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[echo plaza]

@past bone

Python help channel opened

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• Show a code sample as text (rather than a screenshot) and the error message, if you've got one.
• Explain what you expect to happen and what actually happens.

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Closes after a period of inactivity, or when you send !close.

[gloomy crow]

!code

[echo plaza]

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[gloomy crow]

please wrap your code in a code block
it'll be easier to read

[past bone]

how do i do that

[gloomy crow]

#1220050725850058893 message

[rotund gull]

follow this

[past bone]

i tried and it looks better when i edit but when i hit save it go back to text

here a image click for quality

[rotund gull]

print("hi everyone")

def protein_sources():
 egg = "6g protein  {155kcal}"
 chicken = 21  , "g protein" , "{239kcal}"
 peanut = "26g protein {588kcal}"
 salmon = "20g protein {208kcal}"
 pasta = "5g protein {157kcal}"
 print(chicken)

protein_sources()




def calculations(chicken):
 food = int(input("what did you eat : " ))
 grams = int(input("how many grams : " ))
 if food == "chicken":
  calc = chicken/100 * grams 
  print(calc)

calculations(chicken) 

[gloomy crow]

where are you trying to pull the last line's chicken from?

[past bone]

from the top

[rotund gull]

chicken was never defined

you didn't access the top function

[past bone]

how can i do that master

[rotund gull]

if you didn't access the function, it will remain in the function and won't be defined yet

[gloomy crow]

in python, variables have scopes
chicken (inside the protein_sources function) is inside that function's scope
once the function finishes, the variable stops existing

[past bone]

oh

but how do i make it stay

[gloomy crow]

move your variable definitions outside the function, since you don't edit them anyway

your code should look something liek this

print("hi everyone")

egg = "6g protein  {155kcal}"
chicken = 21  , "g protein" , "{239kcal}"
peanut = "26g protein {588kcal}"
salmon = "20g protein {208kcal}"
pasta = "5g protein {157kcal}"

def protein_sources():
 print(chicken)

protein_sources()

def calculations(chicken):
 food = int(input("what did you eat : " ))
 grams = int(input("how many grams : " ))
 if food == "chicken":
  calc = chicken/100 * grams 
  print(calc)

calculations(chicken) 

[split olive]

I would really be using a dictionary for that data though

[past bone]

it aint meant to be dictonairy i just like decoration

[split olive]

you're just making it harder for yourself though

[past bone]

why i like decorations

[split olive]

Suit yourself 🤷

You asked for tips to improve this code

[gloomy crow]

making multiple variables like this can get messy fast

imagine if you needed to add, say, 10 more protein sources

[past bone]

i always put symbols underscores and other stuff to decorate my code when done

[gloomy crow]

or add a protein source while the program is running (i.e. user prompt)
you could do it but it'd be easier to do so with a dict

[past bone]

what is more effective way master

[split olive]

use a dict

[gloomy crow]

with a dictionary, as we suggested

[split olive]

I don't understand why you'd ignore our suggestions after asking for help

[past bone]

how i do that it 2 years since i use a dictonary

you dont have to do all my code just show example

[gloomy crow]

print("hi everyone")

protein_sources = {
  "egg": "6g protein {155kcal}",
  "chicken": "21g protein {239kcal}",
  # and so on...
}

# Removed the protein_sources function since it does nothing but print chicken

def calculations(chicken):
 food = int(input("what did you eat : " ))
 grams = int(input("how many grams : " ))
 if food == "chicken":
  calc = chicken/100 * grams 
  print(calc)

calculations(protein_sources["chicken"]) 

[past bone]

will it work for the math tho

[split olive]

Even still, I would separate the data so it's not just a string as the value

protein_sources = {
  "egg": (6, 155),
  "chicken": (21, 239),
  # and so on...
}

I would do it like this, where the value data is the protein in grams and kcal

now you can easily look up a protein and get the relevant data

[past bone]

that is looked up but will that work with the math still

[split olive]

if the numbers are the same, why wouldn't it?

you're going to have to change your logic a bit

but the math is the same

[past bone]

ok ill try that

[split olive]

this prevents you from have to write an if for every single protein

as mentioned above, imagine you had 50 protein sources. Would you want to write 50 if statements?

[past bone]

you gotta do what you gotta do

im willing to do allat to track my protein with accuracy

but i wll try dictonary

[split olive]

!e

protein_sources = {
  "egg": (6, 155),
  "chicken": (21, 239),
  # and so on...
}


protein = 'chicken'
if protein in protein_sources:
    info = protein_sources[protein]
    print(f'{protein} has {info[0]}g of protein and {info[1]} kcal')

[echo plaza]

@split olive :white_check_mark: Your 3.12 eval job has completed with return code 0.

chicken has 21g of protein and 239 kcal

[split olive]

work smarter, not harder

[past bone]

or show how much extra ur willing to sacrafice for something because if you dont go far for something then you dont really want or need it

[split olive]

Why even ask us for help then?

[past bone]

what is the info{0}

[past bone]

bcs i want to learn

[split olive]

info = protein_sources[protein]

[past bone]

ohhh

[split olive]

I'm using info as the variable to look up the value of that associated protein

info[0] is the grams, and info[1] is the kcal

[past bone]

for oposite i call for -1 then 0 right

[split olive]

just do [1] and [0]

[past bone]

if i want calories first

yeah that works to

[split olive]

[1] is always kcal

[0] is always g

[past bone]

ok thanks i lofe you

[echo plaza]

Python help channel closed

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