🔒 Python program convert english to pig latin

[timber hound]

def translate(text):
    sentence = text.split()
    piggysentence = []
    vowels = ["a","e","i","o","u"]

    for word in sentence:
        if word[0].lower() in vowels or word[:2].lower() in ("xr","yt"):  # for words with vowel starting
            piggyword = word + "ay"
            piggysentence.append(piggyword)
        else: # for consonants starting
            
            cons_num = 0  #keep track of consonants
            for letter in word:
                if letter.lower() not in vowels:
                    cons_num += 1
                else:
                    break
            
            print(cons_num,word)
            piggyword = word[cons_num:] + word[:cons_num] + "ay"
            piggysentence.append(piggyword)
    return piggysentence


print(translate("chcair"))

[gaunt hawk]

@timber hound

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[timber hound]

https://exercism.org/tracks/python/exercises/pig-latin

[timber hound]

i have completed the first 2 requirements i dont have idea where to place if block for next condition .. am i on right track??

[timid hound]

1. python strings has a method called x.startswith(str), where it returns true if x starts with str, and false otherwise. (you can use this instead of your .lower())
2. My understanding of rule 3 is that it will overwrite rule 2 when appliable, so Iwould put this check before your rule 2 check.

[timber hound]

def translate(text):
    sentence = text.split()
    piggysentence = []
    vowels = ["a","e","i","o","u"]

    for word in sentence:
        if word[0].lower() in vowels or word[:2].lower() in ("xr","yt"):  # for words with vowel starting
            piggyword = word + "ay"
            piggysentence.append(piggyword)
        else: # for consonants starting
            
            cons_num = 0  #keep track of consonants
            for letter in word:
                letter = letter.lower()
                if letter == "u":
                    index_l = word.index(letter)
                    if word[index_l - 1] == "q":
                        cons_num += 1
                        continue
                if letter not in vowels:
                    cons_num += 1
                else:
                    print("thiss",letter)
                    break
            
            print(cons_num,word)
            piggyword = word[cons_num:] + word[:cons_num] + "ay"
            piggysentence.append(piggyword)
    return piggysentence


print(translate("square"))



``` i hardcoded like this is this ok?

oh i could use enumerate instead?

[timid hound]

well my idea is check if the word.startswith(constant + 'qu')

where the constant part you figure out

and when I say replace.lower() i meant you can write

if word.startswith(tuple(vowels), 'xr', 'yt'):
#instead of 
if word[0].lower() in vowels or word[:2].lower() in ("xr","yt"):

[timber hound]

oh didnt knew startswith accept iterable too...!

!str.startswith

!d str.startswith

[gaunt hawk]

str.startswith

str.startswith(prefix[, start[, end]])```
Return `True` if string starts with the *prefix*, otherwise return `False`. *prefix* can also be a tuple of prefixes to look for. With optional *start*, test string beginning at that position. With optional *end*, stop comparing string at that position.

[timber hound]

this seem better i change it now

[timid hound]

it can't acceptlist, but it can with tuple

in my testing

so that's why the tuple() was there

[timber hound]

yeah ok 👍

[gaunt hawk]

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