why erore ?
#🔒 try/except
thick storm
strange grail
Can you paste the full error you're getting?
hardy iris
Do you get an error when you run it?
cold shale
@thick storm show your error
lusty reef
why erore ?
Use ValueError instead of NameError.
final lintel
Well yeah…
thick storm
Then you didn’t define n
im nake it
final lintel
You need to actually set n to something if you’re gonna use it
lusty reef
If the exception is caught, n never gets defined
thick storm
You need to actually set n to something if you’re gonna use it
hoow
cold shale
Just except everything
lusty reef
Put the code inside the try
heady sage
Or you can just do exit() in the except clause
final lintel
Or…
Just do
while True:
N = input()
Try
N =int(N)
Break
thick storm
Or…
Just do
while True:
N = input()
Try
N =int(N)
Brea...
ok 1m
floral cove
hoow
while True:
try:
user_input = int(input(' > '))
break
except ValueError:
print('Input must be a valid number, try again')
now work
final lintel
👍
thick storm
```py
while True:
try:
user_input = int(input(' > '))
break
...
why use break ??
floral cove
why use break ??
break ends the while True loop
thick storm
what make break
heady sage
!d break
knotty estuaryBOT
floral cove
what make break
and if an exception is raised (if user didnt enter a valid number), break is not executed, it goes into except ValueError:, prints 'Input must be a valid number, try again', and loop starts over
thick storm
and if an exception is raised (if user didnt enter a valid number), `break` is n...
oh okkkkkkk
thick storm
and if an exception is raised (if user didnt enter a valid number), `break` is n...
ty for help
floral cove
no problem
floral cove
NameError: name 'n' is not defined
because variable that stores input is user_input
n doesnt exist in your program
and lower you still did for i in range(n):
thick storm
ty brooo
thick storm
@floral cove
floral cove
?
thick storm
im need some help ((:
thick storm
```py
while True:
try:
user_input = int(input(' > '))
break
...
how im can make it herer
There is one mistake in the book that repeats it
Not everything repeats itself
floral cove
def input_float(promt='', error_message=''):
while True:
try:
user_input = float(input(promt))
return user_input
except ValueError:
print(error_message)
# ... (your main part)
name = input(...)
grade = input_float(f"enter the mark '{name}': ", "Please enter a valid float number")
# ...
ok 1m
thick storm
```py
def input_float(promt='', error_message=''):
while True:
try:
...
put why you put promt im input
floral cove
?
def input_float(promt='', error_message=''):
while True:
try:
user_input = float(input(promt))
you give promt to this function
and that input() will print it out
input_float(f"enter the mark '{name}': ", ...
floral cove
show ur code
floral cove
why did u paste in the comment 💀
thick storm
💀
floral cove
i meant to change ur for loop
floral cove
how im can make it herer
this one
also u can write a function like that
>>> def input_type(promt='', error_message='', _type=int):
... while True:
... try:
... user_input = _type(input(promt))
... return user_input
... except ValueError:
... print(error_message)
...
>>> input_type('enter a float: ', 'input must be a float', float)
enter a float: 12
12.0
>>> input_type('enter an int: ', 'input must be int', int)
enter an int: 100
100
which u can use in both places where u need int and float
thick storm
```pycon
>>> def input_type(promt='', error_message='', _type=int):
... whil...
It's hard for a 15 year old to understand this
floral cove
u'll get there
floral cove
now just delete the comment and edit ur actual loop that u needed to change
floral cove
whu _type=int will make ??
well u see
u do int(input(...)) right
but int is sort of a function so u can store it in a variable
a = int
value = a('50')
print(type(value))
and we get
<class 'int'>
so we can create an argument _type that will store this function
>>> input_type('enter a float: ', 'input must be a float', float)
enter a float: 12
12.0
>>> input_type('enter an int: ', 'input must be int', int)
enter an int: 100
100
look here
the third argument in first call is float
and we get back 12.0
which is a float
and in second call we use int
and we get back 100
which is an integer
thick storm
well u see
bake
thick storm
u do `int(input(...))` right
yup
thick storm
but `int` is sort of a function so u can store it in a variable
oh okkkkkkk
thick storm
```py
a = int
value = a('50')
print(type(value))
```
and we get
```
<class 'int'...
I know this
floral cove
so yeah
_type=int means that the default value of _type is int
if we dont use it it will be int
floral cove
float: 12 and int: 100
those are just examples
floral cove
`_type=int` means that the default value of `_type` is `int`
>>> input_type('enter an int: ', 'input must be int')
enter an int: 10
10
also as u can see i didnt specify int as the third argument
and i got back an integer
thick storm
oh okkk
floral cove
if u will change the function to input_type like i showed before
>>> def input_type(promt='', error_message='', _type=int):
... while True:
... try:
... user_input = _type(input(promt))
... return user_input
... except ValueError:
... print(error_message)
...
then in ur code
floral cove
how im can make it herer
for i in range(user_input):
name = #...(same as before)
grade = input_type(f"enter the mark '{name}': ", "Please enter a valid float number", float)
student_grades[name] = grade
and also u can change the previous loop to
user_input = input_type(' > ', 'Input must be a valid number, try again', int)
I don't understand what is written, can you explain?
floral cove
what exactly u dont understand
thick storm
what exactly u dont understand
It's hard for me😭
thick storm
```py
while True:
try:
user_input = int(input(' > '))
break
...
This code is the first thing that will be in it. If the code is correct, it will work. If it is incorrect, it will not work. We have recovered from the fracture in both. If the value is true, it will work if it is false. Will not work.
The break will work whether it is true or not
knotty estuaryBOT
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