true. In your case, that's the print("Correct")

Additionally, something you confused is the equality syntax

Instead of if Password: (13131), you want if Password == 13131:

Finally, this code probably won't work how you want it to, because you aren't getting any user input. Do you know how to do that?

@green bone ^

[green bone]

I'm reafing

But thanks

[rich abyss]

||py password = int(input("Try a password: ")) if password == 13131: print("Correct") else: print("Incorrect")||

[rich abyss]

This is what a working code could look like, if you want it for reference

[green bone]

Thanks so much

[green bone]

Sorry but how can I make a user too

[rich abyss]

The same way, ask for an input, check if it's the one you want and only let them keep going if that happens

Try it out, if you need help, feel free to ask

I'm not sure I'll be able to respond, but someone surely will

[glass dirge]

Python help channel closed

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