🔒 Trying to keep tuples intact when typecasting

[outer vapor]

I have a text file that contains list of files, example line: "drwx------ 8 foo bar-all 4096 Dec 27 13:55 .git"
The regex is correct and findall works as expected. The var ´matches´ is a list of tuples that have strings representing numbers and other strings inside them.
How can I typecast all the strings representing numbers to integers without losing the tuples?
The below code returns a list with the tuples no longer there 😦

#!/usr/bin/env python3

import re


def file_listing(filename="src/listing.txt"):
    with open(filename, "r") as file:
        contents = file.read()
        pattern = (
            r"([\d]*)\s([A-Z][a-z]+)\s([\d]+)\s([\d]+)\:([\d]+)\s(.[a-z]*[.]?[a-z]*)"
        )
        matches = re.findall(pattern, contents)
        print(matches) # [('2356', 'Dec', '11', '11', '50', 'add'), ('164519', 'Dec', '28', '17', '59', 'basics.ipynb')]
        return [(int(j) if j.isdigit() else j) for i in matches for j in i]


def main():
    print(file_listing("src/listing.txt"))


if __name__ == "__main__":
    main()

[agile sun]

@outer vapor

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[minor prism]

(int(j) if j.isdigit() else j) When you put a list comprehension in (), you create a generator expression instead of the expected tuple expression. But you can feed the generator expression into tuple() with tuple(int(j) if j.isdigit() else j).

Nevermind

I was thinking you had for in the () part, but you don't. You'll still need to use the above though to create tuples in your nested list comprehension.

I think tuple(int(j) if j.isdigit() else j for j in i) as the inner expression should do the trick

[outer vapor]

Would you look at that, it works with that. Thanks a lot mate

!close

[agile sun]

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