🔒 Iterating over a list value in a dictionary list.

[sour tree]

Hey folks so I am making a tic tac toe game.

I was wondering, how I Iterate over each item in a list. I am using keys as values for the rows and then the index of the list is a column value.

gameboard = { 1: ["[ ]","[ ]", "[ ]"],
             2: ["[ ]","[ ]", "[ ]"],
             3: ["[ ]","[ ]", "[ ]"]
}

for key in gameboard:
    print(gameboard[key])```

I'm confused. How would I iterate over each invididual list item? 

I am aware also, that each item in the list is a string, how to I get the program to treat not iterate over each character  - but the string itself? 

Thanks in advance.

[left stump]

@sour tree

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[finite maple]

gameboard[key] is a list. You can just iterate that. The more idiomatic way would be to use values though if you don't actually need the key (or items if you do):

for row in gameboard.values():
    # Use row list

[sour tree]

thanks, so far I've done this much. I'm still getting confused.

[sour tree]

gameboard = {1: ["[ ]", "[ ]", "[ ]"],
             2: ["[ ]", "[X]", "[ ]"],
             3: ["[ ]", "[ ]", "[ ]"]
             }

for key in gameboard:
    print("".join(gameboard[key]))

for row in gameboard:
    for column in gameboard[row]:
        if column != "[ ]":
            print(f"That square is occupied at row {row}, ")```

[sour tree]

how would I print the column though?

[finite maple]

You can just print column.

[sour tree]

when I printed column, it prints "[X]" and not "2"

[crisp cosmos]

You would need to enumerate the columns then to get the column index

You might find it easier to separate out the representation of the gameboard with the actual data that you will be parsing as part of your game logic, lots of these kind of projects have something like a draw_board function that takes in the data and draws it however and just represents the underlying game data as ints or bools or whatever makes the most sense

[sour tree]

i figured it out, thanks

[sour tree]

for row in gameboard:
    for column in gameboard[row]:
        if column != "[ ]":
            print(f"That square is occupied at row {row}, column {gameboard[row].index(column)+1} ")

[rigid solar]

for row in gameboard:
    for i, column in enumerate(gameboard[row], start=1):
        if column != "[ ]":
            print(f"That square is occupied at row {row}, column {i} ")

your index(...) version won't work, if you got more than one [X] in a row, as it would always pick the first one

[left stump]

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