#🔒 why my python decode don't working correct
orchid robin
@pulsar idol show your code?
pulsar idol
yo
pulsar idol
<@821054520037081128> show your code?
i don't have a nitro
65 strings
@orchid robin
'''the str_split() function splits a string into characters'''
'''функция str_split() разбивает строку на символы'''
def str_split(seq, length):
return [seq[i:i + length] for i in range(0, len(seq), length)]
'''the encode() function encrypts the text with a key that determines the number of columns, and prints the encrypted text by reading the characters across the columns'''
'''функция encode() шифрует текст с ключом, определяющим количество столбцов, и печатает зашифрованный текст, читая символы по столбцам'''
def encode(key, plaintext):
order = {int(val): num for num, val in enumerate(key)}
ciphertext = ''
for index in sorted(order.keys()):
for part in str_split(plaintext, len(key)):
try:ciphertext += part[order[index]]
except IndexError:
continue
return ciphertext
'''Please implement the decode() function'''
'''Функцию decode() реализуйте сами'''
def decode(key, ciphertext):
# Determine the order of columns based on the key
order = {int(val): num for num, val in enumerate(key)}
# Determine the number of columns
num_columns = len(key)
# Initialize a list of columns to store characters
columns = [''] * num_columns
# Iterate over the ciphertext, filling the columns
col_index = 1 # Start from 1 instead of 0
for char in ciphertext:
columns[order[col_index]] += char
col_index = (col_index % num_columns) + 1 # Adjust index to start from 1
# Concatenate characters from each column to obtain plaintext
plaintext = ''.join(columns)
return plaintext.rstrip('$') # Remove any trailing '$' characters
'''Setting the key/Задаем ключ key:'''
key = '3421'
'''Setting the plaintext/Задаем открытый текст'''
Text = 'Hello, world'
'''Let's add a non-significant text to the last row in the table (add the "$" sign)'''
'''Дополним незначащим текстом последнюю строку в таблице (допишем знак "$")'''
AddTextNum = len(Text) % len(key)
for k in range(AddTextNum):
Text = Text + '$'
#print ("Plaintext: \n", Text, "\n")
'''We encrypt the plaintext supplemented with special, insignificant, text'''
'''Шифруем открытый текст, дополненный незначащим текстом'''
Encrypted = encode(key, Text)
print("\nCiphertext: \n", Encrypted, "\n")
'''We decrypt the ciphertext'''
'''Расшифруем криптограмму'''
Decrypted = decode('2413', Encrypted)
print("Plaintext: \n", Decrypted, "\n")
print("Plaintext in a table form: \n")
@heavy plume this is a task Complications of the simple vertical permutation cipher (SVPS)
For the definition of PVPS (without complications), see, for example, paragraph 1.3. books
B. Schneier “Applied cryptography”
a) In the file XTransposition_Cipher_Complicated.py,
PVPS encryption with alternative keys is implemented, then
there is a key in such a cipher 𝑘 has the form 𝑘 = 𝑎1𝑎2 … 𝑎𝑚, where
𝑎1, 𝑎2, … , 𝑎𝑚 are different numbers from 1 to m, and m is the number
columns (key) in the table. Note that in the usual PVPS 𝑘 =
12…𝑚.
Add this script by implementing
✓ the Decode() function, which performs decryption,
✓ output of plaintext in a line and in the form of a table.
Please submit the source code as an answer.
b) Given is the C1 ciphergram obtained by PVPS.
✓ After performing cryptanalysis, find the plaintext T1 and the key
K1 encryption.
✓ Encrypt the plaintext T2 using the found key,
having received the C2 ciphergram.
Provide C2 as an answer.
C1:
Osfshnsaқmyrsrtryөsdovөyayyіқzіynozndnrnmgzbylaa
YAUDUDEIIKRALETRARARAAYAIIIIROA
T2:
ZHZHELZHYNEASDATKLRIENA-SYSPYSRIKUATYIZADUEGLTYAYR
ADDURYSZELIҢAE
@orchid robin are you here?
orchid robin
!paste
sacred orbitBOT
pulsar idol
@orchid robin https://paste.pythondiscord.com/HPQQ
orchid robin
You didn't write a decode function
pulsar idol
@orchid robin https://paste.pythondiscord.com/K7MA
@orchid robin it's a wrong code?
or this need to work like that?
orchid robin
What does it do when you run it?
orchid robin
What does it do when you run it?
