🔒 Stuck with python exercise

[ocean lynx]

Hey guys I've been stuck on this exercise for a while now could someone please help/guide me on how to solve this?

[open jasper]

@ocean lynx

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[elder sonnet]

sorry both pics don't make sense. 1 is about leap year, the other is about soup?

[ocean lynx]

hey thanks for pointing it out. just fixed it!

[prisma locust]

you're not checking any years beyond the initial input

[ocean lynx]

So would I have equate my year input to lyear and syear in the while true sections?

[prisma locust]

try increasing the year from the input onwards and for each year check if the year is leap or not

[ocean lynx]

Okay will give it a shot!

[river snow]

oof

ik a faster way

year = int(input("Year: "))
expected = year + 4 - (year % 4)
if expected % 100 == 0:
  print(f"The next leap year is: {expected + 4}")
else:
  print(f"The next leap year is: {expected}")

after you get a year

you will get the remainder of that year with 4

then take 4 subtract with that remainder and add that value to the current year value

because, if your year has remainder of n, you need 4 - n years to get to the next leap year (n > 0)

and in case the current year is a leap year, you just need to add 4 (4 - 0) to the current year

so the formula is current year + (4 - remainder of current year to 4)

break the brackets and you get current year + 4 - remainder of current year to 4

this works 100% im sure about that

if the result is divisible by 100, just add 4 more

@ocean lynx hope you understand this fast solution (only requires math and some conditions)

[open jasper]

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