🔒 help with dictionaries

[ember knot]

@rustic wasp

Python help channel opened

Remember to:

• Ask your Python question, not if you can ask or if there's an expert who can help.
• Show a code sample as text (rather than a screenshot) and the error message, if you've got one.
• Explain what you expect to happen and what actually happens.

:warning: Do not pip install anything that isn't related to your question, especially if asked to over DMs.

Closes after a period of inactivity, or when you send !close.

[south mauve]

!e

dic = {}

key = 'a'
val = 3

if dic.get(key):
    print("Key exists")
else:
    print("Added to dic")
    dic[key] = val

print(dic)

[ember knot]

@south mauve :white_check_mark: Your 3.12 eval job has completed with return code 0.

001 | Added to dic
002 | {'a': 3}

[rustic wasp]

ooh so you are checking if a key exists and if it doesn't then you creat it

[south mauve]

yes

[rustic wasp]

and if it is already created then you add an element

[south mauve]

perhaps I should show a more extensive example

!e

dic = {}

key = 'a'
val = 3

if dic.get(key):
    print("Key exists")
else:
    print("Added to dic")
    dic[key] = val

# Now, the key has been created

if dic.get(key):
    print("The key finally exists")
    dic[key] = dic[key] + 1
else:
    print("The key doesn't exist...")

print(dic)

[ember knot]

@south mauve :white_check_mark: Your 3.12 eval job has completed with return code 0.

001 | Added to dic
002 | The key finally exists
003 | {'a': 4}

[south mauve]

hope that's a bit more helpful

[rustic wasp]

what i ve understood is i check if my key (1,1) exists if it does than i add my value. if it doesn't i creat (1,1) and add my value to it

[south mauve]

It checks if the key exists, if it does you can add to the value
If it doesn't, you can create the key with a default value

[rustic wasp]

ok thanks a lot

[rustic wasp]

i get this error msg: 'list' object has no attribute 'get'

never mind

[south mauve]

mk

[rustic wasp]

xd

i checked in a list if i had a key😂

hmmm i seem to have a problem

if L.get(ligne+1,s+1):
[ligne+1,s+1].append(carte[ligne][e])
else:
L[ligne+1,s+1]=carte[ligne][e]

i wrote this with the key that i want to check if it exists beeing: L[ligne+1,s+1]

but the console feeds bacl {} so it did not creat any key

[south mauve]

you'll have to put it in another pair of parens

if L.get((ligne+1, s+1)):

[rustic wasp]

ooooh

sorry for beeing this noobie

[south mauve]

it's alright, this server is to help people learn python :)

[rustic wasp]

how do i add a list to a key in dictionary python do i use append or is that only for lists

and can a key have multiple lists?

[south mauve]

wdym

[rustic wasp]

like (1, 3): [4, 'purple'],[3,'red']

[south mauve]

sure, that exists

!e

key = (1, 3)
value = ([4, 'purple'], [3, 'red'])

dic = {}
dic[key] = value

print(dic)

[ember knot]

@south mauve :white_check_mark: Your 3.12 eval job has completed with return code 0.

{(1, 3): ([4, 'purple'], [3, 'red'])}

[south mauve]

just like any other value

note the parens here: ([4, 'purple'], [3, 'red']) which show that both of these lists are the value of that key

[rustic wasp]

i see

but here in your exemple : value = ([4, 'purple'], [3, 'red']) value is already equal to all this whereas i have two values : value 1= [4, 'purple'] and value 2 = [3, 'red'] that i want to add to one single key

to make (1, 3): ([4, 'purple'], [3, 'red'])

[south mauve]

are you saying you want to make it so that dic[1] gives [4, 'purple']

[rustic wasp]

not really

i want to add another value to my dic

but in you example value is 2 elements already

[south mauve]

ok so you have a dic, it has 2 key-value pairs, you want to join them?

[rustic wasp]

i have a dic with 1 key 1 pair inside and i want to add another pair to that key

[south mauve]

ah

ok

Not sure if you can edit the key...

give me a second

!e though I would say it sounds like you're getting tunnel vision.

to_add_key = 3
to_add_value = [3, 'red']
key_to_add_to = 1

dic = {1: [4, 'purple']}
print("before: ", dic)

prev_val = dic.pop(key_to_add_to)

dic[(key_to_add_to, to_add_key)] = prev_val, to_add_value

print("after: ", dic)

[ember knot]

@south mauve :white_check_mark: Your 3.12 eval job has completed with return code 0.

001 | before:  {1: [4, 'purple']}
002 | after:  {(1, 3): ([4, 'purple'], [3, 'red'])}

[south mauve]

whatever you hope to achieve with this, there's probably a better (and less complicated) way of achieving it

[rustic wasp]

should i explain what i m trying to do?

[south mauve]

go for it, but I have to run soon

it's almost 4am

[rustic wasp]

oh shoot

[south mauve]

I'll help if I can, but if I can't, I'm sure someone else will

[rustic wasp]

the aim is to creat a game where you go from 1 colored number to another

its on a board

and the only way you can move is vertically and horizontally and on either a same colored or same numbered piece

i m trying to find every possible move on the board

[2, 'bleu'], [6, 'jaune'], [5, 'rose'], [4, 'rose'], [1, 'blanc'], [4, 'vert']

# [4, 'bleu'], [6, 'blanc'], [6, 'rose'], [3, 'vert'], [5, 'blanc'], [5, 'vert']

[3, 'bleu'], [4, 'jaune'], [1, 'bleu'], [2, 'rose'], [4, 'blanc'], [1, 'rose']

[5, 'rouge'], [6, 'vert'], [1, 'rouge'], [4, 'rouge'], [5, 'jaune'], [5, 'bleu']

[2, 'vert'], [2, 'blanc'], [1, 'jaune'], [3, 'rouge'], [2, 'jaune'], [6, 'bleu']

# [3, 'blanc'], [4, 'vert'], [3, 'jaune'], [2, 'rouge'], [6, 'rouge'], [3, 'rose']

here for example you can go from [5, 'rose'] to [4, 'rose'] because they have rose in common

but you can also move from [5, 'rose'] to [6, 'rose'] because they are in the same collumn

so i need to make a dictionnary where all the combos are possible

[tame sail]

Why a dictionary?

[rustic wasp]

cuz then i have to make the fastes path between one random to another

[south mauve]

there's algorithms for that

[rustic wasp]

and by having a dic of all the combos i can find the path more easly?

i could use something else than a dic but then i have to change my code for the quickest path

[south mauve]

though I am slightly confused by your board, that might just be because of how tired I am

I should probably go

[rustic wasp]

the board form the actual game is this

so in my dic i want to have (1,1) the first square on the top left : ([6,'pink'], [2,'pink],[4,pink],[5,'red])

all the possible moves from 5 pink

on python my board is a list with in it a list for each line containing in them another list with the number and the color in it

like this (its in french) : carte=[[[2, 'bleu'],[6, 'jaune'],[5, 'rose'],[4, 'rose'], [1, 'blanc'],[4, 'vert']],[[4, 'bleu'], [6, 'blanc'], [6, 'rose'], [3, 'vert'], [5, 'blanc'], [5, 'vert']],[[3, 'bleu'], [4, 'jaune'], [1, 'bleu'], [2, 'rose'], [4, 'blanc'], [1, 'rose']],[[5, 'rouge'], [6, 'vert'], [1, 'rouge'], [4, 'rouge'], [5, 'jaune'], [5, 'bleu']],[[2, 'vert'], [2, 'blanc'], [1, 'jaune'], [3, 'rouge'], [2, 'jaune'], [6, 'bleu']],[[3, 'blanc'], [4, 'vert'], [3, 'jaune'], [2, 'rouge'], [6, 'rouge'], [3, 'rose']]]

[rustic wasp]

note that the board is randomly generated so the numbers and colours here dont match the image

[tame sail]

how do i add a value to a key but if this key does not existe i have to create it

you can use a default dict for this

!e

from collections import defaultdict

moves = defaultdict(list)

for a in range(5):
    for b in range(5):
        moves[a].append(b)

print(moves)```

[ember knot]

@tame sail :white_check_mark: Your 3.12 eval job has completed with return code 0.

defaultdict(<class 'list'>, {0: [0, 1, 2, 3, 4], 1: [0, 1, 2, 3, 4], 2: [0, 1, 2, 3, 4], 3: [0, 1, 2, 3, 4], 4: [0, 1, 2, 3, 4]})

[rustic wasp]

what i have done rn is this (its made by me i dont have a lot of experiance): L={}
for ligne in range (0,6):
for s in range (0,6):
for e in range (0,6):
for i in range (0,2):
if carte[ligne][s][i] == carte[ligne][e][i] and e!=s:
if L.get((ligne+1,s+1)):
[(ligne+1,s+1)].append(carte[ligne][e])
else:
L[(ligne+1,s+1)]=carte[ligne][e]
C={}
for colonne in range (0,6):
for compare in range (0,6):
for ligne in range (0,6):
for i in range (0,2):
if carte[ligne][colonne][i] == carte[compare][colonne][i] and ligne!= compare:
C[ligne+1,colonne+1]=carte[compare][colonne]

first part is to find where i can move in the ligne second one is in the column

[tame sail]

it's a start

[rustic wasp]

xd it is what it is

[rustic wasp]

could you help me fix it ?

[tame sail]

I can stay for a bit but I have to leave soon

what part is broken?

[rustic wasp]

if carte[ligne][s][i] == carte[ligne][e][i] and e!=s:
if L.get((ligne+1,s+1)):
[(ligne+1,s+1)].append(carte[ligne][e])
else:
L[(ligne+1,s+1)]=carte[ligne][e]

[ember knot]

Hey @rustic wasp!

It looks like you're trying to paste code into this channel.

Discord has support for Markdown, which allows you to post code with full syntax highlighting. Please use these whenever you paste code, as this helps improve the legibility and makes it easier for us to help you.

To do this, use the following method:
```py
print('Hello, world!')
```

This will result in the following:

print('Hello, world!')```
You can **edit your original message** to correct your code block.

[rustic wasp]

i can t manage to have a dic with multiple values in my keys

[tame sail]

why do you use 1 based indexing that's making it hard on yourself

[rustic wasp]

1 based indexing?

[tame sail]

you are adding +1 to your indexes

[rustic wasp]

hmm what should i do?

[tame sail]

L[(ligne+1,s+1)]=carte[ligne][e]
You need an extra [] around the carte[ligne][e]

[rustic wasp]

hmm okkk let me try

[tame sail]

I would recommend the defaultdict solution I talked about earlier instead though

[rustic wasp]

!e

[ember knot]

Missing required argument

code

[tame sail]

[(ligne+1,s+1)].append(carte[ligne][e])
also you forgot to put the L in front of here

[rustic wasp]

oh

[tame sail]

It's easy to miss if you use non descriptive 1 letter variable names like that

[rustic wasp]

xddd yeah

[rustic wasp]

now with this code carte=[[[2, 'bleu'],[6, 'jaune'],[5, 'rose'],[4, 'rose'], [1, 'blanc'],[4, 'vert']],[[4, 'bleu'], [6, 'blanc'], [6, 'rose'], [3, 'vert'], [5, 'blanc'], [5, 'vert']],[[3, 'bleu'], [4, 'jaune'], [1, 'bleu'], [2, 'rose'], [4, 'blanc'], [1, 'rose']],[[5, 'rouge'], [6, 'vert'], [1, 'rouge'], [4, 'rouge'], [5, 'jaune'], [5, 'bleu']],[[2, 'vert'], [2, 'blanc'], [1, 'jaune'], [3, 'rouge'], [2, 'jaune'], [6, 'bleu']],[[3, 'blanc'], [4, 'vert'], [3, 'jaune'], [2, 'rouge'], [6, 'rouge'], [3, 'rose']]]

dic_Voisin={}
a={}
for ligne in range (0,6):
for case in range (0,6):
for voisin in range (0,6):
for i in range (0,2):
if carte[ligne][case][i] == carte[ligne][voisin][i] and voisin!=case:
if dic_Voisin.get((ligne,case)):
dic_Voisin[(ligne,case)].append(carte[ligne][voisin])
else:
dic_Voisin[(ligne,case)]=[carte[ligne][voisin]]
if carte[voisin][ligne][i] == carte[case][ligne][i] and voisin!= case:

                    if a.get((ligne,case)):
                        a[(ligne,case)].append(carte[voisin][ligne])
                    else:
                        a[(ligne,case)]=[carte[voisin][ligne]]

when i have 2 seperate dico it works

but when i put them in one it doesn t work anymore

[wise furnace]

!code You should format your code when you paste it here otherwise the indentation gets weird

[ember knot]

Formatting code on Discord

Here's how to format Python code on Discord:

```py
print('Hello world!')
```

These are backticks, not quotes. Check this out if you can't find the backtick key.

For long code samples, you can use our pastebin.

[rustic wasp]

ok

!code carte=[[[2, 'bleu'],[6, 'jaune'],[5, 'rose'],[4, 'rose'], [1, 'blanc'],[4, 'vert']],[[4, 'bleu'], [6, 'blanc'], [6, 'rose'], [3, 'vert'], [5, 'blanc'], [5, 'vert']],[[3, 'bleu'], [4, 'jaune'], [1, 'bleu'], [2, 'rose'], [4, 'blanc'], [1, 'rose']],[[5, 'rouge'], [6, 'vert'], [1, 'rouge'], [4, 'rouge'], [5, 'jaune'], [5, 'bleu']],[[2, 'vert'], [2, 'blanc'], [1, 'jaune'], [3, 'rouge'], [2, 'jaune'], [6, 'bleu']],[[3, 'blanc'], [4, 'vert'], [3, 'jaune'], [2, 'rouge'], [6, 'rouge'], [3, 'rose']]]

dic_Voisin={}
a={}
for ligne in range (0,6):
for case in range (0,6):
for voisin in range (0,6):
for i in range (0,2):
if carte[ligne][case][i] == carte[ligne][voisin][i] and voisin!=case:
if dic_Voisin.get((ligne,case)):
dic_Voisin[(ligne,case)].append(carte[ligne][voisin])
else:
dic_Voisin[(ligne,case)]=[carte[ligne][voisin]]
if carte[voisin][ligne][i] == carte[case][ligne][i] and voisin!= case:

                    if a.get((ligne,case)):
                        a[(ligne,case)].append(carte[voisin][ligne])
                    else:
                        a[(ligne,case)]=[carte[voisin][ligne]]

!e

[ember knot]

Missing required argument

code

[rustic wasp]

/home

!e carte=[[[2, 'bleu'],[6, 'jaune'],[5, 'rose'],[4, 'rose'], [1, 'blanc'],[4, 'vert']],[[4, 'bleu'], [6, 'blanc'], [6, 'rose'], [3, 'vert'], [5, 'blanc'], [5, 'vert']],[[3, 'bleu'], [4, 'jaune'], [1, 'bleu'], [2, 'rose'], [4, 'blanc'], [1, 'rose']],[[5, 'rouge'], [6, 'vert'], [1, 'rouge'], [4, 'rouge'], [5, 'jaune'], [5, 'bleu']],[[2, 'vert'], [2, 'blanc'], [1, 'jaune'], [3, 'rouge'], [2, 'jaune'], [6, 'bleu']],[[3, 'blanc'], [4, 'vert'], [3, 'jaune'], [2, 'rouge'], [6, 'rouge'], [3, 'rose']]]

dic_Voisin={}
a={}
for ligne in range (0,6):
for case in range (0,6):
for voisin in range (0,6):
for i in range (0,2):
if carte[ligne][case][i] == carte[ligne][voisin][i] and voisin!=case:
if dic_Voisin.get((ligne,case)):
dic_Voisin[(ligne,case)].append(carte[ligne][voisin])
else:
dic_Voisin[(ligne,case)]=[carte[ligne][voisin]]
if carte[voisin][ligne][i] == carte[case][ligne][i] and voisin!= case:

                    if a.get((ligne,case)):
                        a[(ligne,case)].append(carte[voisin][ligne])
                    else:
                        a[(ligne,case)]=[carte[voisin][ligne]]

[ember knot]

@rustic wasp :warning: Your 3.12 eval job has completed with return code 0.

[No output]

[rustic wasp]

hmmm

[rustic wasp]

how do you show whats inside a dictionnary?

[wise furnace]

You format code by surrounding it with ```py on top and ``` on the bottom of it.

typing !code <your code> doesn't do anything except make the bot tell you how to format code.

backticks, not apostrophe

If you have a US qwerty keyboard it's probably to the left of the 1 key on top.

[ember knot]

Hey @rustic wasp!

It looks like you pasted Python code without syntax highlighting.

Please use syntax highlighting to improve the legibility of your code and make it easier for us to help you.

To do this, use the following method:
```py
print('Hello, world!')
```

This will result in the following:

print('Hello, world!')```
You can **edit your original message** to correct your code block.

[rustic wasp]

is this better?

'''py '''

carte=[[[2, 'bleu'],[6, 'jaune'],[5, 'rose'],[4, 'rose'], [1, 'blanc'],[4, 'vert']],[[4, 'bleu'], [6, 'blanc'], [6, 'rose'], [3, 'vert'], [5, 'blanc'], [5, 'vert']],[[3, 'bleu'], [4, 'jaune'], [1, 'bleu'], [2, 'rose'], [4, 'blanc'], [1, 'rose']],[[5, 'rouge'], [6, 'vert'], [1, 'rouge'], [4, 'rouge'], [5, 'jaune'], [5, 'bleu']],[[2, 'vert'], [2, 'blanc'], [1, 'jaune'], [3, 'rouge'], [2, 'jaune'], [6, 'bleu']],[[3, 'blanc'], [4, 'vert'], [3, 'jaune'], [2, 'rouge'], [6, 'rouge'], [3, 'rose']]]

dic_Voisin={}
a={}
for ligne in range (0,6):    
        for case in range (0,6):
            for voisin in range (0,6):                 
                for i in range (0,2):
                    if carte[ligne][case][i] == carte[ligne][voisin][i] and voisin!=case:
                        if dic_Voisin.get((ligne,case)):
                            dic_Voisin[(ligne,case)].append(carte[ligne][voisin])
                        else:
                            dic_Voisin[(ligne,case)]=[carte[ligne][voisin]]
                    if carte[voisin][ligne][i] ==  carte[case][ligne][i] and voisin!= case:
                        
                        if a.get((ligne,case)):
                            a[(ligne,case)].append(carte[voisin][ligne])
                        else:
                            a[(ligne,case)]=[carte[voisin][ligne]]

[wise furnace]

excellent!

That's some deeply-nested for looping going on.

[rustic wasp]

so here i get two dic that are what i want

[wise furnace]

You see how case is a different color there?

[rustic wasp]

carte=[[[2, 'bleu'],[6, 'jaune'],[5, 'rose'],[4, 'rose'], [1, 'blanc'],[4, 'vert']],[[4, 'bleu'], [6, 'blanc'], [6, 'rose'], [3, 'vert'], [5, 'blanc'], [5, 'vert']],[[3, 'bleu'], [4, 'jaune'], [1, 'bleu'], [2, 'rose'], [4, 'blanc'], [1, 'rose']],[[5, 'rouge'], [6, 'vert'], [1, 'rouge'], [4, 'rouge'], [5, 'jaune'], [5, 'bleu']],[[2, 'vert'], [2, 'blanc'], [1, 'jaune'], [3, 'rouge'], [2, 'jaune'], [6, 'bleu']],[[3, 'blanc'], [4, 'vert'], [3, 'jaune'], [2, 'rouge'], [6, 'rouge'], [3, 'rose']]]

dic_Voisin={}
a={}
for ligne in range (0,6):    
        for case in range (0,6):
            for voisin in range (0,6):                 
                for i in range (0,2):
                    if carte[ligne][case][i] == carte[ligne][voisin][i] and voisin!=case:
                        if dic_Voisin.get((ligne,case)):
                            dic_Voisin[(ligne,case)].append(carte[ligne][voisin])
                        else:
                            dic_Voisin[(ligne,case)]=[carte[ligne][voisin]]
                    if carte[voisin][ligne][i] ==  carte[case][ligne][i] and voisin!= case:
                        
                        if dic_Voisin.get((ligne,case)):
                            dic_Voisin[(ligne,case)].append(carte[voisin][ligne])
                        else:
                            dic_Voisin[(ligne,case)]=[carte[voisin][ligne]]

but here i get 1 dic and every thing is broken somehow

[rustic wasp]

why so?

[wise furnace]

case is used in Python for switch/case statements.

[rustic wasp]

o

should i switch it

[wise furnace]

It's not the source of your problem but you should definitely call it something else in your code.

I don't see any dict here.

carte looks like a list of lists

[rustic wasp]

if i call it Case

[rustic wasp]

it is

[wise furnace]

oh dic_Voisin

[rustic wasp]

yes

[wise furnace]

What is it that you're trying to do?

[rustic wasp]

right here haha

basically making a dic of all the possible movement

for every spot

[wise furnace]

If you need 3.10 why did you install 3.12?

[rustic wasp]

?

i figured out my mistake i was dumb

i inverted lines and columns

just what does 'dict' object is not callable

mean

[wise furnace]

It means you're trying to call a dict as a function, like with parentheses.

[rustic wasp]

oh ok

ty

i have solved most of my problems for now

[wise furnace]

Fantastic.

[rustic wasp]

haha are you still here?

my end result is this : {(1, 1): [[4, 'bleu'], [3, 'bleu'], [2, 'vert']],
(2, 1): [[2, 'bleu'], [3, 'bleu']],
(3, 1): [[2, 'bleu'], [4, 'bleu'], [3, 'blanc'], [1, 'bleu']],
(1, 3): [[4, 'rose'], [6, 'rose']],
(1, 4): [[5, 'rose'], [4, 'vert'], [2, 'rose'], [4, 'rouge']],
(5, 1): [[2, 'bleu'], [2, 'blanc'], [2, 'jaune']],
(6, 1): [[3, 'bleu'], [3, 'jaune'], [3, 'rose']],
(1, 6): [[4, 'rose'], [5, 'vert']],
(1, 2): [[6, 'blanc'], [4, 'jaune'], [6, 'vert']],
(2, 2): [[6, 'jaune'], [6, 'rose'], [6, 'vert'], [5, 'blanc'], [2, 'blanc']],
(3, 2): [[6, 'jaune'], [4, 'vert'], [4, 'blanc']],
(2, 3): [[6, 'blanc'], [5, 'rose']],
(4, 2): [[6, 'jaune'], [6, 'blanc'], [4, 'vert']],
(2, 4): [[5, 'vert'], [3, 'rouge']],
(2, 5): [[6, 'blanc'], [5, 'vert'], [1, 'blanc'], [4, 'blanc'], [5, 'jaune']],
(5, 2): [[6, 'blanc'], [2, 'vert'], [2, 'jaune']],
(6, 2): [[4, 'jaune'], [6, 'vert']],
(2, 6): [[3, 'vert'], [5, 'blanc'], [4, 'vert'], [5, 'bleu']],
(3, 3): [[3, 'bleu'], [1, 'rouge'], [1, 'jaune'], [1, 'rose']],
(4, 3): [[1, 'bleu'], [1, 'jaune'], [5, 'rouge'], [4, 'rouge']],
(3, 4): [[1, 'rose'], [4, 'rose'], [2, 'rouge']],
(3, 5): [[4, 'jaune'], [1, 'blanc'], [5, 'blanc']],
(5, 3): [[1, 'bleu'], [1, 'rouge'], [3, 'jaune'], [2, 'jaune']],
(3, 6): [[1, 'bleu'], [2, 'rose'], [3, 'rose']],
(6, 3): [[1, 'jaune'], [3, 'blanc'], [3, 'rose']],
(4, 1): [[1, 'rouge'], [4, 'rouge'], [5, 'jaune'], [5, 'bleu']],
(4, 4): [[4, 'rose'], [5, 'rouge'], [1, 'rouge'], [3, 'rouge'], [2, 'rouge']],
(4, 5): [[5, 'rouge'], [5, 'bleu'], [5, 'blanc'], [2, 'jaune']],
(5, 4): [[3, 'vert'], [4, 'rouge'], [2, 'rouge']],
(4, 6): [[5, 'rouge'], [5, 'jaune'], [5, 'vert'], [6, 'bleu']],
(6, 4): [[2, 'rose'], [4, 'rouge'], [3, 'rouge'], [6, 'rouge']],
(1, 5): [[5, 'blanc'], [4, 'blanc']],
(5, 5): [[2, 'vert'], [2, 'blanc'], [1, 'jaune'], [5, 'jaune']],
(6, 5): [[2, 'rouge']],
(5, 6): [[5, 'bleu']],
(6, 6): [[3, 'blanc'], [3, 'jaune'], [1, 'rose']]}

can i get rid of the inside brackets?

(2, 1): [[2, 'bleu'], [3, 'bleu']], -> (2, 1): [2, 'bleu', 3, 'bleu']

[tame sail]

That would be harder to work with than without

[rustic wasp]

true

i think ill modifie the second code so that it works better with

[rustic wasp]

it tells me unhashable type: 'list'

[tame sail]

You cannot use a list as the key, only as a value.

[rustic wasp]

END=(1,1)
arriver=(2,5)
chemin={}
chemin[arriver]=[arriver]
sommet_marque=[]; sommet_ferme=[]
sommet_marque.append(arriver)
while len(sommet_marque)!=0:
    S=sommet_marque.pop(0)
    sommet_ferme.append(S)
    for voisin in dic_Voisin[S]:
      
        if  (voisin not in sommet_ferme) and (voisin not in sommet_marque):
                sommet_marque.append(voisin)
                chemin[voisin]=chemin[S]+[voisin]               
                if voisin==END:
                    print(chemin[voisin])          
``` i ve added this (1,1) is not a list is it?

[wise furnace]

that's a tuple

[rustic wasp]

oh you can't put a tuple?

but my tuple is the name of my key though

[wise furnace]

You asked if it was a list and I said it wasn't. You can use a tuple for a key

[rustic wasp]

hmmm

where does the list come from

cuz the error the consol says is still the same

[wise furnace]

for voisin in dic_Voisin[S]: <- voisin is probably going to be a list right?

[tame sail]

What is the full error? It should show a line where the error is happening

[rustic wasp]

yeeee

[wise furnace]

because dic_Voisin is filled with lists

I think you're confusing yourself.

[rustic wasp]

i might

i am

[tame sail]

voisin seems to be a list

or S

S is

[rustic wasp]

END=6
G = {0:[1,2,3],1:[0,7,2],2:[0,1,7],3:[0,2,6],6:[3,7],7:[6,2,1]}
sommet=0
chemin={}
chemin[sommet]=[sommet]
sommet_marque=[]; sommet_ferme=[]
sommet_marque.append(sommet)
while len(sommet_marque)!=0:
   S=sommet_marque.pop(0)
   sommet_ferme.append(S)
   for voisin in G[S]:
      
       if  (voisin not in sommet_ferme) and (voisin not in sommet_marque):
               sommet_marque.append(voisin)
               chemin[voisin]=chemin[S]+[voisin]               
               if voisin==END:
                   print(chemin[voisin])

program was made for this at first

there were no lists

wanted to use the same one for the dic i just made

but in this new dic its made out of lists

!e END=6
G = {0:[1,2,3],1:[0,7,2],2:[0,1,7],3:[0,2,6],6:[3,7],7:[6,2,1]}
sommet=0
chemin={}
chemin[sommet]=[sommet]
sommet_marque=[]; sommet_ferme=[]
sommet_marque.append(sommet)
while len(sommet_marque)!=0:
S=sommet_marque.pop(0)
sommet_ferme.append(S)
for voisin in G[S]:

   if  (voisin not in sommet_ferme) and (voisin not in sommet_marque):
           sommet_marque.append(voisin)
           chemin[voisin]=chemin[S]+[voisin]               
           if voisin==END:
               print(chemin[voisin])

[ember knot]

@rustic wasp :white_check_mark: Your 3.12 eval job has completed with return code 0.

[0, 3, 6]

[rustic wasp]

see it was the fastest path from sommet to END

now i want to go from any key to another expl: (1,1) to (2,5)

[tame sail]

I think you should store the coordinates of the places you can go to then, not the number/color

[rustic wasp]

hmmm yes

good idea

[tame sail]

Anyway good luck with this, I got to get some sleep.

[rustic wasp]

xd i have to get some too gn

'tuple' object has no attribute 'append'

[ember knot]

Python help channel closed

This help channel has been closed and it's no longer possible to send messages here. If your question wasn't answered, feel free to create a new post in #1035199133436354600. To maximize your chances of getting a response, check out this guide on asking good questions.

🔒 help with dictionaries