🔒 why does it not delete out of the list.

[velvet mauve]

when i run this code and i enter of the players names why does it not delete. DOes anyone see any problem?

[brazen scroll]

@velvet mauve

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[rare walrus]

You're recreating that list each time you call the function.

[velvet mauve]

do i need to put the list than out of the function?

[gaunt grove]

how do you know it's not deleting?

[rare walrus]

That is one option.

[velvet mauve]

i tried it

[gaunt grove]

and... what happened?

[rare walrus]

It is removing the entry. But that change is one without effect.

Because the list gets recreated within the function.

Presumably you have a free_players list outside this function?

You're dealing with scope.

[gaunt grove]

yeah i think it's the code that was not shared that makes the problem clear: repeated calls of this function recreate the free_players list

[rare walrus]

!e py def func(): v = 1 print(v) v = 0 func() print(v)

[brazen scroll]

@rare walrus :white_check_mark: Your 3.12 eval job has completed with return code 0.

001 | 1
002 | 0

[velvet mauve]

i only call it once when the player is on the freeplayer position of the board

[rare walrus]

In this way, it's two different v variables.

Like two signposts labelled the same, but in different rooms.

Where you couldn't have multiple signposts of the same name in the same room.

[velvet mauve]

yea i see

it works now i put the list out of the function now it deletes

[rare walrus]

You're dealing with state. So you're knocking on the door of classes and/or databasing.

Good luck.

[velvet mauve]

thank you very much for your help

!close

[brazen scroll]

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