🔒 Why is there no output in the last option

[pine cedar]

a = enumerate('YouTube')
print(a) #outputs : <enumerate object at 0x000001D2F6327290>

print(list(a))
# outputs : [(0, 'Y'), (1, 'o'), (2, 'u'), (3, 'T'), (4, 'u'), (5, 'b'), (6, 'e')]

for j, item in list([(0, 'Y'), (1, 'o'), (2, 'u'), (3, 'T'), (4, 'u'), (5, 'b'), (6, 'e')]):
print(j, item)
outputs :
0 Y
1 o
2 u
3 T
4 u
5 b
6 e

for k, ktem in list(a):
print(k, ktem)

**NO OUTPUT
**

[verbal oar]

@pine cedar

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[hoary basalt]

enumerate objects are generators, once you use them they're gone

so when you have print(list(a)), this effectively consumes a, if you remove that print statement you'll find that your last for loop should work

[pine cedar]

i see

yes it worked ! thanks

[stray jackal]

*Iterator, not generator.

You can't send an enumerate object, for example.

[verbal oar]

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