#🔒 Python assignment help

86 messages · Page 1 of 1 (latest)

desert peakBOT
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@eternal knot

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eternal knot
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Need help with homework assignment

dreamy iris
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You can't upload it. Copy and paste relevant text into the chat.

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@eternal knot

eternal knot
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oh ok

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do i just copy paste the code?

dreamy iris
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Yes

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!code

desert peakBOT
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Formatting code on Discord

Here's how to format Python code on Discord:

```py
print('Hello world!')
```

These are backticks, not quotes. Check this out if you can't find the backtick key.

For long code samples, you can use our pastebin.

eternal knot
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it says code is too long

dreamy iris
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Read the bot message

eternal knot
dreamy iris
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play = [[0, 0, 0]] * 7
This is a problem

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You'll have the same list seven times. So changes to one "row" will appear in all rows

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Because they're the same list

eternal knot
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what should i do about that?

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i was provided a starter file and this was already included in that starter file

dreamy iris
eternal knot
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my professor

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i think

dreamy iris
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In the meantime, you'd use a list comprehension to make sure that each sub-list is a separate object

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!listcomp

desert peakBOT
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List comprehensions

Do you ever find yourself writing something like this?

>>> squares = []
>>> for n in range(5):
...    squares.append(n ** 2)
[0, 1, 4, 9, 16]

Using list comprehensions can make this both shorter and more readable. As a list comprehension, the same code would look like this:

>>> [n ** 2 for n in range(5)]
[0, 1, 4, 9, 16]

List comprehensions also get an if clause:

>>> [n ** 2 for n in range(5) if n % 2 == 0]
[0, 4, 16]

For more info, see this pythonforbeginners.com post.

eternal knot
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so i would use listcomp with play = [[0, 0, 0]] * 7

cursive mica
eternal knot
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is this better?
# Declare a 7 row by 3 column list
column = 3
row = 7
play = [[int() for _ in range(column)] for _ in range(row)]

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or this for more condensed play = [[int() for _ in range(3)] for _ in range(7)]

tall summit
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!code

desert peakBOT
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Formatting code on Discord

Here's how to format Python code on Discord:

```py
print('Hello world!')
```

These are backticks, not quotes. Check this out if you can't find the backtick key.

For long code samples, you can use our pastebin.

eternal knot
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play = [[int() for  in range(3)] for  in range(7)]
tall summit
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some characters have special meaning for formatting in Markdown, which discord employs

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italics for example

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that word is surrounded by *

cursive mica
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I'd personally write 0 instead of int(). And I'd probably not use a list comprehension for the 3-element inner list. But ya.

tall summit
eternal knot
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ok

tall summit
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yeah and as Carci said, can do [0] * 3 for the inner lists

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because 0 is immutable

cursive mica
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Ya, you can't mutate a number, so it doesn't matter if you have multiple references to the same number.

eternal knot
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this is a program for the 21 card trick do i want to the values in list to be immutable

cursive mica
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Numbers are just inherently immutable. If you want a list of numbers, the mutability isn't your main concern. The fact that they're immutable makes them "safer" in some circumstances though.

eternal knot
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ok

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so i changed the line deal(deck) to deal(deck,play) and that fix one error i was having

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i can finally see the 3 columns now but it's all the same card atm

cursive mica
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What's wrong?

eternal knot
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each card is supposed to be a different card

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then the program is supposed to pick up the cards and then use those same cards and put them in each column

cursive mica
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Notice how BuildDeck doesn't use the deck parameter. That function does some work then throws away everything it does.

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So you create deck via deck = [0] * 52, then it doesn't change after that.

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Then that deck full of only 0s is passed into Deal.

eternal knot
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i see what you mean

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i was trying to make BuildDeck
build a deck of 52 cards in random order but for some reason it's not working

cursive mica
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You want a list full of unique numbers in random order?

eternal knot
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yeah from 1 to 52

cursive mica
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Just use random.shuffle.

eternal knot
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or 0 or 51

cursive mica
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!e

import random
cards = list(range(52))
random.shuffle(cards)
print(cards)
desert peakBOT
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@cursive mica :white_check_mark: Your 3.12 eval job has completed with return code 0.

[36, 10, 21, 6, 41, 22, 48, 18, 29, 16, 9, 11, 42, 38, 17, 12, 2, 37, 28, 7, 8, 39, 3, 31, 51, 34, 23, 44, 32, 27, 4, 30, 0, 13, 35, 20, 24, 47, 50, 1, 45, 25, 43, 15, 49, 33, 26, 40, 5, 19, 14, 46]
cursive mica
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That's 0-51 inclusive.

eternal knot
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would i use deck = list(range(52))?

cursive mica
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Well, that's a very easy to create a list with the numbers 0-51. That's what'd I'd use unless they're forcing you to do something different.

eternal knot
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i think it'll work as long as put it into the BuildDeck function

cursive mica
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That won't work with how your code currently is, where deck is passed in. You'd need to return the list of numbers from BuildDeck.

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Wow, there's not a single return in that code. Have you learned about return?

eternal knot
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i don't remember how it works tho

cursive mica
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!return

desert peakBOT
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Return statement

A value created inside a function can't be used outside of it unless you return it.

Consider the following function:

def square(n):
    return n * n

If we wanted to store 5 squared in a variable called x, we would do:
x = square(5). x would now equal 25.

Common Mistakes

>>> def square(n):
...     n * n  # calculates then throws away, returns None
...
>>> x = square(5)
>>> print(x)
None
>>> def square(n):
...     print(n * n)  # calculates and prints, then throws away and returns None
...
>>> x = square(5)
25
>>> print(x)
None

Things to note

  • print() and return do not accomplish the same thing. print() will show the value, and then it will be gone.
  • A function will return None if it ends without a return statement.
  • When you want to print a value from a function, it's best to return the value and print the function call instead, like print(square(5)).
cursive mica
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!e

def build_deck():
    deck = list(range(52))
    return deck
d = build_deck()
print(d)
desert peakBOT
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@cursive mica :white_check_mark: Your 3.12 eval job has completed with return code 0.

[0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51]
cursive mica
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Then maybe also add a shuffle call in there if you also want that function to produce the deck as shuffled.

eternal knot
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i think im getting it to work

cursive mica
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That looks better

eternal knot
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not sure why the last card is always the same card

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column 2 row 7 is always the same

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maybe my PickUp() is not correct

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i messed up one number in my PickUp() but it's working now

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but the last card is always the same card for some reason

eternal knot
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i believe it works now

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ty for everyone that helped

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!close

desert peakBOT
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