🔒 looping through nested dict in a list

[late perch]

Here i am trying to have an input of a course name, and whoever has that course in their info, pop up in the format person - identify, but it says that a 'set' object is not subscriptable, what does that mean?

people = []
info = input().split(':')

while len(info) > 1:
    for i in range(0, len(info), 3):
        name = info[i]
        identify = int(info[i+1])
        course = info[i+2]
        new_person = name, identify, course
        people.append({new_person})
    info = input().split(':')
else:
    for person in [person for person in people if info[0] in {person['course']}]:
        print(f'{person["name"]} - {person["identify"]}')

[idle iron]

@late perch

Python help channel opened

Remember to:

• Ask your Python question, not if you can ask or if there's an expert who can help.
• Show a code sample as text (rather than a screenshot) and the error message, if you've got one.
• Explain what you expect to happen and what actually happens.

:warning: Do not pip install anything that isn't related to your question, especially if asked to over DMs.

Closes after a period of inactivity, or when you send !close.

[late perch]

the code gets info in the format of
John:5622:fundamentals (example)
and splits it into name, id and course, then put on a list

and if we get a text that isnt split, then that's the course name we're supposed to find which students have and it should begin searching for any person with that course

example output

the error is in people if info[0] in {person['course']}]:

[still knoll]

the error is in people.append({new_person}), effectively, that is a set with 1 element

what did you mean by it?

[late perch]

i wanted to make it a dictionary of name, id and course, then to put onto a list

[still knoll]

if you want to make a dictionary you're going to need to well, construct it

[late perch]

isnt that what {} does?

[still knoll]

like {"name": name} whatever

[still knoll]

no, {something} is a set, {key: value} is a dict
(empty {} is a dict, though)

[late perch]

oh..

i have the key:value, 2ndvalue

i just havent formatted it correctly ig

[still knoll]

        new_person = name, identify, course
        people.append({new_person})

new_person is a tuple of 3 values, {new_person} is a set with that tuple, so yeah, you'll want to change how you define new_person, and remove the {} from the thing you append, as its going to already be a dict

[rough totem]

There are more is more than one problem tho

[still knoll]

dict(new_person) will error

[late perch]

soo make new_person = {}

and then add to it

then finally add to list

?

[still knoll]

you can make the whole dict with 1 literal

[late perch]

how?

[still knoll]

{"name": name, "age": age, ...}
im not sure why do you want to use it though here, as you are going to like, use it right away, and you're creating the data yourself, so you're just adding a level of indirection/complexity by doing that instead of a tuple/whatever

[late perch]

im just trying to learn how dicts work, so i am definitely open to suggestions/ideas

[still knoll]

thats fine then

[late perch]

but everything has to be inside of the dict stuff :D

[still knoll]

if you want to define a structure that like just stores a bunch of specific data - you can use classes (dataclasses) for this
but learning dicts is still good, they're really useful, maybe not in this case but overall

[late perch]

how exactly do i make that?

ah i have an idea

[still knoll]

make what?

[late perch]

give me a second

[rough totem]

Yo my bad, there is two ways of doing it actually

people.append(dict(zip(['name', 'identify', 'course'], new_person)))

# This will create a dictionary with the keys name, identify, and course, and the corresponding values from the new_person tuple.

# Alternatively, you can use a dictionary literal to create the dictionary, like this:

people.append({'name': name, 'identify': identify, 'course': course})

#Either of these approaches should fix the error and allow you to access the elements of the dictionary using the square bracket notation.

[late perch]

        name = info[i]
        identify = int(info[i+1])
        course = info[i+2]
        new_person = {'name': name, 'identify': identify, 'course': course}
        people.append(new_person)```

oh just like you made it now

perfect

[rough totem]

Nice

👍

[late perch]

could save a line on new_person also

thanks a lot, both of you!

the info with split : is just the exercise

thats how they input it

Peter:123:fundamentals

cheers! works perfectly

[rough totem]

Np, any question just dm or ask here 🙂

[late perch]

but the reader seems to dislike something

gives me an error that pycharm wouldnt give

[rough totem]

Send it pls

[late perch]

nevermind

i posted the solution to a wrong exercise

been programming like 8 hours today i am halfway braindead

[rough totem]

Xd

What course you doing?

[late perch]

hmm..

this just seems wrong on their side

[late perch]

its one available in bulgaria only, for now, i think

Softuni

but its the best one here

[rough totem]

Can you pass me the full problem?

[late perch]

oh i ignored the snake case part

right..

[rough totem]

xD

Fixed?

[late perch]

yup! easy solution

just replace '_' with ' '

[rough totem]

Noice

[late perch]

thanks alot, once again! :D

!close

[idle iron]

Python help channel closed

This help channel has been closed and it's no longer possible to send messages here. If your question wasn't answered, feel free to create a new post in #1035199133436354600. To maximize your chances of getting a response, check out this guide on asking good questions.