🔒 Help with dictionaries | Python | Page 1

humble turret Apr 5, 2024, 1:05 AM

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Hey I've a doubt in implementing some logic in the code

wheat nymphBOT Apr 5, 2024, 1:05 AM

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humble turret Hey I've a doubt in implementing some logic in the code

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@humble turret

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humble turret Apr 5, 2024, 1:06 AM

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i've a string

json_string = "{\"day 1\":  \"location 1\",\n\"day 2\": \"location 2\",\n\"day 3\": [\"location 3\",\"location4\"],\n\"day 4\":[\"location 5\",\"location 6\"]}"

and I want to convert this into a list which will have 4 dict

{"day 1": "location 1", "day 2": "location 2", "day 3": "location 3", "day 4": "location 5",}
{"day 1": "location 1", "day 2": "location 2", "day 3": "location 3", "day 4": "location 6"}
{"day 1": "location 1", "day 2": "location 2", "day 3":  "location4", "day 4": "location 5"}
{"day 1": "location 1", "day 2": "location 2", "day 3": "location4", "day 4": "location 6"}```

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implemented code byfar -


import json
json_string = "{\"day 1\":  \"location 1\",\n\"day 2\": \"location 2\",\n\"day 3\": [\"location 3\",\"location4\"],\n\"day 4\":[\"location 5\",\"location 6\"]}"

day_plans = json.loads(json_string)

print(day_plans['day 1'])

result_dicts = []
for key, value in day_plans.items():
    if isinstance(value, list):
        for location in value:
            new_dict = day_plans.copy()
            new_dict[key] = location
            result_dicts.append(new_dict)

for data in result_dicts:
    print(data)```

brazen forum Apr 5, 2024, 1:11 AM

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Hey, first i would advise you to use lists no matter what, even if its only on location

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Then you iterate through the values of the dictionary and you get the longer one

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Not sure why do you want to have a list with 4 dict?

brazen forum Apr 5, 2024, 1:13 AM

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humble turret i've a string ``` json_string = "{\"day 1\": \"location 1\",\n\"day 2\": \"loc...

Seems to me 2 of these items are duplicates

humble turret Apr 5, 2024, 1:14 AM

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This is my internship code
I want to first convert this into 4 to show users 4 different output of what choices he have

humble turret Apr 5, 2024, 1:15 AM

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brazen forum Seems to me 2 of these items are duplicates

oh sorry I just checked
wait let me edit it

brazen forum Apr 5, 2024, 1:15 AM

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Got it you want to print all the possibilities right ?

humble turret Apr 5, 2024, 1:15 AM

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check now please

humble turret Apr 5, 2024, 1:15 AM

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brazen forum Got it you want to print all the possibilities right ?

yes

brazen forum Apr 5, 2024, 1:15 AM

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Okay

stray path Apr 5, 2024, 1:16 AM

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do you always have at most 4 options, or do you need a more general solution to handle an arbitrary number of arrays of arbitrary length

humble turret Apr 5, 2024, 1:16 AM

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current output

{'day 1': 'location 1', 'day 2': 'location 2', 'day 3': 'location 3', 'day 4': ['location 5', 'location 6']}
{'day 1': 'location 1', 'day 2': 'location 2', 'day 3': 'location4', 'day 4': ['location 5', 'location 6']}
{'day 1': 'location 1', 'day 2': 'location 2', 'day 3': ['location 3', 'location4'], 'day 4': 'location 5'}
{'day 1': 'location 1', 'day 2': 'location 2', 'day 3': ['location 3', 'location4'], 'day 4': 'location 6'}```

humble turret Apr 5, 2024, 1:17 AM

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stray path do you always have at most 4 options, or do you need a more general solution to ...

no not mandatory
There can be 2 options aswell

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or 8

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other sample string
"{"day 1": "location 1",\n"day 2": "location 2",\n"day 3": ["location 3","location4"],\n"day 4":"location 5"} "

deft geyser Apr 5, 2024, 1:20 AM

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humble turret i've a string ``` json_string = "{\"day 1\": \"location 1\",\n\"day 2\": \"loc...

something i see immediately is you can just have single quotes for the json string instead of a backslash after every double quote in the string

humble turret Apr 5, 2024, 1:20 AM

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deft geyser something i see immediately is you can just have single quotes for the json stri...

It's not me
I was given it this way

stray path Apr 5, 2024, 1:21 AM

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this is a pretty common leetcode style-question

humble turret Apr 5, 2024, 1:21 AM

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this is the api output i was provided

stray path Apr 5, 2024, 1:21 AM

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you can solve this either iteratively or recurisvely

deft geyser Apr 5, 2024, 1:21 AM

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humble turret It's not me I was given it this way

bit strange of a question to spam backslashes

humble turret Apr 5, 2024, 1:21 AM

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deft geyser bit strange of a question to spam backslashes

Ikr

stray path Apr 5, 2024, 1:21 AM

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that's just how json looks when it's stringified

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you can remove the escapes if you use single quotes for the outer string

humble turret Apr 5, 2024, 1:22 AM

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I just use json.loads

humble turret Apr 5, 2024, 1:22 AM

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humble turret implemented code byfar - ```py import json json_string = "{\"day 1\": \"locati...

@stray path this is the best I could think of

stray path Apr 5, 2024, 1:22 AM

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your solution is pretty close to the iterative case, but it's missing a loop over result_dicts

humble turret Apr 5, 2024, 1:22 AM

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I did iterative approach

stray path Apr 5, 2024, 1:23 AM

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every time you have an array of values, you need to duplicate the elements in result_dicts

deft geyser Apr 5, 2024, 1:23 AM

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humble turret This is my internship code I want to first convert this into 4 to show users 4 d...

whats wrong with the code?

humble turret Apr 5, 2024, 1:23 AM

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50%

deft geyser Apr 5, 2024, 1:23 AM

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ima let connor handle this actually

humble turret Apr 5, 2024, 1:23 AM

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humble turret current output ```location 1 {'day 1': 'location 1', 'day 2': 'location 2', 'day...

@deft geyser this is the output

stray path Apr 5, 2024, 1:27 AM

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in pseudocode this might look something like

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# we initialize the list to empty dict to make iteration simpler
+ result_dicts = [{}]
for key, value in day_plans.items():
    if isinstance(value, list):
# we keep a copy of result_dicts and change the array to be empty to simplify appending
+       copy = result_dicts
+       result_dicts = []
        for location in value:
+           for r in copy:
+              new_dict = r.copy()
               new_dict[key] = location
               result_dicts.append(new_dict)
# no array means we add the key to every dictionary
+   else:
+     for r in result_dicts:
+       r[key] = value

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disclaimer i haven't run this, just wrote in discord. this is roughly what you want for the iterative approach

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at each step you're effectively multiplying the number of dictionaries in the result_dicts array by the number of elements in the value

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added on changed lines for effect and i'd remove comments in production code

humble turret Apr 5, 2024, 1:34 AM

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wow

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It ran

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damn thanks dude

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😭

stray path Apr 5, 2024, 1:35 AM

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humble turret Apr 5, 2024, 1:35 AM

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you've no idea how much this helped

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do you code alot?

stray path Apr 5, 2024, 1:36 AM

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make sure you're able to write it without looking at this example! i didn't mean to solve the problem haha

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yes you can check out my github https://github.com/connorskees/

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connorskees has 66 repositories available. Follow their code on GitHub.

humble turret Apr 5, 2024, 1:37 AM

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god damn

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744 contrib

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I just followed you

wheat nymphBOT Apr 5, 2024, 2:37 AM

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#🔒 Help with dictionaries