proud forge
I have a dictionary that looks like this:
{key1: [value1, value2], key2: [value3, value4]}
where each key is added by a user and a value comes along with it.
last name is a variable containing the last added/modified key
i want to pop() the last element of the last modified key and i think it should look something like this:
key(last_name).values().pop(len(key(last_name).values()))
but of course it doesn't work because im not sure of the syntax, so i need a little help
lament ibexBOT
I have a dictionary that looks like this:
{key1: [value1, value2], key2: [value3...
@proud forge
Python help channel opened
lean mesa
What was wrong with the previous solution you were provided?
sand kernel
It is very easy.
last_name = 'key2'
# You can pop the last element of the list associated with 'key2' like this
user_dict[last_name].pop()
Hey @sand kernel!
proud forge
yeah but the issue is not resolved
lean mesa
You don't need another thread. The answer has not changed.
You just need to show the code, as asked previously 🙂
proud forge
and the code stays the same:
dict = {key1: [value1, value2], key2: [value3, value4]}
last_name = input()
print(dict[last_name].pop())
Here's the error:
TypeError: unbound method dict.pop() needs an argument
lean mesa
That's great, but your example code here isn't complete. There are variables involved which makes your code incomplete, the use of input() without providing the input, and the use of a native python type dict aliased to something else.
So... what is the actual code we can help you with?
I'm only arguing because I want to help. You're just restraining yourself and me being able to help you 🙂
proud forge
imo it useless for me to give you the whole code but here it is:
for url in urls:
get_browser()
name = input('Category: ')
if name == 'exit':
print(dict[last_name].pop())
save_data()
break
if name not in data:
data[name] = []
data[name].append(url)
last_name = name
a url opens in a tab, then u type a label for it and it stores it like:
{label : [url1]}
then i opens another url and if the label is the same it puts it as a second value in the array
as i said im overcomplicating it but you asked for it
the essential part is that if i type exit i want it to start from the url one before (which ive done) but then it makes duplicates so i want to remove the last stored url
urls is a [] and data is {}
lean mesa
print(dict[last_name].pop())
what is dict?
proud forge
the alternative of dictionary because dictionary doesnt exist
you cant dictionary[key].pop()
lean mesa
Have you assigned dict to anything?
lean mesa
If dict is the standard/default type, then this will not work.
proud forge
and what will?
lean mesa
You should be referencing the dictionary you want to access.
Like the example:
some_variable = {"key1": ["value1", "value2"], "key2": ["value3", "value4"]}
print(some_variable["key1"].pop())
ie reference the dictionary variable that holds the keys and values you want to access and pop.
You have provided incomplete code, but I assume this might be data variable.
lament ibexBOT
Python help channel closed