#🔒 Converting a date stamp to Roman numerals

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neat forge
#

Hello, I have made a small program for a calculator that records the calculation and date in a file after each use. I need to convert the date time stamp in the file to Roman numerals . None of my functions work, could some please show me how to do this thanks!

azure mistBOT
#

@neat forge

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neat forge
# 
import time

ts = time.strftime("%Y-%m-%d %H:%M:%S")  # Get the current timestamp
# Opening file for output
f = open("C:\\Temp\\calcs.txt", "w")





def isValidMenuOption(num, minV, maxV):
    if (num < minV) or (num > maxV):
        return False
    return True



# Function to output detail
def outputDetail(num1, num2, result):
    file_writing_example = ["Timestamp " + str(result) + " at " + ts + "\n"]
    f.writelines(file_writing_example)

def menu():
    print("Menu")
    print("1. Addition")
    print("2. Subtraction")
    print("3. Multiplication")
    print("4. Division")
    print("")

    menu_option = int(input("Please input a valid menu number: "))
    while not isValidMenuOption(menu_option, 1, 4):
        menu_option = int(input("Please input a valid menu number: "))

    num1 = int(input("Please input the first number: "))
    num2 = int(input("Please input the second number: "))

    if menu_option == 1:
        addition(num1, num2)
    elif menu_option == 2:
        subtraction(num1, num2)
    elif menu_option == 3:
        multiplication(num1, num2)
    elif menu_option == 4:
        division(num1, num2)

def addition(num1, num2):
    sum = num1 + num2
    print("Calculation", num1, " + ", num2, " = ", sum)
    outputDetail(num1, num2, sum)

def subtraction(num1, num2):
    sub = num1 - num2
    print("Calculation", num1, " - ", num2, " = ", sub)
    outputDetail(num1, num2, sub)

def multiplication(num1, num2):
    times = num1 * num2
    print("Calculation", num1, " x ", num2, " = ", times)
    outputDetail(num1, num2, times)

def division(num1, num2):
    if num2 != 0:
        divide = num1 / num2
        print("Calculation", num1, " ÷ ", num2, " = ", divide)
        outputDetail(num1, num2, divide)

menu()
#

And my file output is
Timestamp 9 at 2024-03-12 19:03:02

I need to make is so the date is roman numerals.

raw storm
#

You would have to add another function that checks for the roman numerals every time you pass another calculation to your file

neat forge
# 
def int_to_Roman(num):
  """Converts an integer to its Roman numeral representation.

  Args:
      num: The integer to convert.

  Returns:
      The Roman numeral representation of the integer.
  """

  roman_numerals = {
      1000: 'M',
      900: 'CM',
      500: 'D',
      400: 'CD',
      100: 'C',
      90: 'XC',
      50: 'L',
      40: 'XL',
      10: 'X',
      9: 'IX',
      5: 'V',
      4: 'IV',
      1: 'I'
  }

  result = ''
  for value, numeral in roman_numerals.items():
    while num >= value:
      result += numeral
      num -= value
  return result
azure mistBOT
#
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