🔒 help understanding this code

[rocky wraith]

This is supposed to,
Input: song lyrics
Output: the most frequent words

im not sure how it does this

[karmic linden]

@rocky wraith

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[light nebula]

Is it working or not?

[rocky wraith]

yes it works

[light nebula]

ahh okay

so thing is the first for loop goes through lyrics

and the second one geos through the keys of the dictionaries

and if the repsected keys match then increment value of key by 1 each time

[rocky wraith]

but the dictionary is empty

[light nebula]

you're updating it during the for loop

so each for lop sotres words and their values

it's like dictionary.update

but this time setting key and value

[rocky wraith]

hmm

where exactly does each word in the lyrics become a key

[inland copper]

why have you made artwork out of your code

[inland copper]

in the else block

[rocky wraith]

i still dont get how it can find the word in the dictionary if its empty

def lyrics_to_frequencies(lyrics):
    myDict = {}
    for word in lyrics:
        if word in myDict:
            myDict[word] += 1
    else:
        myDict[word] = 1
    return myDict
print(lyrics_to_frequencies([apple, banana, grape, apple]))

also it doesnt seem to work

[viral creek]

The else needs to be indented one more time

Otherwise you're doing a for ... else loop, which is also a thing, but not what you want now

[viral creek]

It thinks that's a variable, if you want it to consider it a string (aka text), it needs to be between quotes, so "apple", "banana" etc

[rocky wraith]

oh ok

it works

if word in myDict:

i dont get how this line works

[viral creek]

!e py my_dict = { "apple": 1, "banana": 4 } if "apple" in my_dict: print("apple found") if "grape" in my_dict: print("grape found (this won't print)")

[karmic linden]

@viral creek :white_check_mark: Your 3.12 eval job has completed with return code 0.

apple found

[rocky wraith]

but in my other code the dictionary is empty

[viral creek]

Yeah, if the item isn't found the else block runs, and adds the item to the dict

[rocky wraith]

ok, but how can it be found if myDict = {}

[warm sand]

if it FINDS it in the dict, it adds a frequency to it, if it DOESNT FIND, it will add the word to the dict, so that on the next loop through, it can find it

[viral creek]

!e That's the point, it can't be found

my_dict = {}

if "apple" in my_dict:
    print("won't print")
else:
    my_dict["apple"] = 1 #this will run

print(my_dict) #now has apple in it```

[karmic linden]

@viral creek :white_check_mark: Your 3.12 eval job has completed with return code 0.

{'apple': 1}

[rocky wraith]

ah

i get it now

[karmic linden]

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🔒 help understanding this code