🔒 What do leetcode want me to return???

[wind torrent]

This is problem 26 in Leetcode.
When I return the result as an integer, they said the expected output as an array.
When I return the result as an array, they said it's TypeError because I need to return an integer.
My code with return statement as integer: https://paste.pythondiscord.com/DTFA
My code with return statement as array: https://paste.pythondiscord.com/O2KA

[woeful apex]

@wind torrent

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[limber oxide]

this is the problem right? https://leetcode.com/problems/remove-duplicates-from-sorted-array/description/
it looks to me like it wants you to modify the list, but to also return a separate integer from the function

[wind torrent]

yeah?

i also modified the list btw

nums = [min(nums) + i for i in range(counter)]

plus i checked in other interpreter alr

[wind torrent]

its the problem

[limber oxide]

when the code's being ran and tested, leetcode is keeping hold of that nums list, and is checking its values after the function runs, because they're expecting you to change that list
but when you do nums = whatever, you aren't editing that original list, you're instead actually creating a brand new list

[wind torrent]

???????

oh okay

lemme try again 🙂

i cant use list comprehension 😦

[limber oxide]

so long as at no point you do nums =, then yeah, it counts 😄
(you can also do nums[i] =, or call any methods, but just never specifically nums =)

[wind torrent]

then why in the original code, it says my output is [1, 1]?

wow it got me wrong again. its example consists of consecutive numbers!

[limber oxide]

see what the question says for example 1, which is the same as that input

you got given an input list of [1, 1, 2], and leetcode expected for that list to be changed to start with [1, 2], basically

[wind torrent]

yeah so i see 1 and 2

i thought that only return consecutive outputs

class Solution:
    def removeDuplicates(self, nums: List[int]) -> int:
        new = list(set(nums))
        new.sort()
        counter = 1
        pointer = 0
        expected_number = min(nums)
        while expected_number in new:
            counter += 1
            pointer += 1
            expected_number = new[pointer]

        # Clears the list (setup)
        for i in range(len(nums)):
            nums.pop(0)

        # Add the values
        for i in range(counter):
            nums.append(new[i])

        return counter

i hope this works

oh nvm

class Solution:
    def removeDuplicates(self, nums: List[int]) -> int:
        new = list(set(nums))
        new.sort()

        # Clears the list (setup)
        for i in range(len(nums)):
            nums.pop(0)

        # Add the values
        for i in range(len(new)):
            nums.append(new[i])

        return len(new)

this works just like you said

thanks 😄

!close

[woeful apex]

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