🔒 Restaurant Menu problem

[barren sigil]

@muted wadi

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[muted wadi]

im kinda stuck on how to create the dictionary with strings and floats

[open idol]

do you know how a dictionary work?

[muted wadi]

well ye but like

wouldnt it just be:
menu = {"Burger": 10.99, "Fries": 3.99,"Salad": 7.99,"Milkshake": 5.99}

im not sure..

[open idol]

show me what you have tried

[open idol]

yep, pretty much like this

[muted wadi]

ok great

[open idol]

now you know what to do next?

[muted wadi]

haha T_t

im thinking about it

[open idol]

just try things out and explore

[crystal pine]

Look into the exercise

If You read it well You can do it

We dont want to tell You the answers so You can think

[open idol]

yep

we also have

!rule hw

[barren sigil]

Rules

8. Do not help with ongoing exams. When helping with homework, help people learn how to do the assignment without doing it for them.

[crystal pine]

Yup

[muted wadi]

yeye but im allowed to ask you guys if the code is right/good?

[open idol]

ofc

[crystal pine]

Yes

For sure

[muted wadi]

for item in menu:
print(f'{item}: menu[item]')
that's the next part pretty sure

[open idol]

have you tested it?

[muted wadi]

wait ur right

[void token]

If menu is a dict[item,price] than yes

[crystal pine]

Its a dict

[void token]

U could use
For k,v in menu.items():

[muted wadi]

#Question 2

menu = {"Burger": 10.99, "Fries": 3.99,"Salad": 7.99,"Milkshake": 5.99}

for item in menu:
print(f'{item}: menu[item]')

[open idol]

what have you forgot when using f-strings?

[void token]

menu[item] is not revognised as a var by the f string

[muted wadi]

I FORGOT ANOTHER PAIR OF {} AROUND MENU[ITEM] 😭

it prints out the meny now

[open idol]

yessir

[void token]

Yes

[open idol]

now what you need to do next?

[crystal pine]

Nice

No you should make a user input and check if the input is in the menu

[void token]

If u print both the key and the value use
for key, value in dict.items()

[crystal pine]

Good luck

[muted wadi]

#Question 2

menu = {"Burger": 10.99, "Fries": 3.99,"Salad": 7.99,"Milkshake": 5.99}

for item in menu:
print(f'{item}: {menu[item]}')

user_input = input("Enter the name of a menu item you would like to order: ")

if user_input in menu:
print(f"The price of {user_input} is ${menu[user_input]}.")
else:
print("The item is not on the menu.")

the code looks good right?

[crystal pine]

Try to say something not in the menu and see what happens

[muted wadi]

ye it shows the right statement, im j talking ab like the code itself tho

[crystal pine]

Yes its good

[muted wadi]

horray thanks

[crystal pine]

But

What if the user typed a number in the user input

[muted wadi]

it says the item is not on the menu

the right statement^

[void token]

i still think it looks better if u use
for key, value in menu.items():
but it works and dosent have any other thing i could say is wrong

[muted wadi]

is this just a better syntax or something

[void token]

yes

[solemn plinth]

They key and value you can name yourself, so could be:
for item, price in ..

[barren sigil]

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🔒 Restaurant Menu problem