🔒 How to clean up timeout-ed subprocess.run process?

[native lodge]

I have the following snippet to run a task and terminate it if a timeout is exceeded.

    try:
        process = subprocess.run(
            [
                node_path,
                render_puppeteer_path,
                task.url,
                tempdir,
            ],
            capture_output=True,
            check=False,
            text=True,
            timeout=TIMEOUT,
        )
    except subprocess.TimeoutExpired:
        delete_dir(tempdir)
        return Box(
            success=False,
            task=task,
         data=dict(reason='timeout'),
        )

My problem is that children of the running process is not cleared up after a timeout. How can I modify it such that they are cleared up?

[digital field]

@native lodge

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[wanton marlin]

Is this nodejs? Probably you want to do the timeout in JavaScript

Otherwise you can kill the extra subprocesses with psutil

[native lodge]

Yes, it's a node script starting Puppeteer which starts Chrome. My problem is that the Chrome processes stay running after the Python timeout.

How can I kill the subprocesses? Do I have a process id or similar in the except subprocess.TimeoutExpired block?

[wanton marlin]

The processes should end up as children of your current python process

Eg psutil.Process().children()

[native lodge]

somehow it doesn't end up there

in pstree they are in a higher level

[wanton marlin]

Where do they end up?

Oh it goes to init

You might have to fix this in the node process

[native lodge]

Yes, it goes to init. I'll fix it with a pkill.

[digital field]

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