thick gale
I have a dictionary where the first element is the continents.
'''
{asia : {japan : [cities], china: [cities]},
}
'''
I want to sort it by the countries, so japan and china. the commented out code is currently what I have. I don't really don't know how to proceed here.
short swiftBOT
Hey @thick gale!
short swiftBOT
I have a dictionary where the first element is the continents.
'''
{asia : {japa...
@thick gale
Python help channel opened
feral tiger
the asia dict contains the japan and china keys, so you want to sort the keys:
for country_key in sorted(continent.keys()):
this will give you 'china', then 'japan', in your example
it looks like you already knew this, however, since you sort the continents at the start...?
thick gale
I sort the contients so it goes africa, asia then europe, then I want to sort the countries and then the cities
thick gale
this is the current error I get with what I'm trying to do
neon vigil
Remove the dict() from that last line and take a look at : what type is returned by sorted there?
(Line 60: Where that error occurs)
The hint is: you’re trying to sort the keys of a dictionary, not the dictionary itself
thick gale
oh so by putting dict() on it, it's trying to force it to be a dict data structure
neon vigil
oh so by putting dict() on it, it's trying to force it to be a dict data structu...
The way to debug these problems is to simplify and debug each step.
Much as it’s tempting to write dict(sorted(dict[something].keys())), you have four different things happening here. Do one thing per line, to make it easier to debug.
thick gale
so for now just do sorted(data_types[continents].keys())
neon vigil
What do you expect that to do?
And, try it: what happens?
There’s a logical problem here: you’re trying to sort the keys… then trying to turn those sorted keys into a dictionary. Do you see why that won’t do what you want?
thick gale
yeah I see the issue, however what I want is to sort it so that the countries within every continents are sorted. Doesn't have to put it back into the dictionary necessarily, just need it for printing purposes.
neon vigil
Just the country names?
Err sorry, no; you’re trying to sort the continents first.
But you’re not going to get a dictionary back by sorting the keys.
If you want to sort a dictionary, then do something like:
!e example_dict = {"banana": 3, "apple": 4, "pear": 1, "orange": 2}
sorted_keys = sorted(example_dict.keys())
sorted_dict = {key: example_dict[key] for key in sorted_keys}
print(sorted_keys, sorted_dict)
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@neon vigil :white_check_mark: Your 3.12 eval job has completed with return code 0.
['apple', 'banana', 'orange', 'pear'] {'apple': 4, 'banana': 3, 'orange': 2, 'pear': 1}
The simpler version is just sorting the dict’s items rather than the keys:
!e example_dict = {"banana": 3, "apple": 4, "pear": 1, "orange": 2}
sorted_dict_one_step = dict(sorted(example_dict.items()))
print(sorted_dict_one_step)
short swiftBOT
@neon vigil :white_check_mark: Your 3.12 eval job has completed with return code 0.
{'apple': 4, 'banana': 3, 'orange': 2, 'pear': 1}
are you talking about line 57
neon vigil
I was only looking at your error line 60
thick gale
oh okay. yeah that doesn't return a dict, it's giving me a type error unhashable type: list
neon vigil
Yup, so break that into multiple lines. Don’t fall into the ‘dense is good’ trap.
Then you’ll see the step that’s failing
thick gale
so data_map[continent].items() returns a list of items.
so I just then need to sort the list so that the first elements are sorted
and then use the list to print
I don't need to modify the dictionary anymore
I think i figured it out
data_map[continent] = dict(sorted(data_map[continent].items()))
I did it layer by layer and that's what I came up with
it returns me a sorted dictionary with the nested layer sorted
short swiftBOT
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