brisk dew
Hello all, for this code I am asking the user to input a new vehicle to be added to the dictionary. However, if I input an invalid rental rate (eg. e4) it will immediately raise the valueerror. How can I make it so even if an invalid input in entered, the code will still prompt me for the VIN code before raising the valueerror? thank you!
carmine warrenBOT
Hello all, for this code I am asking the user to input a new vehicle to be added...
@brisk dew
Python help channel opened
analog zodiac
what I always do is: I write a separate function named something like "get_valid_input". It does what it says: it loops until it gets input that we consider valid, and only then does it return it.
gimme a second, I'll show you an example
this isn't exactly your situation, but it's vaguely similar: ```py
def get_string_from_choices(prompt: str, choices: list[str]) -> str:
while True:
datum = input(prompt).strip()
if datum in choices:
return datum
print(f"{datum} isn't in {choices}; please try again")
perhaps a closer analog is this ```py
def get_int(prompt: str) -> int:
while True:
try:
return int(input(prompt))
except ValueError as e:
print(f"{e}; please try again")
hmm it is slightly similar, but in this case it isn't a must to have a valid input
analog zodiac
it isn't?
but you're catching the same exception.
post your code as text and I'll show you
brisk dew
nope, all I wish to change is so all 3 questions are asked despite the user input
ah alright
if choice == "1":
try:
model = input("Enter vehicle model: ")
rental_rate = float((input("Enter rental rate: ")))
vin = input("Enter VIN: ")
company.add_vehicle(Vehicle(model, rental_rate, vin))
print("Vehicle added successfully!")
except ValueError:
print("Vehicle could not be added.")
whoops the formatting is a bit off
analog zodiac
like this ```py
def add_vehicle_model() -> str:
while True:
try:
model = input("Enter vehicle model: ")
rental_rate = float((input("Enter rental rate: ")))
vin = input("Enter VIN: ")
company.add_vehicle(Vehicle(model, rental_rate, vin))
return
except ValueError as e:
print(f"Vehicle could not be added because {e}")
this is a bit annoying, since it always asks for both model and VIN, even if they only got one of those two things wrong.
still wind
You can also convert to a float only after asking the questions
brisk dew
this is a bit annoying, since it *always* asks for both model and VIN, even if t...
yes lol
still wind
In pseudo code:
try:
model =input
rental_rate =input
vin=input
rental_rate -> float
except:
...```yes I've tried that and unfortunately it doesn't really work
brisk dew
like this ```py
def add_vehicle_model() -> str:
while True:
try:
...
for this code it works but the VIN is asked after the exception is printed which might be weird
still wind
yes I've tried that and unfortunately it doesn't really work
What did you try with and how doesn't it work?
brisk dew
if choice == "1":
while True:
try:
model = input("Enter vehicle model: ")
rental_rate = (input("Enter rental rate: "))
vin = input("Enter VIN: ")
rental_rate = float(rental_rate)
company.add_vehicle(Vehicle(model, rental_rate, vin))
print("Vehicle added successfully!")
return
except ValueError:
print("Vehicle could not be added.")
in this case the vin is still asked after the exception is raised 🤔
dense kraken
that's weird
dense kraken
```py
if choice == "1":
while True:
try:
...
that should work
brisk dew
that should work
I think there was something off with the initial input for rental rate, I added rental_rate = “” and it ended up working
thank you everyone!
