🔒 beginner variable problem

[clever wasp]

hi, why doesn't the resultat variable change

    n=n_mots(ch)
    for i in range(len(ch)):
        if ch[i] != " ":
            b=ord(ch[i])
            if b+n < 90:
                resultat=resultat+chr(b+n)
            else:
                resultat=resultat+chr(b+n-26)
        else:
            resultat=resultat+" "
resultat=""
crypter(ch,resultat)
print(resultat)```

[tacit prawn]

Hey @clever wasp!

It looks like you pasted Python code without syntax highlighting.

Please use syntax highlighting to improve the legibility of your code and make it easier for us to help you.

To do this, use the following method:
```py
print('Hello, world!')
```

This will result in the following:

print('Hello, world!')```
You can **edit your original message** to correct your code block.

[tacit prawn]

@clever wasp

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[clever wasp]

def crypter(ch,resultat):
    n=n_mots(ch)
    for i in range(len(ch)):
        if ch[i] != " ":
            b=ord(ch[i])
            if b+n < 90:
                resultat=resultat+chr(b+n)
            else:
                resultat=resultat+chr(b+n-26)
        else:
            resultat=resultat+" "
resultat=""
crypter(ch,resultat)
print(resultat)

immutable?

[celest coral]

what would the value of ch be?

[jolly aspen]

It means to "change" a string that you basically just create a new one and assign it to the old variable

[clever wasp]

it's a string

[fathom onyx]

I think you should check out https://nedbatchelder.com/text/names.html

[celest coral]

And it looks like the function isn't returning anything

[celest coral]

!return-gif might explain better

[tacit prawn]

Print and return

Here's a handy animation demonstrating how print and return differ in behavior.

See also: /tag return

[clever wasp]

i thought that it should change resultat

[celest coral]

It won't if you don't return the value from the function

[clever wasp]

what isn't it a procedure

[celest coral]

except for class attributes

[clever wasp]

so it doesn't need a return?

[jolly aspen]

They are expecting pass-by-reference

[celest coral]

hmm

[celest coral]

it needs a return

[upbeat forge]

strings arent mutable datatypes so when the function ends the string will be pointing to an entirely different address and outside the function when you print its value, you wont get the desired result

[clever wasp]

so the problem is with strings

if it's an array it works?

[jolly aspen]

It's not a problem per se - it's just the way Python works

[upbeat forge]

pretty much, if you use list or dict it will work that way

[clever wasp]

because when we use array it does work i thought it's the same

oh okay list or array is the same thing right?

[upbeat forge]

you could say its the same

its not entirely true

[clever wasp]

so it's better to use a function ( return a string)

[upbeat forge]

if im not wrong: arrays allow you to hold a bunch same datatypes in a single variable but since python is a dynamic language we have list which allows us to hold an "array" of different datatypes in a single variable

[clever wasp]

oh okay it's hard to understand

i'll stick to what i'm told to do hah but thank you so much ☺️

[upbeat forge]

yeah alr

[clever wasp]

!close

[tacit prawn]

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