🔒 Simple coding that everyone can know I think but not me so dont hesitate to help

[candid path]

I would like a code that returns a list without the last number, can you help me pls ? For the moment I did this :

[carmine owl]

@candid path

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[wary crypt]

!slice

[carmine owl]

Sequence slicing

Slicing is a way of accessing a part of a sequence by specifying a start, stop, and step. As with normal indexing, negative numbers can be used to count backwards.

Examples

>>> letters = ['a', 'b', 'c', 'd', 'e', 'f', 'g']
>>> letters[2:]  # from element 2 to the end
['c', 'd', 'e', 'f', 'g']
>>> letters[:4]  # up to element 4
['a', 'b', 'c', 'd']
>>> letters[3:5]  # elements 3 and 4 -- the right bound is not included
['d', 'e']
>>> letters[2:-1:2]  # Every other element between 2 and the last
['c', 'e']
>>> letters[::-1]  # The whole list in reverse
['g', 'f', 'e', 'd', 'c', 'b', 'a']
>>> words = "Hello world!"
>>> words[2:7]  # Strings are also sequences
"llo w"

[wary crypt]

Please read embedded above. I think that’ll answer your question, but if not clear, ask more

[candid path]

ok thank you

it is a way to do it

but do you know why my code doesn't work ?

[wary crypt]

It works fine at removing the first occurrence of the last digit

[candid path]

but the "2" is still there

[wary crypt]

Read what I wrote

[candid path]

ahhhhhh

sorry I missread

do you know what I should do ?

because I don't understand why

I put [-1]

so it should be the last two

[deep nova]

You want all 2s gone? (If the last digit is 2?) Or just the last element

?

You can use a slice to get a new string without the last char

Then turn that string to a list

[real token]

[-1] is the last and it is a 2.
Then you are looking through the list removing it the first time it is found.

letters = ['a', 'b', 'c', 'd']
print( letters[:-1] )
['a', 'b', 'c']

[carmine owl]

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